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ACCENTURE EXAM SOLUTIONS

ACCENTURE EXAM SOLUTIONS

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πŸ”₯Guys plz Stop fearing for daily exams πŸ“ πŸ‘¨β€πŸ’» @srksvk is here to help you all at lowest cost possible.πŸ’ͺ πŸŒ€ ” Our Only Aim Is To Let Get Placed To You In A Reputed Company πŸ”₯Effort from our side = πŸ’― πŸ“±Main Channel: @coding_are πŸ“±Tel I'd : @srksvk

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πŸ“ˆ Analytical overview of Telegram channel ACCENTURE EXAM SOLUTIONS

Channel ACCENTURE EXAM SOLUTIONS (@coding_are) in the English language segment is an active participant. Currently, the community unites 14 042 subscribers, ranking 14 513 in the Education category and 28 436 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 14 042 subscribers.

According to the latest data from 13 October, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -124 over the last 30 days and by -6 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 3.63%. Within the first 24 hours after publication, content typically collects 1.83% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 510 views. Within the first day, a publication typically gains 257 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
  • Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œπŸ”₯Guys plz Stop fearing for daily exams πŸ“ πŸ‘¨β€πŸ’» @srksvk is here to help you all at lowest cost possible.πŸ’ͺ πŸŒ€ ” Our Only Aim Is To Let Get Placed To You In A Reputed Company πŸ”₯Effort from our side = πŸ’― πŸ“±Main Channel: @coding_are πŸ“±Tel I'd : @srks...”

Thanks to the high frequency of updates (latest data received on 14 October, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

14 042
Subscribers
-624 hours
-377 days
-12430 days
Posts Archive
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IBM exam successfully done by remote access βœ…βœ… 2/2 codes fully passed with all the tests cases passed βœ…βœ… Contact for placement exam @srksvk

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int f(int i, int j, int flag, vector& arr, int sum, vector>>& dp) {     if (i >= j) return 0;     if (dp[i][j][flag] != -1) return dp[i][j][flag];     int firsttwo = 0;     int lasttwo = 0;     int firstlast = 0;     if (i + 1 < arr.size() && arr[i] + arr[i + 1] == sum) {         firsttwo = 1 + f(i + 2, j, flag, arr, sum, dp);     }     if (arr[i] + arr[j] == sum) {         firstlast = 1 + f(i + 1, j - 1, flag, arr, sum, dp);     }     if (j >= 0 && arr[j] + arr[j - 1] == sum) {         lasttwo = 1 + f(i, j - 2, flag, arr, sum, dp);     }     return dp[i][j][flag] = max({firsttwo, lasttwo, firstlast}); } int solution(vector& arr) {     int n = arr.size();     vector>> dp(n, vector>(n, vector(3, -1)));     int sum1 = arr[0] + arr[n - 1];     int sum2 = arr[0] + arr[1];     int sum3 = arr[n - 1] + arr[n - 2];     int ans1 = f(0, n - 1, 0, arr, sum1, dp);     int ans2 = f(0, n - 1, 1, arr, sum2, dp);     int ans3 = f(0, n - 1, 2, arr, sum3, dp);     int res = max(ans1, max(ans2, ans3));     return res; }

#include <bits/stdc++.h> using namespace std; int solution(vector<int>& A) { sort(A.begin(), A.end()); if (A.size() <= 2) { return A.size(); } int maxCount = 0; unordered_map<int, int> differences[A.size()]; for (int i = 1; i < A.size(); i++) { for (int j = 0; j < i; j++) { int currentDiff = A[i] - A[j]; int currentCnt = 1; if (differences[j].count(currentDiff) != 0) { currentCnt += differences[j][currentDiff]; differences[i][currentDiff] = currentCnt; } else { differences[i][currentDiff] = 1 + currentCnt; } maxCount = max(maxCount, differences[i][currentDiff]); } } return maxCount; } task 2

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