Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Open in Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

India31 783 Education15 316...

📈 Analytical overview of Telegram channel Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Channel Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) in the English language segment is an active participant. Currently, the community unites 13 223 subscribers, ranking 15 316 in the Education category and 31 783 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 13 223 subscribers.

According to the latest data from 23 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -162 over the last 30 days and by 1 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 2.68%. Within the first 24 hours after publication, content typically collects 0.93% reactions from the total number of subscribers.
Post reach: On average, each post receives 354 views. Within the first day, a publication typically gains 123 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 1.
Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Thanks to the high frequency of updates (latest data received on 24 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

13 223

Subscribers

+124 hours

-317 days

-16230 days

354

Post views

~ 12324 hours

~ 14148 hours

2.68%

Engagement rate

~ 2

Posts per day

Ads index

beta

Posts Archive

13 223

Tmrw deshaw exsm help available Contact fast and book your slots Contact @srksvk 100% clearance guarantee ✅ Remote access also available ✅

13 223

Infosys sp exam help successfully done by remote access ✅✅ 3/3 code fully passed ✅✅✅ 🔥🔥🔥 Contact for placement exam @srksvk

13 223

#include <vector> const int MOD = 1000000007; int countPrettyPartitions(int N, int L, int R, std::vector<int>& A) { std::vector<int> dp(N + 1, 0); dp[0] = 1; for (int i = 1; i <= N; ++i) { int xor_value = 0; for (int j = i; j >= 1; --j) { xor_value ^= A[j - 1]; if (L <= xor_value && xor_value <= R) { dp[i] = (dp[i] + dp[j - 1]) % MOD; } } } return dp[N]; } Dividing array

13 223

int findTotal(string s){ unordered_setst; for(int i=0;i

13 223

After 12k I willl post all

13 223

Fully passed

13 223

#include <iostream> #include <vector> #include <algorithm> long long solve(int N, std::vector<int>& A) { std::sort(A.begin(), A.end()); long long minSum = A[0]; int prev = A[0]; for (int i = 1; i < N; ++i) { if (A[i] <= prev) { A[i] = prev + 1; } prev = A[i]; minSum += A[i]; } return minSum; } .. Minimum unique sum 🙃🙃

13 223

Make it 12k everyone Then I will share all codes ☺️ Share @codeing_area

13 223

int n = S.length(); unordered_map leftFreq, rightFreq; unordered_set leftSet, rightSet; // Initialize the rightFreq map and rightSet with the entire string S for (char c : S) { rightFreq[c]++; rightSet.insert(c); } int maxX = 0; // Traverse the string and adjust the left and right sets and maps for (int i = 0; i < n - 1; ++i) { char c = S[i]; leftFreq[c]++; rightFreq[c]--; if (rightFreq[c] == 0) { rightSet.erase(c); } leftSet.insert(c); int currentSum = leftSet.size() + rightSet.size(); maxX = max(maxX, currentSum); } return n - maxX; Infosys ✅ Fully passed Split string ✅✅

13 223

Shortest string

13 223

Done first ✅✅✅✅

13 223

Make it 12k

13 223

Gys share FAstt

13 223

long long solve(int n,vector<int>v){ long long ans=0; sort(v.begin(),v.end()); for(int i=1;i<n;i++){ if(v[i]<=v[i-1]){ v[i]=v[i-1]+1; } } ans=accumulate(v.begin(),v.end(),0); return ans; } Minimum unique sum✅ Infosys ( Full passed ✅✅ Share @codeing_area

13 223

Guys, Make it 12k .. after 12 k I will send sloution

13 223

Next sloution After 12k I will uploaded ✅✅

13 223

#include <bits/stdc++.h> using namespace std; int equalzeroandone(vector<int>v){ int n=v.size(); for(int i=0;i<n;i++){ if(v[i]==0){ v[i]=-1; } } int sum=0; int ans=-1; map<int,int>mp; for(int i=0;i<n;i++){ sum+=v[i]; if(sum==0){ ans=i+1; } if(mp.find(sum)!=mp.end()){ ans=max(ans,i-mp[sum]); } else{ mp[sum]=i; } } return ans; } int main() { int n; cin>>n; vector<int>v(n); for(int i=0;i<n;i++){ cin>>v[i]; } cout<<equalzeroandone(v); } Equal no of zero and one(Infosys) Full passed ✅✅ Shared @codeing_area

13 223

Share with your Friends and in Big groups we will definitely post answers here We will Try to share Some answers Here also in our Groups. So must Join 1) @codeing_area 2) @codeing_area 3) @codeing_area

13 223

Accenture hackdivaa slot available ✅ Contact fast and book your slots ✅ Contact @srksvk Remote access available 🔥🥇🥇 200% suree clearance guarantee ✅🔥🔥 Priviously helped 👇👇👇 https://t.me/codeing_area/7643?single https://t.me/codeing_area/8059?single

13 223