en
Feedback
C Programming Language || Hands On Coding

C Programming Language || Hands On Coding

Open in Telegram

Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii

Show more

📈 Analytical overview of Telegram channel C Programming Language || Hands On Coding

Channel C Programming Language || Hands On Coding (@c_programming_language_coding) in the English language segment is an active participant. Currently, the community unites 12 787 subscribers, ranking 9 608 in the Technologies & Applications category and 31 053 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 12 787 subscribers.

According to the latest data from 02 September, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -213 over the last 30 days and by -6 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 8.62%. Within the first 24 hours after publication, content typically collects 2.42% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 102 views. Within the first day, a publication typically gains 310 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 3.
  • Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii

Thanks to the high frequency of updates (latest data received on 03 September, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

12 787
Subscribers
-624 hours
-447 days
-21330 days
Posts Archive
#include<stdio.h> void main() { int a[]={10,11,-1,56,67,5,4}; int *p,*q; p=&a[0]; q=&a[0]+3; printf("%d,%d,%d\n",(*p)++,(*p)++,*(++p)); printf("%d\n",*p); printf("%d\n",(*p)++); printf("%d\n",(*p)++); q--; printf("%d\n",(*(q+2))--); printf("%d\n",*(p+2)-2); printf("%d\n",*(p++-2)-1); }

#include<stdio.h> void main() { int a[7]={4,8,3,6,1,2,7}; int *p=&a[0],*q; printf("%d\n",*p); //4 printf("%d,%d,%d\n",(*p)++,*p++,*++p); //3,8,8 printf("%d\n",*p); //4 q=p+3; //q is pointing to a[5] printf("%d\n",*q-3); //-1 printf("%d\n",*--p+5); //13 printf("%d\n",*p+*q); //10 }

Is This Channel Helpful to you
Anonymous voting

//Performing increment and decrement on pointer #include<stdio.h> void main() { int a[5]={5,4,6,8,3}; int *p=&a[0]; printf("Value:%d\n",*p); // Value:5 p++; // now,p is pointing to a[1] printf("Value:%d\n",*p); // Value:4 ++p; // now p is pointing to a[2] printf("Value:%d\n",*p); // value:6 p--; // now p is pointing to a[1] printf("Value:%d\n",*p); // value:4 --p; // now p is pointing to a[0] printf("Value:%d\n",*p); // Value:5 }

// performing subraction on pointers. #include<stdio.h> void main() { int a[5]={6,4,2,5,8}; int *p=&a[0]; int *q=&a[4]; printf("p-q=%d\n",p-q); //p-q=-4 *q=15; // now a[4]=15 printf("q-p=%d\n",q-p); //q-p=4 *p=32; //now ,a[0]=32 q=q-3; //now q is pointing to a[1] printf("value:%d\n",*q); //value:4 p=p+3; //now p is pointing to a[3] printf("value:%d\n",*p); //value:5 printf("p-q=%d\n",p-q); //p-q=2 }

//performing addition on pointer. #include<stdio.h> void main() { int a[5]={5,3,9,7,2}; int *p=&a[0]; printf("Value : %d\n",*p); //Value :5 printf("Address of element:%u\n",p); //Adress of element:6422280 p=p+2; //The pointer will point to a[2] *p=4; //Now the value of a[2] is modified to 4 printf("Value :%d\n",*p); //Value:9 printf("Address of element:%u\n",p); //Adress of element:6422288 }

// // pointer is a variable which stores the adress of other variable. // // int *p :- p is a pointer variable which stores the adress of any other int type variable // // (&)adress of (*) indirection/dereferencing operator // #include<stdio.h> // void main() // {int a=5,b=6; // int *p,*q; //declaration of pointers p and q // p=&a; // pointer variable p,has the address of variable a // q=&b; // pointer variable q, has the adress of variable b // printf("Value of a:%d\n",*p); //*p will give the value of a i.e *(&a) value at adress of a // printf("Value of b:%d",*q); //*q will give the alue of b i.e *(&b) value at adress of b // } //performing addition on pointer. #include<stdio.h> void main() { int a[5]={5,3,9,7,2}; int *p=&a[0]; printf("Value : %d\n",*p); //Value :5 printf("Address of element:%u\n",p); //Adress of element:6422280 p=p+2; //The pointer will point to a[2] *p=4; //Now the value of a[2] is modified to 4 printf("Value :%d\n",*p); //Value:9 printf("Address of element:%u\n",p); //Adress of element:6422288 }

// pointer is a variable which stores the adress of other variable. // int *p :- p is a pointer variable which stores the adress of any other int type variable // (&)adress of (*) indirection/dereferencing operator #include<stdio.h> void main() {int a=5,b=6; int *p,*q; //declaration of pointers p and q p=&a; // pointer variable p,has the address of variable a q=&b; // pointer variable q, has the adress of variable b printf("Value of a:%d\n",*p); //*p will give the value of a i.e *(&a) value at adress of a printf("Value of b:%d",*q); //*q will give the alue of b i.e *(&b) value at adress of b }

// Program to reverse a sring using a loop. #include<stdio.h> #include<string.h> int main() { char str[50]; printf("Enter the string:"); gets(str); int i,l=strlen(str); for(i=0;i<l/2;i++) { char ch=str[i]; str[i]=str[l-1-i]; str[l-1-i]=ch; } printf("Reversed string:\n%s",str); return 0; }

// Program to reverse a sring using strrev function. #include<stdio.h> #include<string.h> int main() { char str[20]="coding"; strrev(str); printf("Reversed string:\n%s",str); return 0; }

// Program to concatenate two strings using a loop. #include<stdio.h> #include<string.h> int main() { int l1,l2,i; char s1[50]="C_"; char s2[50]="Programming"; l1=strlen(s1); l2=strlen(s2); for(i=0;i<=l2;i++) { s1[l1+i]=s2[i]; } printf("Concatenated string:\n%s",s1); return 0; }

// Program to concatenate two strings using strcat function. #include<stdio.h> #include<string.h> int main() { char s1[50]="C_"; char s2[50]="Programming"; strcat(s1,s2); printf("Concateated string:\n%s",s1); return 0; }

// Program to find length of a string using a loop. #include<stdio.h> int main() { int len=0,i; char string[100]; printf("Enter string:"); gets(string); for(i=0;string[i]!='\0';i++) { len++; } printf("Length of the string is: %d",len); return 0; }

// Program to find length of a string using strlen function #include<stdio.h> #include<string.h> int main() { int len=0; char string[100]; printf("Enter string:"); gets(string); len=strlen(string); printf("Length of the string is: %d",len); return 0; }

//Program to read a string and print it. #include<stdio.h> int main() {char name[20]; printf("Enter name:"); gets(name); puts(name); return 0; }

//Program for matrix multiplication. #include<stdio.h> int main() {int r1,c1,r2,c2; printf("Enter number of rows in first matrix:"); scanf("%d",&r1); printf("Enter number of coulumns in first matrix:"); scanf("%d",&c1); printf("Enter number of rows in second matrix:"); scanf("%d",&r2); printf("Enter number of coulumns in second matrix:"); scanf("%d",&c2); if(c1==r2) //two matrices can be multiplied only if coloumns of first matrix is equal to rows of second matrix { printf("The matrices can be multiplied.\n"); int a[r1][c1],b[r2][c2],c[r1][c2],i,j,k,sum=0; printf("Enter the elements of first matrix:\n"); for(i=0;i<r1;i++) { for(j=0;j<c1;j++) { printf("Enter the Element at a[%d][%d]:",i,j); scanf("%d",&a[i][j]); } } printf("Enter the Elements of second matrix:\n"); for(i=0;i<r2;i++) { for(j=0;j<c2;j++) { printf("Enter the Element at b[%d][%d]:",i,j); scanf("%d",&b[i][j]); } } for(i=0;i<r1;i++) { for(j=0;j<c2;j++) { sum=0; for(k=0;k<c1;k++) { sum=sum+(a[i][k]*b[k][j]); } c[i][j]=sum; } } printf("Matrix 1:\n"); for(i=0;i<r1;i++) { for(j=0;j<c1;j++) { printf("%d\t",a[i][j]); } printf("\n"); } printf("Matrix 2:\n"); for(i=0;i<r2;i++) { for(j=0;j<c2;j++) { printf("%d\t",b[i][j]); } printf("\n"); } printf("Matrix 1 * Matrix 2:\n"); for(i=0;i<r1;i++) { for(j=0;j<c2;j++) { printf("%d\t",c[i][j]); } printf("\n"); } } else{ printf("Matrix cannot be multipled Enter the row and column number correctly."); } return 0; }

//Program to do sum of 2 matrices and store the sum in third matrix, read the elements of matrix. #include<stdio.h> int main() {int a[2][3],b[2][3],c[2][3],i,j; printf("Enter elemnts of first matrix:\n"); for(i=0;i<2;i++) { for(j=0;j<3;j++) { printf("Enter the element at a[%d][%d]:",i,j); scanf("%d",&a[i][j]); } } printf("Enter elemnts of second matrix:\n"); for(i=0;i<2;i++) { for(j=0;j<3;j++) { printf("Enter the element at b[%d][%d]:",i,j); scanf("%d",&b[i][j]); } } for(i=0;i<2;i++) { for(j=0;j<3;j++) { c[i][j]=a[i][j]+b[i][j]; } } printf("The sum of two matices=\n"); for(i=0;i<2;i++) { for(j=0;j<3;j++) { printf("%d\t",c[i][j]); } printf("\n"); } return 0; }

//Program to perform sum of individual row and column of 3X3 matrix, read the elements of matrix. #include<stdio.h> int main() {int m[3][3],i,j,sr,sc; for(i=0;i<3;i++) { for(j=0;j<3;j++) { printf("Enter the element at m[%d][%d]:",i,j); scanf("%d",&m[i][j]); } } printf("The matrix is:\n"); for(i=0;i<3;i++) { for(j=0;j<3;j++) { printf("%d\t",m[i][j]); } printf("\n"); } for(i=0;i<3;i++) { sr=0,sc=0; for(j=0;j<3;j++) { sr=sr+m[i][j]; sc=sc+m[j][i]; } printf("Th sum of row %d:%d\n",i,sr); printf("The sum of column %d:%d\n",i,sc); } }

//Program to read 2X3 matrix and print transpose of it (3X2). #include <stdio.h> int main() { int m[2][3],i,j; for(i=0;i<2;i++) { for(j=0;j<3;j++) { printf("Enter the element at m[%d][%d]:",i,j); scanf("%d",&m[i][j]); } } printf("The matrix is:\n"); for(i=0;i<2;i++) { for(j=0;j<3;j++) { printf("%d\t",m[i][j]); } printf("\n"); } printf("The transposed matrix is:\n"); for(i=0;i<3;i++) { for(j=0;j<2;j++) { printf("%d\t",m[j][i]); } printf("\n"); } return 0; }