C Programming Language || Hands On Coding
Hands-on C programming language challenges for beginners. Learn building logic by solving programs. Owner: @Pradeep_saii
Show moreπ Analytical overview of Telegram channel C Programming Language || Hands On Coding
Channel C Programming Language || Hands On Coding (@c_programming_language_coding) in the English language segment is an active participant. Currently, the community unites 12 824 subscribers, ranking 9 562 in the Technologies & Applications category and 31 207 in the India region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 12 824 subscribers.
According to the latest data from 26 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -210 over the last 30 days and by -2 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 12.56%. Within the first 24 hours after publication, content typically collects 2.42% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 612 views. Within the first day, a publication typically gains 310 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 4.
- Thematic interests: Content is focused on key topics such as input, string, scanf("%d, array, element.
π Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
βHands-on C programming language challenges for beginners. Learn building logic by solving programs.
Owner: @Pradeep_saiiβ
Thanks to the high frequency of updates (latest data received on 27 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
#include <stdio.h>
int findMaxRecursive(int arr[], int size) {
if (size == 1) {
return arr[0];
} else {
int maxRest = findMaxRecursive(arr, size - 1);
if (arr[size - 1] > maxRest) {
return arr[size - 1];
} else {
return maxRest;
}
}
}
int main() {
int size, i;
printf("Enter the size of the array: ");
scanf("%d", &size);
int arr[size];
printf("Enter the elements of the array:n");
for (i = 0; i < size; i++) {
scanf("%d", &arr[i]);
}
int max = findMaxRecursive(arr, size);
printf("Maximum element in the array is: %dn", max);
return 0;
}
π€ Output:
Input: 5 Input: 10 Input: 5 Input: 20 Input: 15 Input: 25 Output: Maximum element in the array is: 25 Input: 3 Input: -5 Input: 0 Input: 5 Output: Maximum element in the array is: 5 Input: 1 Input: 100 Output: Maximum element in the array is: 100
#include <stdio.h>
void towerOfHanoi(int n, char from_rod, char to_rod, char aux_rod) {
if (n == 1) {
printf("Move disk 1 from rod %c to rod %cn", from_rod, to_rod);
return;
}
towerOfHanoi(n - 1, from_rod, aux_rod, to_rod);
printf("Move disk %d from rod %c to rod %cn", n, from_rod, to_rod);
towerOfHanoi(n - 1, aux_rod, to_rod, from_rod);
}
int main() {
int num_disks;
printf("Enter the number of disks: ");
scanf("%d", &num_disks);
towerOfHanoi(num_disks, 'A', 'C', 'B'); // A, B and C are names of rods
return 0;
}
π€ Output:
Input: 3 Output: Enter the number of disks: Move disk 1 from rod A to rod C Move disk 2 from rod A to rod B Move disk 1 from rod C to rod B Move disk 3 from rod A to rod C Move disk 1 from rod B to rod A Move disk 2 from rod B to rod C Move disk 1 from rod A to rod C
#include <stdio.h>
int countDigits(int n) {
if (n == 0) {
return 0;
} else {
return 1 + countDigits(n / 10);
}
}
int main() {
int num;
printf("Enter an integer: ");
scanf("%d", &num);
int digitCount = countDigits(num);
printf("Number of digits: %dn", digitCount);
return 0;
}
π€ Output:
Input: 12345 Output: Enter an integer: Number of digits: 5 Input: 0 Output: Enter an integer: Number of digits: 0 Input: 99 Output: Enter an integer: Number of digits: 2 Input: -123 Output: Enter an integer: Number of digits: 3
#include <stdio.h>
#include <stdbool.h>
bool isPrimeRecursive(int n, int i) {
if (n <= 1)
return false;
if (i == 1)
return true;
if (n % i == 0)
return false;
return isPrimeRecursive(n, i - 1);
}
int main() {
int num;
printf("Enter a positive integer: ");
scanf("%d", &num);
if (isPrimeRecursive(num, num / 2))
printf("%d is a prime number.n", num);
else
printf("%d is not a prime number.n", num);
return 0;
}
π€ Output:
Input: 7 Output: 7 is a prime number. Input: 12 Output: 12 is not a prime number. Input: 1 Output: 1 is not a prime number.
#include <stdio.h>
int product(int a, int b) {
if (b == 0) {
return 0;
} else if (b > 0) {
return a + product(a, b - 1);
} else {
return -product(a, -b);
}
}
int main() {
int num1, num2, result;
printf("Enter two integers: ");
scanf("%d %d", &num1, &num2);
result = product(num1, num2);
printf("Product of %d and %d is: %dn", num1, num2, result);
return 0;
}
π€ Output:
Input: 5 3 Output: Product of 5 and 3 is: 15 Input: 4 -2 Output: Product of 4 and -2 is: -8 Input: -6 2 Output: Product of -6 and 2 is: -12 Input: -3 -4 Output: Product of -3 and -4 is: 12 Input: 7 0 Output: Product of 7 and 0 is: 0
#include <stdio.h>
int sum(int n) {
if (n == 0) {
return 0;
} else {
return n + sum(n - 1);
}
}
int main() {
int num;
printf("Enter a positive integer: ");
scanf("%d", &num);
if (num < 0) {
printf("Please enter a positive integer.n");
} else {
int result = sum(num);
printf("Sum = %dn", result);
}
return 0;
}
π€ Output:
Input: 10 Output: Enter a positive integer: Sum = 55 Input: 5 Output: Enter a positive integer: Sum = 15 Input: -3 Output: Enter a positive integer: Please enter a positive integer.
#include <stdio.h>
void printNumbers(int n) {
if (n > 0) {
printf("%d ", n);
printNumbers(n - 1);
}
}
int main() {
int n;
printf("Enter a positive integer: ");
scanf("%d", &n);
printNumbers(n);
printf("n");
return 0;
}
π€ Output:
Input: 5 Output: 5 4 3 2 1
#include <stdio.h>
void printNumbers(int n, int current) {
if (current <= n) {
printf("%d ", current);
printNumbers(n, current + 1);
}
}
int main() {
int n;
printf("Enter a positive integer N: ");
scanf("%d", &n);
if (n <= 0) {
printf("Please enter a positive integer.n");
} else {
printNumbers(n, 1);
printf("n");
}
return 0;
}
π€ Output:
Input: 5 Output: Enter a positive integer N: 1 2 3 4 5 Input: 1 Output: Enter a positive integer N: 1 Input: 0 Output: Enter a positive integer N: Please enter a positive integer. Input: -3 Output: Enter a positive integer N: Please enter a positive integer.
#include <stdio.h>
void decimalToBinary(int n) {
if (n > 0) {
decimalToBinary(n / 2);
printf("%d", n % 2);
}
}
int main() {
int decimal;
printf("Enter a decimal number: ");
scanf("%d", &decimal);
printf("Binary equivalent: ");
if (decimal == 0) {
printf("0");
} else {
decimalToBinary(decimal);
}
printf("n");
return 0;
}
π€ Output:
Input: 10 Output: Enter a decimal number: Binary equivalent: 1010 Input: 0 Output: Enter a decimal number: Binary equivalent: 0 Input: 25 Output: Enter a decimal number: Binary equivalent: 11001 Input: 127 Output: Enter a decimal number: Binary equivalent: 1111111 Input: 1 Output: Enter a decimal number: Binary equivalent: 1
#include <stdio.h>
int gcd(int a, int b) {
if (b == 0)
return a;
return gcd(b, a % b);
}
int lcm(int a, int b) {
return (a * b) / gcd(a, b);
}
int main() {
int num1, num2;
printf("Enter two positive integers: ");
scanf("%d %d", &num1, &num2);
printf("LCM of %d and %d is %dn", num1, num2, lcm(num1, num2));
return 0;
}
π€ Output:
Input: 12 18 Output: Enter two positive integers: LCM of 12 and 18 is 36 Input: 25 15 Output: Enter two positive integers: LCM of 25 and 15 is 75 Input: 7 9 Output: Enter two positive integers: LCM of 7 and 9 is 63
#include <stdio.h>
int gcd(int a, int b) {
if (b == 0) {
return a;
} else {
return gcd(b, a % b);
}
}
int main() {
int num1, num2;
printf("Enter two positive integers: ");
scanf("%d %d", &num1, &num2);
printf("GCD of %d and %d is %dn", num1, num2, gcd(num1, num2));
return 0;
}
π€ Output:
Input: 36 60 Output: Enter two positive integers: GCD of 36 and 60 is 12
#include <stdio.h>
int power(int base, int exponent) {
if (exponent == 0) {
return 1;
} else if (exponent > 0) {
return base * power(base, exponent - 1);
} else {
return 1 / power(base, -exponent);
}
}
int main() {
int base, exponent, result;
printf("Enter the base number: ");
scanf("%d", &base);
printf("Enter the exponent: ");
scanf("%d", &exponent);
result = power(base, exponent);
printf("%d^%d = %dn", base, exponent, result);
return 0;
}
π€ Output:
Input: 2 Input: 3 Output: 2^3 = 8 Input: 5 Input: 0 Output: 5^0 = 1 Input: 2 Input: -2 Output: 2^-2 = 0
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int isPalindrome(char str[], int start, int end) {
if (start >= end) {
return 1;
}
if (str[start] != str[end]) {
return 0;
}
return isPalindrome(str, start + 1, end - 1);
}
int main() {
char str[100];
printf("Enter a string: ");
scanf("%s", str);
int length = strlen(str);
if (isPalindrome(str, 0, length - 1)) {
printf("%s is a palindromen", str);
} else {
printf("%s is not a palindromen", str);
}
return 0;
}
π€ Output:
Input: madam Output: madam is a palindrome Input: racecar Output: racecar is a palindrome Input: hello Output: hello is not a palindrome Input: A man, a plan, a canal: Panama Output: A is not a palindrome
#include <stdio.h>
#include <string.h>
void reverseString(char *str, int start, int end) {
if (start >= end) {
return;
}
char temp = str[start];
str[start] = str[end];
str[end] = temp;
reverseString(str, start + 1, end - 1);
}
int main() {
char str[100];
printf("Enter a string: ");
scanf("%s", str);
int length = strlen(str);
reverseString(str, 0, length - 1);
printf("Reversed string: %sn", str);
return 0;
}
π€ Output:
Input: hello Output: Reversed string: olleh Input: world Output: Reversed string: dlrow Input: abcdef Output: Reversed string: fedcba Input: A Output: Reversed string: A Input: racecar Output: Reversed string: racecar
#include <stdio.h>
int sumOfDigits(int n) {
if (n == 0) {
return 0;
}
return (n % 10) + sumOfDigits(n / 10);
}
int main() {
int num;
printf("Enter a positive integer: ");
scanf("%d", &num);
if (num < 0) {
printf("Please enter a positive integer.n");
return 1;
}
printf("Sum of digits of %d is %dn", num, sumOfDigits(num));
return 0;
}
π€ Output:
Input: 12345 Output: Enter a positive integer: Sum of digits of 12345 is 15 Input: 9876 Output: Enter a positive integer: Sum of digits of 9876 is 30 Input: 0 Output: Enter a positive integer: Sum of digits of 0 is 0 Input: -123 Output: Enter a positive integer: Please enter a positive integer.
#include <stdio.h>
int fibonacci(int n) {
if (n <= 1) {
return n;
}
return fibonacci(n - 1) + fibonacci(n - 2); // Recursive call
}
int main() {
int num, i;
printf("Enter the number of terms: ");
scanf("%d", &num);
printf("Fibonacci Series: ");
for (i = 0; i < num; i++) {
printf("%d ", fibonacci(i));
}
printf("n");
return 0;
}
π€ Output:
Input: 10 Output: Enter the number of terms: Fibonacci Series: 0 1 1 2 3 5 8 13 21 34
#include <stdio.h>
int factorial(int n) {
if (n == 0) {
return 1;
} else {
return n * factorial(n - 1); // Recursive call
}
}
int main() {
int num;
printf("Enter a non-negative integer: ");
scanf("%d", &num);
if (num < 0) {
printf("Factorial is not defined for negative numbers.n");
} else {
printf("Factorial of %d = %dn", num, factorial(num));
}
return 0;
}
π€ Output:
Input: 5 Output: Enter a non-negative integer: Factorial of 5 = 120 Input: 0 Output: Enter a non-negative integer: Factorial of 0 = 1 Input: -2 Output: Enter a non-negative integer: Factorial is not defined for negative numbers.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main() {
char inputFile[100];
char outputFilePrefix[100];
long long chunkSize;
printf("Enter the input file name: ");
scanf("%s", inputFile);
printf("Enter the output file prefix: ");
scanf("%s", outputFilePrefix);
printf("Enter the chunk size in bytes: ");
scanf("%lld", &chunkSize);
FILE *fp = fopen(inputFile, "rb");
if (fp == NULL) {
printf("Error opening input file.n");
return 1;
}
int fileCount = 1;
long long bytesRead = 0;
unsigned char *buffer = (unsigned char *)malloc(chunkSize);
if (buffer == NULL) {
printf("Memory allocation error.n");
fclose(fp);
return 1;
}
while (1) {
size_t bytes = fread(buffer, 1, chunkSize, fp);
if (bytes == 0) {
break; // End of file
}
char outputFileName[200];
sprintf(outputFileName, "%s_%03d.part", outputFilePrefix, fileCount);
FILE *outFile = fopen(outputFileName, "wb");
if (outFile == NULL) {
printf("Error creating output file.n");
fclose(fp);
free(buffer);
return 1;
}
fwrite(buffer, 1, bytes, outFile);
fclose(outFile);
bytesRead += bytes;
fileCount++;
}
fclose(fp);
free(buffer);
printf("File split successfully.n");
return 0;
}
π€ Output:
Input: input.txt Input: output Input: 1000 Output: Enter the input file name: Enter the output file prefix: Enter the chunk size in bytes: Error opening input file.
