allcoding1
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📈 Analytical overview of Telegram channel allcoding1
Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 20 643 subscribers, ranking 9 752 in the Education category and 19 463 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 20 643 subscribers.
According to the latest data from 06 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -405 over the last 30 days and by -19 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 3.59%. Within the first 24 hours after publication, content typically collects 1.08% reactions from the total number of subscribers.
- Post reach: On average, each post receives 742 views. Within the first day, a publication typically gains 223 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
- Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.
📝 Description and content policy
Channel description not provided.
Thanks to the high frequency of updates (latest data received on 07 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
20 643
Subscribers
-1924 hours
-957 days
-40530 days
Posts Archive
20 637
Repost from allcoding1_official
![array AR of size N perfect_sum(arr, s, result) : x = [0]*len(arr) j = len(arr) - 1 while (s > 0) : x[j] = s % 2 s = s // 2 j](https://cdn.tlmtr.io/_next/static/media/empty-channel.35ed232f.svg)
array AR of size N
perfect_sum(arr, s, result) :
x = [0]*len(arr)
j = len(arr) - 1
while (s > 0) :
x[j] = s % 2
s = s // 2
j -= 1
sum = 0
for i in range(len(arr)) :
if (x[i] == 1) :
sum += arr[i]
if (sum == result) :
print("{",end="");
for i in range(len(arr)) :
if (x[i] == 1) :
print(arr[i],end= ", ");
print("}, ",end="")
def print_subset(arr, K) :
x = pow(2, len(arr))
for i in range(1, x):
perfect_sum(arr, i, K)
# Driver code
arr = [ ]
n = int(input("Enter length of array : "))
s=int(input("Enter sum : "))
for i in range(n):
ele=int(input("Enter element : "))
arr.append(ele)
print_subset(arr, s)
Python
Telegram :- @allcoding1_official
20 637
Repost from allcoding1_official
class CountOccurrences {
public static void main(String[] args) {
String str = "aabbccd";
char a[]=str.toCharArray();
int cnt = 0;
for (int i = 0; i < a.length; i++) {
for (int j = i + 1; j < a.length; j++)
{
if ((a[i] == a[j])) {
cnt++;
}
}
}
System.out.println(cnt);
}
}
Java
Telegram:- @allcoding1_official
20 637
Number Of Subsequences Code For Infosys
int A[] = {10,13,7,8,14,11};
int n = 6;
int memo[6];//initialized with -1s;
int count(int currIndex){
if (currIndex == n-1) return 1;
if (memo[currIndex] != -1) return memo[currIndex];
int res = 0;
for (int i=currIndex+1 ; i<n ; i++){
if (abss(A[currIndex] - A[i]) <= 3){
res += count(i);
}
}
memo[currIndex] = res;
return res;
}
c++
Telegram:- @allcoding1
20 637
n = int(input())
A = int(input())
A1 = []
A2= []
A3= []
ans = 0
for i in range(n):
A1.append(int(input()))
for j in range(n):
A2.append(int(input()))
for k in range(n):
A2.append([p[k], b[k]])
a.sort()
for z in a:
if a[0] > N:
break
N += a[1]
ans += 1
print(ans)
Try this code for this question... Python 3
Telegram:- @allcoding1
20 637
Infosys exam Ans 29/7/22 at 10AM
http://www.joboffersadda.com/2022/01/infosys-exam-answer.html
http://www.joboffersadda.com/2022/01/infosys-exam-answer.html
Guys ❤️
Once check it after msg in group
Allcoding Ans are available
Telegram:- @Infosys_Ans
20 637
20 637
Guys ❤️
Get ready who are follow & subscribe OUR instagram and YouTube I'm send a private channel link at 8:40 Am
Telegram:- @allcoding1
20 637
Guys ❤️
Infosys sending test mails for SP and DSE Roles. The exam is on 29th July 2022. Please check your mails.
20 637
Private channel for Infosys 29/30/31 Exam Ans
Ask your 10 friends to follow Instagram And subscribe🛑 & LIKE👍 youtube channel and send screenshot to
He will add you to private channel for tomorrow Ans
YouTube channel:-
https://youtu.be/ofDvcsP3OWY
https://youtu.be/ofDvcsP3OWY
https://youtu.be/ofDvcsP3OWY
Instagram:-
https://instagram.com/allcoding1_official?igshid=YmMyMTA2M2Y=
https://instagram.com/allcoding1_official?igshid=YmMyMTA2M2Y=
https://instagram.com/allcoding1_official?igshid=YmMyMTA2M2Y=
Send A screen shots in this group
https://t.me/+FQoo8kIBWww2Y2Fl
Share with your friends and college group's
20 637
Private channel for Tomorrow Infosys Exam Ans
Ask your 10 friends to follow Instagram And subscribe🛑 & LIKE👍 youtube channel and send screenshot to
He will add you to private channel for tomorrow Ans
YouTube channel:-
https://youtu.be/ofDvcsP3OWY
https://youtu.be/ofDvcsP3OWY
https://youtu.be/ofDvcsP3OWY
Instagram:-
https://instagram.com/allcoding1_official?igshid=YmMyMTA2M2Y=
https://instagram.com/allcoding1_official?igshid=YmMyMTA2M2Y=
https://instagram.com/allcoding1_official?igshid=YmMyMTA2M2Y=
Send A screen shots in this group
@softwareexam_Ans
Share with your friends and college group's
20 637
KPMG hiring - Analyst
Qualification: BE/B-Tech
Apply Now:- http://www.joboffersadda.com
Telegram:- @allcoding1
20 637
🎯Volvo Off Campus Drive 2022 | Freshers | Graduate Engineer | BE/ B.Tech | Bangalore
Job Role : Graduate Engineers
Qualification : B.E/B.Tech
Batch : 2020, 2021 & 2022
CTC : 7.5 LPA-10 LPA
Apply Now:- http://www.joboffersadda.com
Telegram:- @allcoding1
20 637
🎯Wipro Recruitment 2022 For Customer Service Representative
Location: Gurugram
Qualification: Graduate
Work Experience: 0 - 2 Years
Apply:- http://www.joboffersadda.com
Telegram:- @allcoding1
20 637
🎯Tata Technologies Recruitment 2022 : Hiring for Freshers with 6 LPA
Designation : Graduate Engineer Trainee
Batch : 2021/2022
Eligibility : BE/B.Tech
CTC : Rs. 6.5LPA
Apply Now:- http://www.joboffersadda.com/2022/07/tata-technologies-recruitment-2022.html
Telegram:- @allcoding1
20 637
import javadotio; import java.util.;
public class Solution {
public static void main(String[] args) {
Scanner sc=new Scanner(Systemdotin);
int N=sc.nextInt();
int X=sc.nextInt();
int Y=sc.nextInt();
int T=sc.nextInt();
int M=sc.nextInt();
int[][] mat=new int[N][N];
for(int i=0;i<M;i++){
int a=sc.nextInt();
int b=sc.nextInt();
mat[a][b]=1;
mat[b][a]=1;
}
int[][] tempMat=mat;
int[][] temp2Mat=new int[N][N];
if(T==1){
System.out.println(mat[X][Y]==0?"not possible":mat[X][Y]);
}
else{
int temp=0;
for(int i=1;i<T;i++){
for(int j=0;j<N;j++){
for(int k=0;k<N;k++){
int t2=0;
for(int l=0;l<N;l++){
t2+=mat[j][l]*tempMat[l][k];
}
temp2Mat[j][k]=t2;
}
}
mat=temp2Mat;
temp2Mat=new int[N][N];
}
System.out.println(mat[X][Y]==0?"not possible":mat[X][Y]);
}
}
}
BANK ROBBERY
Java 8
Telegram:- @allcoding1
