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Tcs exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Tcs exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

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πŸ”₯Guys plz Stop fearing for daily exams πŸ“ πŸ‘¨β€πŸ’» @srksvk is here to help you all at lowest cost possible.πŸ’ͺ πŸŒ€ ” Our Only Aim Is To Let Get Placed To You In A Reputed Company πŸ”₯Effort from our side = πŸ’― πŸ“±Main Channel: @coding_are πŸ“±Tel I'd : @srksvk

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πŸ“ˆ Analytical overview of Telegram channel Tcs exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Channel Tcs exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) in the English language segment is an active participant. Currently, the community unites 13 276 subscribers, ranking 15 335 in the Education category and 32 351 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 13 276 subscribers.

According to the latest data from 12 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 111 over the last 30 days and by -9 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 2.86%. Within the first 24 hours after publication, content typically collects 1.13% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 380 views. Within the first day, a publication typically gains 150 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 1.
  • Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œπŸ”₯Guys plz Stop fearing for daily exams πŸ“ πŸ‘¨β€πŸ’» @srksvk is here to help you all at lowest cost possible.πŸ’ͺ πŸŒ€ ” Our Only Aim Is To Let Get Placed To You In A Reputed Company πŸ”₯Effort from our side = πŸ’― πŸ“±Main Channel: @coding_are πŸ“±Tel I'd : @srks...”

Thanks to the high frequency of updates (latest data received on 13 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

13 276
Subscribers
-924 hours
-397 days
+11130 days
Posts Archive
from collections import deque from typing import List, Dict, Tuple, Set class InputData: def init(self): self.connections: List[Tuple[int, int]] = [] self.costs: Dict[int, int] = {} self.values: Dict[int, int] = {} self.budget: int = 0 self.depth: int = 0 self.seed_order: List[int] = [] def read_input() -> InputData: data = InputData() n = int(input()) num_connections = int(input()) for _ in range(num_connections): u, v = map(int, input().split()) data.connections.append((u, v)) num_seeds = int(input()) for _ in range(num_seeds): user_id, cost = map(int, input().split()) data.costs[user_id] = cost data.seed_order.append(user_id) for i in range(1, n + 1): value = int(input()) data.values[i] = value data.budget, data.depth = map(int, input().split()) return data def bfs_reach(start: int, adj: List[List[int]], d: int) -> List[int]: visited: Set[int] = set() q = deque([(start, 0)]) visited.add(start) reach = [] while q: u, dist = q.popleft() reach.append(u) if dist == d: continue for v in adj[u]: if v not in visited: visited.add(v) q.append((v, dist + 1)) return reach def solve_campaign( connections: List[Tuple[int, int]], costs: Dict[int, int], values: Dict[int, int], seed_order: List[int], budget: int, d: int ) -> Tuple[List[int], int, int]: n = len(values) adj = [[] for _ in range(n + 1)] for u, v in connections: adj[u].append(v) adj[v].append(u) reach_map: Dict[int, List[int]] = {} for s in costs: reach_map[s] = bfs_reach(s, adj, d) chosen: List[int] = [] total_value = 0 total_cost = 0 covered: Set[int] = set() remaining = seed_order.copy() while True: best_eff = -1 best_seed = -1 best_gain = 0 best_cost = 0 for s in remaining: c = costs[s] if total_cost + c > budget: continue gain = 0 for u in reach_map[s]: if u not in covered: gain += values[u] if gain == 0: continue eff = gain / c if ( eff > best_eff or (eff == best_eff and seed_order.index(s) < seed_order.index(best_seed)) ): best_eff = eff best_seed = s best_gain = gain best_cost = c if best_seed == -1: break chosen.append(best_seed) total_cost += best_cost total_value += best_gain for u in reach_map[best_seed]: covered.add(u) remaining.remove(best_seed) return chosen, total_value, total_cost def main(): data = read_input() chosen, total_value, total_cost = solve_campaign( data.connections, data.costs, data.values, data.seed_order, data.budget, data.depth, ) print(" ".join(map(str, chosen))) print(total_value) print(total_cost) if name == "main": main()

Puzzle Python 3 All tests caes passed βœ…

from typing import List, Set class Trie: def init(self): self.end = False self.next = {} def insert_word(root: Trie, word: str) -> None: cur = root for c in word: if c not in cur.next: cur.next[c] = Trie() cur = cur.next[c] cur.end = True dirs = [(1,0), (-1,0), (0,1), (0,-1), (1,1), (1,-1), (-1,1), (-1,-1)] def dfs(board: List[List[str]], x: int, y: int, node: Trie, path: List[str], res: Set[str]): c = board[x][y] if c not in node.next: return node = node.next[c] path.append(c) if node.end: res.add("".join(path)) board[x][y] = "#" for dx, dy in dirs: nx, ny = x + dx, y + dy if 0 <= nx < len(board) and 0 <= ny < len(board[0]) and board[nx][ny] != "#": dfs(board, nx, ny, node, path, res) board[x][y] = c path.pop() def solve_problem(rows: int, cols: int, board: List[List[str]], words: List[str]) -> None: root = Trie() for w in words: insert_word(root, w) found = set() path = [] for i in range(rows): for j in range(cols): dfs(board, i, j, root, path, found) if not found: print(0) return ans = sorted(found) print(len(ans)) for w in ans: print(w) if name == "main": R, C = map(int, input().split()) board = [list(input().strip().replace(" ", "")) for _ in range(R)] n = int(input()) words = [input().strip() for _ in range(n)] solve_problem(R, C, board, words)

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