ACCENTURE EXAM SOLUTIONS

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

India28 155 Education14 131...

📈 Analytical overview of Telegram channel ACCENTURE EXAM SOLUTIONS

Channel ACCENTURE EXAM SOLUTIONS (@coding_are) in the English language segment is an active participant. Currently, the community unites 14 088 subscribers, ranking 14 131 in the Education category and 28 155 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 14 088 subscribers.

According to the latest data from 05 October, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -120 over the last 30 days and by -12 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 3.51%. Within the first 24 hours after publication, content typically collects 1.81% reactions from the total number of subscribers.
Post reach: On average, each post receives 495 views. Within the first day, a publication typically gains 255 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Thanks to the high frequency of updates (latest data received on 06 October, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

14 088

Subscribers

-1224 hours

-327 days

-12030 days

495

Post views

~ 25524 hours

~ 31648 hours

3.51%

Engagement rate

~ 4

Posts per day

Ads index

beta

Posts Archive

14 088

int n = S.length(); unordered_map leftFreq, rightFreq; unordered_set leftSet, rightSet; // Initialize the rightFreq map and rightSet with the entire string S for (char c : S) { rightFreq[c]++; rightSet.insert(c); } int maxX = 0; // Traverse the string and adjust the left and right sets and maps for (int i = 0; i < n - 1; ++i) { char c = S[i]; leftFreq[c]++; rightFreq[c]--; if (rightFreq[c] == 0) { rightSet.erase(c); } leftSet.insert(c); int currentSum = leftSet.size() + rightSet.size(); maxX = max(maxX, currentSum); } return n - maxX; Infosys ✅ Fully passed Split string ✅✅

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Shortest string

14 088

Done first ✅✅✅✅

14 088

Make it 12k

14 088

Gys share FAstt

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long long solve(int n,vector<int>v){ long long ans=0; sort(v.begin(),v.end()); for(int i=1;i<n;i++){ if(v[i]<=v[i-1]){ v[i]=v[i-1]+1; } } ans=accumulate(v.begin(),v.end(),0); return ans; } Minimum unique sum✅ Infosys ( Full passed ✅✅ Share @codeing_area

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Guys, Make it 12k .. after 12 k I will send sloution

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Next sloution After 12k I will uploaded ✅✅

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#include <bits/stdc++.h> using namespace std; int equalzeroandone(vector<int>v){ int n=v.size(); for(int i=0;i<n;i++){ if(v[i]==0){ v[i]=-1; } } int sum=0; int ans=-1; map<int,int>mp; for(int i=0;i<n;i++){ sum+=v[i]; if(sum==0){ ans=i+1; } if(mp.find(sum)!=mp.end()){ ans=max(ans,i-mp[sum]); } else{ mp[sum]=i; } } return ans; } int main() { int n; cin>>n; vector<int>v(n); for(int i=0;i<n;i++){ cin>>v[i]; } cout<<equalzeroandone(v); } Equal no of zero and one(Infosys) Full passed ✅✅ Shared @codeing_area

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Share with your Friends and in Big groups we will definitely post answers here We will Try to share Some answers Here also in our Groups. So must Join 1) @codeing_area 2) @codeing_area 3) @codeing_area

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Accenture hackdivaa slot available ✅ Contact fast and book your slots ✅ Contact @srksvk Remote access available 🔥🥇🥇 200% suree clearance guarantee ✅🔥🔥 Priviously helped 👇👇👇 https://t.me/codeing_area/7643?single https://t.me/codeing_area/8059?single

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Now slot open 7 July Infosys sp 1 slot available ✅ Contact fast and book your slots ✅ @srksvk 200% suree clearance guarantee nd Remote access available 🔥

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Infosys sp exam help successfully done by remote access ✅✅ 3/3 code fully passed ✅✅✅ 🔥🔥🔥 Contact for placement exam @srksvk

14 088

Guys we are upload all code passed .. but no one sharing group

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#include <bits/stdc++.h> #define ll long long using namespace std; ll solve(string s1, string s2) { ll m = s1.length(); ll n = s2.length(); vector<vector<ll>>dp(m+1,vector<ll>(n + 1)); for (ll i=1;i<= m;i++) { dp[i][0]=i; } for (ll j = 1; j <= n;j++) { dp[0][j] = j; } for (ll i = 1; i <= m; ++i) { for (ll j = 1; j <= n; ++j) { if (s1[i - 1] == s2[j - 1]) { dp[i][j] = dp[i - 1][j - 1]; } else { dp[i][j] = 1 + min(dp[i - 1][j], dp[i][j - 1]); if (i > 1 && j > 1 && s1[i - 1] == s2[j - 2]) { dp[i][j] = min(dp[i][j], 1 + dp[i - 1][j - 2]); } if (i > 1 && j > 1 && s1[i - 2] == s2[j - 1]) { dp[i][j] = min(dp[i][j], 1 + dp[i - 2][j - 1]); } } } } return dp[m][n]; } signed main() { string s1,s2; cin>>s1>>s2; cout<<solve(s1,s2)<<endl; return 0; } String operation. Just paste it

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Guys we are upload all code passed pic ... but no one sharing group

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Don't forget share the group @codeing_arra