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📈 Analytical overview of Telegram channel allcoding1
Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 22 509 subscribers, ranking 8 844 in the Education category and 19 350 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 22 509 subscribers.
According to the latest data from 18 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -405 over the last 30 days and by -11 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 6.44%. Within the first 24 hours after publication, content typically collects 1.27% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 450 views. Within the first day, a publication typically gains 287 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
- Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.
📝 Description and content policy
Channel description not provided.
Thanks to the high frequency of updates (latest data received on 19 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
22 509
Subscribers
-1124 hours
-887 days
-40530 days
Posts Archive
22 509
INFOSYS ALL EXAM ANS ARE AVAILABLE FREE OFF COST
@Infosys_Ans @Infosys_Ans
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22 509
You are given a rooted tree of N vertices and an array A of N integers A[i] is the parent of the vertex (i+1 or 0 if the vertex (i+1) is the root.
For each vertex V from 1 to N, the answer K is the total number of subsets of vertices with the LCA (lowest common ancestor) equal to V Since the of K can be large calculate it modulo 10 ^ 9 + 7
Let there be an integer array Res where Res[i] contains the answer for (I + 1)th vertex, Find the array Res
Notes:
• The lowest common ancestor (LCA) is defined for X nodes A1, A2,.... Ax as the lowest node in the tree that has all A1 A2..... Ax as descendants (where we allow a node to be a descendant of itself)
Input Formate
The first line contains an integer N denoting the number of elements in A
Each line 1 of the N subsequent lines (where 0<=i<N) contains an integer
describing All It is given that A[i] denotes the parent of the vertex (i+1) or 0
If the vertex (i+1) is the root
//@allcoding1
const int N = 100005;
const int MOD = 1e9 + 7;
int a[N], dp[N], res[N];
vector<int> g[N];
void dfs(int u) {
dp[u] = 1;
for (int v : g[u]) {
dfs(v);
dp[u] = 1ll * dp[u] * (dp[v] + 1) % MOD;
}
res[u] = (1ll * dp[u] * (1 << g[u].size()) - 1 + MOD) % MOD;
}
vector<int> functionName(int n,vector<int>A)
{
g=A;
dfs(1);
return res;
}
Language c++
22 509
INFOSYS EXAM ANS 3PM
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Telegram:- @allcoding1
@allcoding1
discussion group:- @Infosys_exam_Ans
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
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22 509
+1INFOSYS EXAM ANS 10AM
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Telegram:- @allcoding1
@allcoding1
discussion group:- @Infosys_exam_Ans
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
22 509
+1INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1
@allcoding1
discussion group:- @Infosys_exam_Ans
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
22 509
+1Java
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1
@allcoding1
discussion group:- @Infosys_exam_Ans
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
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22 509
// Infosys
// N flowers on a Recatangular pana
int ans = 100000000;
void solve(vector<int> a, int n, int k, int index, int sum,
int maxsum)
{
if (k == 1)
{
maxsum = max(maxsum, sum);
sum = 0;
for (int i = index; i < n; i++)
{
sum += a[i];
}
maxsum = max(maxsum, sum);
ans = min(ans, maxsum);
return;
}
sum = 0;
for (int i = index; i < n; i++)
{
sum += a[i];
maxsum = max(maxsum, sum);
solve(a, n, k - 1, i + 1, sum, maxsum);
}
}
int GetMaxBeauty(int N, int K, vector<int> A)
{
solve(A, N, K, 0, 0, 0);
return ans;
}
C++
INFOSYS EXAM ANS 10AM
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Telegram:- @allcoding1
@allcoding1
discussion group:- @Infosys_exam_Ans
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
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22 509
def getLargestString(s, k):
frequency_array = [0] * 26
for i in range(len(s)):
frequency_array[ord(s[i]) -
ord('a')] += 1
ans = ""
i = 25
while i >= 0:
if (frequency_array[i] > k):
temp = k
st = chr( i + ord('a'))
while (temp > 0):
ans += st
temp -= 1
frequency_array[i] -= k
j = i - 1
while (frequency_array[j] <= 0 and
j >= 0):
j -= 1
if (frequency_array[j] > 0 and
j >= 0):
str1 = chr(j + ord( 'a'))
ans += str1
frequency_array[j] -= 1
else:
break
elif (frequency_array[i] > 0):
temp = frequency_array[i]
frequency_array[i] -= temp
st = chr(i + ord('a'))
while (temp > 0):
ans += st
temp -= 1
else:
i -= 1
return ans
if name == "main":
S = input()
k = 3
print (getLargestString(S, k))
Python
Bob code
Telegram:- @allcoding1
22 509
Python
Once check it out put
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1
@allcoding1
discussion group:- @Infosys_exam_Ans
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
22 509
+1Python
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
22 509
+1Java
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
22 509
def next_stepping_number(N):
N = str(N)
for i in range(len(N) - 1):
if abs(int(N[i]) - int(N[i+1])) != 1:
return int(N[:i+1] + str(int(N[i]) + 1 if int(N[i]) < int(N[i+1]) else int(N[i]) - 1) + '9'*(len(N)-i-1))
return int(N) + 1
print(next_stepping_number(4)) # should return 5
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1
@allcoding1
discussion group:- @Infosys_exam_Ans
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
22 509
+2Python
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1
@allcoding1
Discussion group:- @infosys_exam_Ans
Coding Ans:- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
22 509
def shortest_subarray(colors, C):
n = len(colors)
color_count = [0] * (C+1)
left, right = 0, 0
min_length = float('inf')
count = 0
while right < n:
color_count[colors[right]] += 1
if color_count[colors[right]] == 1:
count += 1
while count == C:
min_length = min(min_length, right - left + 1)
color_count[colors[left]] -= 1
if color_count[colors[left]] == 0:
count -= 1
left += 1
right += 1
if min_length == float('inf'):
return -1
else:
return min_length
Python3
