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allcoding1

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📈 Analytical overview of Telegram channel allcoding1

Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 20 707 subscribers, ranking 9 717 in the Education category and 19 395 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 20 707 subscribers.

According to the latest data from 01 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -420 over the last 30 days and by -12 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 2.97%. Within the first 24 hours after publication, content typically collects 1.03% reactions from the total number of subscribers.
Post reach: On average, each post receives 615 views. Within the first day, a publication typically gains 214 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 02 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

20 707

Subscribers

-1224 hours

-1007 days

-42030 days

615

Post views

~ 21424 hours

~ 32148 hours

2.97%

Engagement rate

No data

Posts per day

Ads index

beta

Posts Archive

20 708

C++ Telegram:- @allcoding1

20 708

sticker.webp0.05 KB

20 708

magic Number Code python 3 All test cases passed Telegram:- @allcoding1

20 708

XOR elements C++ language Telegram:- @allcoding1

20 708

XOR code do you want

20 708

C++ Question:- You are given Queries.each query consists of 3 integer X[i],Y[i] and N[i] where i donates the ith query The answer to ith query X[i],Y[i] and N[i] is denoted By (X[i],Y[i])^((X[i]+1),Y[i])^....^((X[i],N[i]*Y[i]) Find the sum of all answers modulo 10^9+7 Telegram:- @allcoding1

20 708

You are given Queries.each query consists of 3 integer X[i],Y[i] and N[i] where i donates the ith query The answer to ith query X[i],Y[i] and N[i] is denoted By (X[i],Y[i])^((X[i]+1),Y[i])^....^((X[i],N[i]*Y[i]) Find the sum of all answers modulo 10^9+7

20 708

#include <bits/stdc++.h> using namespace std; int count(string s) { int N, i, cnt = 0, ans = 0; N = s.length(); for (i = 0; i < N; i++) { if (s[i] == 'R') cnt++; if (s[i] == 'L') ans += cnt; } return ans; } int main() { string s = "RRLL"; cout << count(s) << endl; return 0; } C++ Telegram - @allcoding1

20 708

def getLargestString(s, k): frequency_array = [0] * 26 for i in range(len(s)): frequency_array[ord(s[i]) - ord('a')] += 1 ans = "" i = 25 while i >= 0: if (frequency_array[i] > k): temp = k st = chr( i + ord('a')) while (temp > 0): ans += st temp -= 1 frequency_array[i] -= k j = i - 1 while (frequency_array[j] <= 0 and j >= 0): j -= 1 if (frequency_array[j] > 0 and j >= 0): str1 = chr(j + ord( 'a')) ans += str1 frequency_array[j] -= 1 else: break elif (frequency_array[i] > 0): temp = frequency_array[i] frequency_array[i] -= temp st = chr(i + ord('a')) while (temp > 0): ans += st temp -= 1 else: i -= 1 return ans if name == "main": S = input() k = 3 print (getLargestString(S, k)) Python Bob code Telegram:- @allcoding1

20 708

Python Find Minimum Distance Between two numbers in Array code Telegram:- @allcoding1

20 708

if (n > k && n > a) { printf("N is the Biggest number is %d", n); return n; } if (k > n && k > a) { printf("k is the Biggest number is %d", k); return k; } if (a > n && a > k) { printf("a is the Biggest number is %d", a); return a; } Telegram:- @allcoding1

20 708

from itertools import permutations def count(arr): z=[] perm = permutations(arr) for i in list(perm): z.append(list(i)) q=[] for i in range(len(arr)-1): x,y=arr[i],arr[i+1] for j in range(len(z)): if z[j].index(x)!=len(z[j])-1: if z[j][z[j].index(x)+1]==y: q.append(z[j]) for i in range(len(q)): if q[i] in z: z.remove(q[i]) return len(z) a= int(input()) b=list(map(int,input().strip().split())) print(count(b)) Python Telegram - @allcoding1

20 708

Java language Telegram:- @allcoding1

20 708

Java language Telegram:- @allcoding1

20 708

Python 3 Telegram:- @allcoding1

20 708

Infosys exam Answer's (22/10/22) https://www.joboffersadda.com/2022/01/infosys-exam-answer.html?m=1 https://www.joboffersadda.com/2022/01/infosys-exam-answer.html?m=1 https://www.joboffersadda.com/2022/01/infosys-exam-answer.html?m=1 Telegram:- @Infosys_Ans