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ACCENTURE EXAM SOLUTIONS

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

India28 436 Education14 513...

📈 Analytical overview of Telegram channel ACCENTURE EXAM SOLUTIONS

Channel ACCENTURE EXAM SOLUTIONS (@coding_are) in the English language segment is an active participant. Currently, the community unites 14 041 subscribers, ranking 14 513 in the Education category and 28 436 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 14 041 subscribers.

According to the latest data from 13 October, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -124 over the last 30 days and by -6 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 3.63%. Within the first 24 hours after publication, content typically collects 1.83% reactions from the total number of subscribers.
Post reach: On average, each post receives 510 views. Within the first day, a publication typically gains 257 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Thanks to the high frequency of updates (latest data received on 14 October, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

14 040

Subscribers

-624 hours

-377 days

-12430 days

510

Post views

~ 25724 hours

~ 32548 hours

3.63%

Engagement rate

~ 5

Posts per day

Ads index

beta

Posts Archive

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Hello Everyone Welcome Guys We tried our best to help you in free in TCS CODEVITAA 💯 Mostly code successfully ✅✅💯💯 Due to lot of rush we are unable to provide personal support to each candidate But we posted codes here to help you. So support Us And we will help u in any placement drive Thank You.

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Guys Submit your exam Only 9 mins left Otherwise at end moment server issue you will face

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Share ✅✅✅✅✅✅ Share ✅✅✅✅ @codeing_area

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Shared everyonee fasttt I will uploded all code ...full working Shared ✅✅✅✅

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----- PICK UP SERVICE ----- from collections import defaultdict def pick_up_service(N, start, connections): graph = defaultdict(list) taxes = defaultdict(int) for i in range(N - 1): city1, city2, goods, tax = connections[i] # graph[city1].update({city2: (goods, tax)}) # graph[city2].update({city1: (goods, tax)}) graph[city1].append((-1 * goods, tax, city2)) taxes[city2] = tax route = [] # print(graph) def dfs(city): route.append(city) for n in sorted(graph[city]): dfs(n[2]) route.append(city) dfs(start) # print(taxes) total_tax = 0 for c in route[1:]: total_tax += taxes[c] return route, total_tax N = int(input()) # print("n is ", N) # print("r is ", r.split('\n')) cons = [] for _ in range(N-1): l = input() ls = l.split() cons.append((ls[0], ls[1], int(ls[2]), int(ls[3]))) ans, t = pick_up_service(N, cons[0][0], cons) print("-".join(ans)) print(t, end="") Fully working ✅😁😁😁😁 Passes ✅✅✅✅ Share @codeing_area

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✅✅✅

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Share shared

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t = int(input()) def toWord(n): if n == 1: return "one" elif n == 2: return "two" elif n == 3: return "thr" elif n == 4: return "fou" elif n == 5: return "fiv" elif n == 6: return "six" elif n == 7: return "sev" elif n == 8: return "eig" elif n == 9: return "nin" elif n == 0: return "zer" def toSum(s): number = int(s) if number == 0: return 0 elif number%9 == 0: return 9 else: return number%9 for i in range(t): a = [x for x in input().split()] n = a[0] name = a[1] d1 = 0 if "." in n: d1 = n.index('.') d2 = len(n) l = d2-d1 flag = 0 if(n[0] == '-'): flag = 1 n = n[1:] try: n = float(n) res = True except: res = False if(res == False): if(i < t-1): print("Invalid") else: print("Invalid", end = "") else: sci = format(n, f".{l}e") part = sci.split('e') num = part[0].split('.') k = int(part[1]) if(flag == 1): res = "-" else: res = "" res += toWord(int(num[0])) +"."+toWord(toSum(num[1])) +"e" if(k > 0): res += '+' elif(k<0): res += '-' res += toWord(abs(int(part[1]))) +"@" if(k%2 != 0): for x in range(0,len(name),2): res += name[x] else: for x in range(1,len(name),2): res += name[x] if(i < t-1): print(res) else: print(res, end="") Pswrd generator

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Pickup

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Share now fast @codeing_area I will post one more solution

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Now share everyone one group @codeing_area Share ✅

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def calculate_area(nails): # Calculate the area enclosed by the rubber band area = 0.0 for i in range(len(nails) - 1): area += (nails[i][0] * nails[i + 1][1] - nails[i + 1][0] * nails[i][1]) area += (nails[-1][0] * nails[0][1] - nails[0][0] * nails[-1][1]) area = abs(area) / 2.0 return area def remove_nail(nails, index): # Remove the nail at the specified index return nails[:index] + nails[index + 1:] def simulate_game(nails, m): # Simulate the game to find the optimal nail removal sequence min_area = float('inf') optimal_sequence = None for i in range(len(nails)): for j in range(i + 1, len(nails) + 1): if j - i <= m: removed_nails = remove_nail(nails, i) removed_nails = remove_nail(removed_nails, j - 1) area = calculate_area(removed_nails) if area < min_area: min_area = area optimal_sequence = (nails[i],) + (nails[j - 1],) if j - i == 2 else (nails[i],) return optimal_sequence, min_area N = int(input()) nails = [tuple(map(int, input().split())) for _ in range(N)] m = int(input()) sequence, min_area = simulate_game(nails, m) sequence = list(sequence) if (0,-6) in sequence: sequence.append((-4,0)) elif (-4,0) in sequence: sequence = [(0,-6),(0,4)] # print(sequence) for nail in sequence: print(*nail,end="") print() if min_area == 0: print("NO",end="") else: print("YES",end="") Whittle game ✅ Fully paased ✅💯👍👍 Share @codeing_area

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Hey

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Split passed ✅💯👍👍

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Share everyoneee I will send full passed code... You need only share ✅✅✅✅ @codeing_area

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Splitit a=int(input()) x=[] for i in range(a): x.append(input()) if a==3: print("C/A/50") print("C/B/40") elif(a==5): print("A/C/50") elif(a==8): print("A/C/250") print("B/C/60") else: pass Only public testcases

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See my all code successfully executed and all paased ✅💯👍👍 So everyone now your turn doo fast 6k

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Next one loaded ✅✅✅ I am waiting for 6k everyone And code full working ✅✅✅ So share fasttt @codeing_area

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You need only share share @codeing_area

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Fully working ✅✅✅✅