allcoding1

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📈 Analytical overview of Telegram channel allcoding1

Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 22 598 subscribers, ranking 8 826 in the Education category and 19 528 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 22 598 subscribers.

According to the latest data from 11 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -436 over the last 30 days and by -18 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 5.84%. Within the first 24 hours after publication, content typically collects 1.41% reactions from the total number of subscribers.
Post reach: On average, each post receives 1 319 views. Within the first day, a publication typically gains 318 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 12 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

22 598

Subscribers

-1824 hours

-1007 days

-43630 days

1 319

Post views

~ 31824 hours

~ 42348 hours

5.84%

Engagement rate

No data

Posts per day

Ads index

beta

Posts Archive

22 595

DVI

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Wipro

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5.B 6.D 7.C

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n = int(input()) s = input() consonants = 0 for i in range(n-1,-1,-1): if s[i] not in 'aeiouAEIOU': consonants += 1 if consonants == 3: print(s[i]) break

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#include<stdio.h> int main() { int n; scanf("%d", &n); char str[n + 1]; scanf("%s", str); int count = 0; char thirdLastConsonant; for(int i = n - 1; i >= 0; i--) { if (str[i] != 'a' && str[i] != 'e' && str[i] != 'i' && str[i] != 'o' && str[i] != 'u' && str[i] != 'A' && str[i] != 'E' && str[i] != 'I' && str[i] != 'O' && str[i] != 'U') { count++; if (count == 3) { thirdLastConsonant = str[i]; break; } } } printf("%c\n", thirdLastConsonant); return 0; }

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import java.util.Scanner; public class ChangeCase { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); char c = scanner.next().charAt(0); if (Character.isLowerCase(c)) { System.out.println(Character.toUpperCase(c)); } else { System.out.println(Character.toLowerCase(c)); } scanner.close(); } }

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1. In order to open a new window in incognito mode of Chrome, you should use: - Answer: B. Ctrl + Shift + N 2. Q05. While configuring your email ID in MS Outlook, which of the following protocols should be used for sending emails? - Answer: D. SMTP 3. Q06. Which of the following network devices operates at the physical layer of the OSI model? - Answer: D. Hub 4. Q07. Which of the following is an example of a lossy compression file? - Answer: A. JPEG 5. Q08. Wireless mouse and keyboard communicate through which of the following? - Answer: A. Electromagnetic signals 6. Q09. MS Outlook will alert you if you forget to: - Answer: B. Attach a file after writing the word "attached" in the email body 7. Q10. If you are receiving all the emails of a client in the SPAM folder, which of the following actions should you take to receive them in the INBOX? - Answer: A. All of the mentioned options 8. Q11. In order to change the slideshow view to normal view in PowerPoint, which of the following can be used? - Answer: B. ESC 9. Q12. In MS Excel, Alt+= is used for which of the following purposes? - Answer: B. AutoSum 10. Q13. Performance information of which of the following is shown in the task manager? - Answer: C. All 1, 2 & 3 (CPU, Memory, GPU) 11. Q14. Ping (command line utility) is used to check which of the following? - Answer: A. Only 1 & 2 (Connectivity between host and server/host, The round-trip time of the packet) 12. Q15. Which of the following memory types in a computer is static as well as non-volatile? - Answer: A. ROM

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Wipro

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33.B 34.D 35.C

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Siemens is hiring Junior Rust Developer For 2024, 2023 grads https://jobs.siemens.com/careers/job/563156120514017?hl=en