Available now! Telegram Research 2025 β the year's key insights 
C Programming Codes
C Programming Codes || Quizzes || DSA Learn along with the community Any queries admin - @Pradeep_saii
Show moreπ Analytical overview of Telegram channel C Programming Codes
Channel C Programming Codes (@c_programming_codes) in the English language segment is an active participant. Currently, the community unites 13 420 subscribers, ranking 9 537 in the Technologies & Applications category and 32 062 in the India region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 13 420 subscribers.
According to the latest data from 12 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -240 over the last 30 days and by -9 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 9.78%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
- Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.
π Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
βC Programming Codes || Quizzes || DSA
Learn along with the community
Any queries
admin - @Pradeep_saiiβ
Thanks to the high frequency of updates (latest data received on 13 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
#include <stdio.h>
int main() {
int age = 30;
float price = 19.99;
char initial = 'J';
printf("Age: %d\n", age);
printf("Price: %.2f\n", price);
printf("Initial: %c\n", initial);
return 0;
}#include <stdio.h>
int main() {
int days, weeks, remaining_days;
printf("Enter the number of days: ");
scanf("%d", &days);
weeks = days / 7;
remaining_days = days % 7;
printf("%d days is %d weeks and %d days\n", days, weeks, remaining_days);
return 0;
}#include <stdio.h>
int main() {
float radius, area, circumference;
const float PI = 3.14159;
printf("Enter the radius of the circle: ");
scanf("%f", &radius);
area = PI * radius * radius;
circumference = 2 * PI * radius;
printf("Area = %.2f\n", area);
printf("Circumference = %.2f\n", circumference);
return 0;
}#include <stdio.h>
int main() {
int length, width, area, perimeter;
printf("Enter the length: ");
scanf("%d", &length);
printf("Enter the width: ");
scanf("%d", &width);
area = length * width;
perimeter = 2 * (length + width);
printf("Area = %d\n", area);
printf("Perimeter = %d\n", perimeter);
return 0;
}#include <stdio.h>
int main() {
float celsius, fahrenheit;
printf("Enter temperature in Celsius: ");
scanf("%f", &celsius);
fahrenheit = (celsius * 9/5) + 32;
printf("Fahrenheit: %.2f\n", fahrenheit);
return 0;
}#include <stdio.h>
int main() {
char character;
printf("Enter a character: ");
scanf(" %c", &character);
printf("ASCII value of %c is: %d", character, character);
return 0;
}#include <stdio.h>
int main() {
int x = 5;
int y = 10;
printf("x: %d, y: %d\n", x, y);
x++;
y--;
printf("x: %d, y: %d\n", x, y);
return 0;
}#include <stdio.h>
int main() {
int dividend, divisor, quotient, remainder;
printf("Enter dividend: ");
scanf("%d", ÷nd);
printf("Enter divisor: ");
scanf("%d", &divisor);
quotient = dividend / divisor;
remainder = dividend % divisor;
printf("Quotient = %d\n", quotient);
printf("Remainder = %d\n", remainder);
return 0;
}#include <stdio.h>
int main() {
int num1, num2, sum, diff, prod, div;
printf("Enter two integers: ");
scanf("%d %d", &num1, &num2);
sum = num1 + num2;
diff = num1 - num2;
prod = num1 * num2;
div = num1 / num2;
printf("Sum: %d\n", sum);
printf("Difference: %d\n", diff);
printf("Product: %d\n", prod);
printf("Division: %d\n", div);
return 0;
}