en
Feedback
Deloitte | PWC | ATS resumes | Wipro | Infosys | Accenture | Capegemini | job links

Deloitte | PWC | ATS resumes | Wipro | Infosys | Accenture | Capegemini | job links

Open in Telegram
4 673
Subscribers
No data24 hours
-17 days
-630 days
Posts Archive
int solve(vector<int>& arr) { if(arr.size()==1) { if(arr[0]==0) return 0; else return 1; } int used = 0; int start = 0; int n = arr.size(); int result = 0; for (int i = 0; i < n; i++) { while ((used&arr[i])!=0) { used ^= arr[start]; start++; } used |= arr[i]; if (start < i) result+=i - start + 1; } return 2*result; } // Count subsets

import java.util.* data class Node(val value: Int, val dist: Int) const val INF = 1e9.toInt() fun main() { val n = readLine()!!.toInt() val m = readLine()!!.toInt() val A = readLine()!!.split(" ").map { it.toInt() }.toMutableList() val graph = List(n) { mutableListOf<Int>() } val dist = List(n) { IntArray(n) { INF } } repeat(n) { A[it] = readLine()!!.toInt() } repeat(m) { val (x, y) = readLine()!!.split(" ").map { it.toInt() - 1 } graph[x].add(y) graph[y].add(x) dist[x][y] = 1 dist[y][x] = 1 } for (k in 0 until n) { for (i in 0 until n) { for (j in 0 until n) { dist[i][j] = minOf(dist[i][j], dist[i][k] + dist[k][j]) } } } val pq = PriorityQueue<Node>(compareBy { it.dist }) for (i in 0 until n) { if (A[i] > 0) { pq.add(Node(i, 0)) } } var cost = 0L while (pq.isNotEmpty()) { val node = pq.poll() val u = node.value val d = node.dist if (A[u] > 0) { cost += d * A[u] A[u] = 0 for (v in graph[u]) { if (A[v] > 0) { pq.add(Node(v, d + 1)) } } } } for (i in 0 until n) { if (A[i] > 0) { println(-n) return } } println(cost) } // Tree = 0

int dp[603]; int mex(vector<int>&v, int i, int j){      set<int>st;      for(int ind = i;ind <= j;ind++) st.insert(v[ind]);      int ans = 1;      for(auto pr : st){           if(pr == ans) ans++;      }      return ans; } int helper(vector<int>& arr, int ind, int k){          int n = arr.size();     if(k == 1) return mex(arr, ind, n - 1);                                                 if(dp[ind] != -1)  return dp[ind];     int maxi = INT_MIN;     for(int i = ind;i <= (n - k);i++){        int ans = mex(arr, ind, i) + helper(arr, i + 1, k - 1);        maxi = max(maxi, ans);     }     return dp[ind] = maxi; } int solve(int N, int K, vector<int>A){      memset(dp, -1, sizeof(dp));     return helper(A, 0 , K); } // Max Strikes again

Next code is ready Add 20 more members enough Share share Pls like this messageWho are sharing our group

Next code is ready Add 20 more members enough Share share https://t.me/infosys_codes Pls like this message 👆 Who are sharing our group

int min_operations(string s) {     int n = s.length();     vector> dp(n, vector(n, INT_MAX));     for (int i = 0; i < n; i++) {         dp[i][i] = 0;     }     for (int len = 2; len <= n; len++) {         for (int i = 0; i <= n - len; i++) {             int j = i + len - 1;             if (s[i] == s[j]) {                 dp[i][j] = min(dp[i][j], dp[i + 1][j - 1]);             } else {                 for (int k = i; k < j; k++) {                     dp[i][j] = min(dp[i][j], dp[i][k] + dp[k + 1][j] + 1);                 }             }         }     }     return dp[0][n - 1]; } String dot Java Code

Pls like this message 👆 Who are sharing our group

Next code is ready Add 20 more members enough Share share https://t.me/infosys_codes

#include <iostream> #include <vector> #include <deque> #include <unordered_map> using namespace std; int smartTaxiDriver(int N, int K, vector<int>& T, vector<int>& P, vector<int>& C) {     unordered_map<int, vector<pair<int, int>>> g;     for (int i = 0; i < N - 1; ++i) {         g[P[i] - 1].push_back({i + 2, C[i]});     }     int mpc = 0;     for (int sn = 1; sn <= N; ++sn) {         vector<int> d(N + 1, -1);         d[sn] = 0;         deque<pair<int, int>> q = {{sn, 0}};         while (!q.empty()) {             auto [cn, cd] = q.front();             q.pop_front();             for (auto& [ne, rd] : g[cn]) {                 if (d[ne] == -1 || d[ne] > cd + rd) {                     d[ne] = cd + rd;                     q.push_back({ne, d[ne]});                 }             }         }         int pc = 0;         for (int des : T) {             if (d[des] <= K) {                 pc++;             }         }         mpc = max(mpc, pc);     }     return mpc - 1; } int main() {     int N, K;     cin >> N >> K;     vector<int> T(N - 1), P(N - 1), C(N - 1);     for (int i = 0; i < N - 1; ++i) {         cin >> T[i];     }     for (int i = 0; i < N - 1; ++i) {         cin >> P[i];     }     for (int i = 0; i < N - 1; ++i) {         cin >> C[i];     }     int res = smartTaxiDriver(N, K, T, P, C);     cout << res << endl;     return 0; } Smart Taxi Driver C++ Code

#include <bits/stdc++.h> using namespace std; void solve(vector<vector<int>> vv, int operation, int xx, int yy, int &res) {     for (int i = 1; i < 3; i++)     {         int sum1 = 0;         for (int j = 0; j < vv.size(); j++)         {             sum1 += vv[j][i - 1];         }         int sum2 = 0;         for (int j = 0; j < vv.size(); j++)         {             sum2 += vv[j][i];         }         if (sum1 == sum2)         {             res = min(res, operation);         }         return;     }     for (int i = 0; i < vv.size(); i++)     {         solve(vv, operation, xx, yy, res);         vector<int> p1 = vv[i];         reverse(p1.begin(), p1.end());         solve(vv, operation + yy, xx, yy, res);         vector<int> p2 = vv[i];         int temp1 = p2[0];         int temp2 = p2[1];         int temp3 = p2[2];         p2[2] = temp1;         p2[1] = temp3;         p2[0] = temp2;         solve(vv, operation + xx, xx, yy, res);         vector<int> p3 = vv[i];         temp1 = p2[0];         temp2 = p2[1];         temp3 = p2[2];         p2[2] = temp2;         p2[1] = temp1;         p2[0] = temp3;         solve(vv, operation + xx, xx, yy, res);     }     return; } int main() {     ios_base::sync_with_stdio(false);     cin.tie(NULL);     int t = 1;     while (t--)     {         int n = 0, m = 0, a = 0, b = 0, c = 0, d = 0, sum = 0, diff = 0, maxN = 0, minN = 0, count = 0, temp = 0;         bool flag = false;         cin >> n;         cin >> m;         int xx;         cin >> xx;         int yy;         cin >> yy;         vector<vector<int>> vv(n, vector<int>(m));         for (int i = 0; i < n; i++)         {             for (int j = 0; j < m; j++)             {                 cin >> vv[i][j];             }         }         if (n == 1)         {             cout << -1 << endl;             continue;         }         int res = INT_MAX;         solve(vv, 0, xx, yy, res);         cout << res << endl;     }     return 0; } // Pay for a gift

Next code is ready Only 20 more members needed Share share https://t.me/infosys_codes

Next code is ready Only 20 more members needed **Share share* https://t.me/infosys_codes

int min_operations(string s) {     int n = s.length();     vector<vector<int>> dp(n, vector<int>(n, INT_MAX));     for (int i = 0; i < n; i++) {         dp[i][i] = 0;     }     for (int len = 2; len <= n; len++) {         for (int i = 0; i <= n - len; i++) {             int j = i + len - 1;             if (s[i] == s[j]) {                 dp[i][j] = min(dp[i][j], dp[i + 1][j - 1]);             } else {                 for (int k = i; k < j; k++) {                     dp[i][j] = min(dp[i][j], dp[i][k] + dp[k + 1][j] + 1);                 }             }         }     }     return dp[0][n - 1]; } // String dot

#include <bits/stdc++.h> using namespace std; #define ll long long ll dp[10005][2]; const int mod = (1e9 + 7); ll solve(ll i, ll o, ll n, ll k, vector<ll> &v) { if (i > n) { return 0; } if (dp[i][o] != -1) return dp[i][o]; ll ans = 0; if (o == 0) { for (int j = i; j < min(n + 1, i + k); j++) { ans = max(ans, solve(j + 1, 1 - o, n, k, v)) % mod; } } else { ll ta = 0; ll mx = 0; for (int j = i; j < min(n + 1, i + k); j++) { if (ta + v[j] >= 0) { ta += v[j]; mx = max(mx, ta); } else { ta = 0; } ll c = solve(j + 1, 1 - o, n, k, v) % mod; ans = max(ans, ((j - i + 1) * mx) % mod + c % mod); } } return dp[i][o] = ans; } int main() { ll n, k; cin >> n >> k; vector<ll> v; ll neg = 0; for (int i = 0; i < n; i++) { ll x; cin >> x; v.push_back(x); if (x <= 0) neg++; } if (neg == v.size()) { cout << 0 << endl; return 1; } memset(dp, -1, sizeof(dp)); cout << max(solve(0, 0, v.size() - 1, k, v), solve(0, 1, v.size() - 1, k, v)) << endl; } // Array Segments

#include <iostream> #include <vector> #include <deque> #include <unordered_map> using namespace std; int smartTaxiDriver(int N, int K, vector<int>& T, vector<int>& P, vector<int>& C) {     unordered_map<int, vector<pair<int, int>>> g;     for (int i = 0; i < N - 1; ++i) {         g[P[i] - 1].push_back({i + 2, C[i]});     }     int mpc = 0;     for (int sn = 1; sn <= N; ++sn) {         vector<int> d(N + 1, -1);         d[sn] = 0;         deque<pair<int, int>> q = {{sn, 0}};         while (!q.empty()) {             auto [cn, cd] = q.front();             q.pop_front();             for (auto& [ne, rd] : g[cn]) {                 if (d[ne] == -1 || d[ne] > cd + rd) {                     d[ne] = cd + rd;                     q.push_back({ne, d[ne]});                 }             }         }         int pc = 0;         for (int des : T) {             if (d[des] <= K) {                 pc++;             }         }         mpc = max(mpc, pc);     }     return mpc - 1; } int main() {     int N, K;     cin >> N >> K;     vector<int> T(N - 1), P(N - 1), C(N - 1);     for (int i = 0; i < N - 1; ++i) {         cin >> T[i];     }     for (int i = 0; i < N - 1; ++i) {         cin >> P[i];     }     for (int i = 0; i < N - 1; ++i) {         cin >> C[i];     }     int res = smartTaxiDriver(N, K, T, P, C);     cout << res << endl;     return 0; } **//Smart Taxi Driver *(

Next code is ready Only 3 more members needed Share share

#include <iostream> #include <vector> const int MOD = 1000000007; using namespace std; int countBeautifulSequences(int n) {     if (n == 1) {         return 1;     }     vector<int> dp(n + 1, 0);     dp[1] = 1;     for (int i = 1; i <= n; ++i) {         for (int j = i; j <= n; ++j) {             dp[j] = (dp[j] + dp[j - i]) % MOD;         }     }     return (dp[n] - 1 + MOD) % MOD; } int main() {     int n;     cin >> n;     int result = countBeautifulSequences(n);     cout << result << endl;     return 0; } Count Beautiful sequence