Don't get caught by a cheater! Telemetrio finds and tags such channels 👉 If you want to see the tag, subscribe

AI Coding & CSE Fundamentals

Open in Telegram

🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.

India31 257Technologies & Applications10 235...

📈 Analytical overview of Telegram channel AI Coding & CSE Fundamentals

Channel AI Coding & CSE Fundamentals (@aicoding_csefundamentals) in the English language segment is an active participant. Currently, the community unites 12 310 subscribers, ranking 10 235 in the Technologies & Applications category and 31 257 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 12 310 subscribers.

According to the latest data from 13 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -236 over the last 30 days and by -9 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 10.85%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
Post reach: On average, each post receives 1 337 views. Within the first day, a publication typically gains 0 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 11.
Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.”

Thanks to the high frequency of updates (latest data received on 14 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

12 310

Subscribers

-924 hours

-837 days

-23630 days

1 337

Post views

No data24 hours

No data48 hours

10.85%

Engagement rate

No data

Posts per day

Ads index

Posts Archive

12 310

https://t.me/dsa_using_c

12 310

https://t.me/student_accessories_deals

12 310

https://t.me/student_accessories_deals

12 310

https://telegram.me/student_accessories_deals join to get best deals ☝️

12 310

https://t.me/student_accessories_deals join our deals channel ☝️

12 310

https://t.me/C_programming_language_group join our discussion group ☝️

12 310

https://t.me/python_programming_language_code

12 310

// program to store data dynamically using malloc and extent the existing data using realloc and print it #include<stdio.h> #include<stdlib.h> int main() { int *p,n,i,k; printf("Enter number of elements to be stored:"); scanf("%d",&n); p=(int*)calloc(n,sizeof(int)); if(p==NULL){ printf("Cannot allocate memory"); exit(1); } printf("Enter %d elements:",n); for(i=0;i<n;i++) { scanf("%d",p+i); } printf("The entered elements are:"); for(i=0;i<n;i++){ printf("%4d",*(p+i)); } printf("\nEnter number of elements you want to extend:"); scanf("%d",&k); p=(int*)realloc(p,k*sizeof(int)); if(p==NULL){ printf("Cannot allocate memory"); exit(1); } printf("Enter the next %d elements:",k); for(i=0;i<k;i++) { scanf("%d",(p+n+i)); } printf("The entered elements after extending are:"); for(i=0;i<n+k;i++){ printf("%4d",*(p+i)); } free(p); return 0; } //@c_programming_language_programs

12 310

// program to store data dynamically using calloc and print it #include<stdio.h> #include<stdlib.h> int main() { int *p,n,i; printf("Enter number of elements to be stored:"); scanf("%d",&n); p=(int*)calloc(n,sizeof(int)); if(p==NULL){ printf("Cannot allocate memory"); exit(1); } printf("Enter %d elements:",n); for(i=0;i<n;i++) { scanf("%d",p+i); } printf("The entered elements are:"); for(i=0;i<n;i++){ printf("%4d",*(p+i)); } free(p); return 0; } //@c_programming_language_programs

12 310

// program to store data dynamically using malloc and print it #include<stdio.h> #include<stdlib.h> int main() { int *p,n,i; printf("Enter number of elements to be stored:"); scanf("%d",&n); p=(int*)malloc(n*sizeof(int)); printf("Enter %d elements:",n); for(i=0;i<n;i++) { scanf("%d",p+i); } printf("The entered elements are:"); for(i=0;i<n;i++){ printf("%4d",*(p+i)); } free(p); return 0; } //@c_programming_language_programs

12 310

// program to read a string from the user and convert characters in lower case to upper // and the characters which are in uppercase to lower uaing pointers. #include<stdio.h> void toggleChar(char*); int main() { char str[50]; printf("Enter the string:"); scanf("%[^\n]",str); toggleChar(str); printf("Converted string is: %s",str); return 0; } void toggleChar(char *ptr_ch){ int i; for(i=0;*(ptr_ch+i)!='\0';i++){ if(*(ptr_ch+i)>='A' && *(ptr_ch+i)<='Z'){ *(ptr_ch+i)=*(ptr_ch+i)+32; } else if(*(ptr_ch+i)>='a' && *(ptr_ch+i)<='z'){ *(ptr_ch+i)=*(ptr_ch+i)-32; } } }

12 310

// Program to print array elements using pointers #include<stdio.h> void printArray(int*,int); int main() { int a[]={10,20,30,40,50}; printArray(a,sizeof(a)/sizeof(a[0])); return 0; } void printArray(int *ptr_arr,int size){ int i; for(i=0;i<size;i++) { printf("%4d",*(ptr_arr+i)); } } //@c_programming_language_programs

12 310

// Program to print sum of three numbers and also find maximum of three void sumAndMax(int ,int ,int ,int*,int*); #include<stdio.h> int main() { int a=50,b=90,c=20,sum,max; sumAndMax(a,b,c,&sum,&max); printf("Sum= %d , Maximum number= %d",sum,max); return 0; } void sumAndMax(int x,int y,int z,int *p,int *q){ *p=x+y+z; *q=(x>y && x>z)?x:(y>z?y:z); // greatest of three numbers using ternary operator } //@c_programming_language_programs

12 310

// program to swap two numbers using pointers #include<stdio.h> void swap(int *,int *); int main() { int a=5,b=10; printf("Values of a and b before swapping:\n"); printf("a=%d , b=%d\n",a,b); swap(&a,&b); printf("Values of a and b after swapping:\n"); printf("a=%d , b=%d\n",a,b); return 0; } void swap(int *a,int *b){ int temp; temp=*a; *a=*b; *b=temp; } //@c_programming_language_programs

12 310

// program for knowing size of pointer,snd also size of the data type that it is pointing to #include<stdio.h> int main() { int *p; float *q; double *r; char *ch; //size of the pointers printf("Size of pointer p: %lu\n",sizeof(p)); printf("Size of pointer q: %lu\n",sizeof(q)); printf("Size of pointer r: %lu\n",sizeof(r)); printf("Size of pointer ch: %lu\n",sizeof(ch)); //sizes of data types that pointers are pointing printf("Size of int: %lu\n",sizeof(*p)); printf("Size of float: %lu\n",sizeof(*q)); printf("Size of double: %lu\n",sizeof(*r)); printf("Size of char: %lu\n",sizeof(*ch)); return 0; } //@c_programming_language_programs

12 310

// Accessing value of a variable using Pointer to pointer #include<stdio.h> int main() { int a=10; int *p,**q; p=&a; q=&p; printf("Value of a :%d",**q); return 0; } //@c_programming_language_programs

12 310

// program to increment the value of a variable using pointer #include<stdio.h> int main() { int x=4; int *p; p=&x; printf("Value of X before incrementing:%d\n",x); *p=*p+1; printf("Value of X after incrementing:%d",x); return 0; } //@c_programming_language_programs

12 310

// Program to print value of a variable using pointer #include<stdio.h> int main() { int x=5; int *p; p=&x; printf("Value of x :%d",*p); return 0; } //@c_programming_language_programs

12 310

🔗https://t.me/student_accessories_deals Join our Students Deals channel,you can find best laptop deals there

12 310