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allcoding1

allcoding1

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📈 Analytical overview of Telegram channel allcoding1

Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 21 499 subscribers, ranking 9 167 in the Education category and 19 105 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 21 499 subscribers.

According to the latest data from 04 September, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -351 over the last 30 days and by -4 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 7.55%. Within the first 24 hours after publication, content typically collects 1.25% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 625 views. Within the first day, a publication typically gains 270 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
  • Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 05 September, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

21 499
Subscribers
-424 hours
-827 days
-35130 days
Posts Archive
def checkSpellingAndSpace(sentence, dictionary): words = sentence.split() corrected_words = [] for word in words: if word.low
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def checkSpellingAndSpace(sentence, dictionary): words = sentence.split() corrected_words = [] for word in words: if word.lower() in dictionary: corrected_words.append(word.lower()) elif len(word) == len(dictionary[0]): for dict_word in dictionary: differences = sum([1 for c1, c2 in zip(word.lower(), dict_word) if c1 != c2]) if differences == 1: corrected_words.append(dict_word.lower()) break else: corrected_words.append(word) corrected_sentence = ' '.join(corrected_words) corrected_sentence = ' '.join(corrected_sentence.split()) print(corrected_sentence) dictionary = ['environment', 'always', 'protect', 'irreplaceable', 'different', 'abs'] sentence = 'We should protect our envaronment alwoys' checkSpellingAndSpace(sentence, dictionary) Python IBM EXAM 6PM ANS Telegram:- @allcoding1_official Telegram:- @IBM_exam_Anss

Python IBM EXAM 6PM ANS Telegram:- @allcoding1_official Telegram:- @IBM_exam_Anss
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Python IBM EXAM 6PM ANS Telegram:- @allcoding1_official Telegram:- @IBM_exam_Anss

IBM EXAM 6PM ANS Telegram:- @allcoding1 Telegram:- @IBM_exam_Anss

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PY IDP Assessment Telegram:- @allcoding1
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PY IDP Assessment Telegram:- @allcoding1

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🎯JPMorgan Hiring SQL Developer Qualifications: Bachelor's/ Master's Degree Salary: Upto 13 LPA (Expected) Batch: 2018/ 19/ 20/ 21/ 22/ 23 Experience: Freshers & Experienced Location: Bengaluru, India Apply Now:- http://www.allcoding1.com Telegram:- @allcoding1