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INFOSYS EXAM SOLUTIONS

INFOSYS EXAM SOLUTIONS

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πŸ”₯Guys plz Stop fearing for daily exams πŸ“ πŸ‘¨β€πŸ’» @srksvk is here to help you all at lowest cost possible.πŸ’ͺ πŸŒ€ ” Our Only Aim Is To Let Get Placed To You In A Reputed Company πŸ”₯Effort from our side = πŸ’― πŸ“±Main Channel: @coding_are πŸ“±Tel I'd : @srksvk

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πŸ“ˆ Analytical overview of Telegram channel INFOSYS EXAM SOLUTIONS

Channel INFOSYS EXAM SOLUTIONS (@coding_are) in the English language segment is an active participant. Currently, the community unites 14 323 subscribers, ranking 14 155 in the Education category and 29 163 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 14 323 subscribers.

According to the latest data from 01 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 987 over the last 30 days and by 552 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 7.48%. Within the first 24 hours after publication, content typically collects 2.55% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 061 views. Within the first day, a publication typically gains 362 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 3.
  • Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œπŸ”₯Guys plz Stop fearing for daily exams πŸ“ πŸ‘¨β€πŸ’» @srksvk is here to help you all at lowest cost possible.πŸ’ͺ πŸŒ€ ” Our Only Aim Is To Let Get Placed To You In A Reputed Company πŸ”₯Effort from our side = πŸ’― πŸ“±Main Channel: @coding_are πŸ“±Tel I'd : @srks...”

Thanks to the high frequency of updates (latest data received on 02 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

14 323
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+8087 days
+98730 days
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2nd linkdin codeβœ…

public static List getMinSum(List arr, List query, int k) { List result = new ArrayList<>(); int n = arr.size(); for (int z : query) { int minSum = Integer.MAX_VALUE; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { int x = arr.get(i); int y = arr.get(j); if (x == 0 && y == 0) continue; if (x != 0 && z % x == 0) { int a = z / x, b = 0; if (a >= 0) minSum = Math.min(minSum, a + b); } if (y != 0 && z % y == 0) { int a = 0, b = z / y; if (b >= 0) minSum = Math.min(minSum, a + b); } if (x != 0) { for (int a = 0; a <= k; a++) { int rem = z - a * x; if (rem < 0) break; if (y != 0 && rem % y == 0) { int b = rem / y; if (b >= 0 && a + b <= k) { minSum = Math.min(minSum, a + b); } } } } } } result.add(minSum <= k ? minSum : -1); } return result; }

Linkdin first' codeβœ…

import java.util.*; class Result { public static int findMinOperations(List<Integer> arr) { int n = arr.size(); int operations = 0; int rootCount = 0; for (int x : arr) { if (x == -1) rootCount++; } if (rootCount == 0) { arr.set(0, -1); operations++; } else if (rootCount > 1) { boolean found = false; for (int i = 0; i < n; i++) { if (arr.get(i) == -1) { if (!found) { found = true; } else { arr.set(i, 1); operations++; } } } } for (int i = 0; i < n; i++) { int parent = arr.get(i); if (parent != -1 && (parent < 1 || parent > n)) { arr.set(i, 1); operations++; } } boolean[] visited = new boolean[n]; boolean[] inStack = new boolean[n]; for (int i = 0; i < n; i++) { if (!visited[i]) { operations += dfsFixCycle(arr, visited, inStack, i); } } return operations; } private static int dfsFixCycle(List<Integer> arr, boolean[] visited, boolean[] inStack, int node) { int operations = 0; while (node != -1 && !visited[node]) { visited[node] = true; inStack[node] = true; int parent = arr.get(node) == -1 ? -1 : arr.get(node) - 1; if (parent != -1) { if (!visited[parent]) { node = parent; } else if (inStack[parent]) { arr.set(node, -1); operations++; break; } else { break; } } else { break; } } Arrays.fill(inStack, false); return operations; } } public class Solution { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); List<Integer> arr = new ArrayList<>(); for (int i = 0; i < n; i++) { arr.add(sc.nextInt()); } System.out.println(Result.findMinOperations(arr)); } }