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#include <stdio.h>
int main()
{
int i, j, N;
scanf("%d", &N);
for(i=1; i<=N; i++)
{
for(j=1; j<i; j++)
{
printf(" ");
}
printf("%d", i);
for(j=1; j<=((N - i) * 2 - 1); j++)
{
printf(" ");
}
if(i != N)
printf("%d", i);
printf("\n");
}
for(i=N-1; i>=1; i--)
{
for(j=1; j<i; j++)
{
printf(" ");
}
printf("%d", i);
for(j=1; j<=((N - i ) * 2 - 1); j++)
{
printf(" ");
}
printf("%d", i);
printf("\n");
}
return 0;
}
X pattern c code
Share this screen shot
to ur frdss..
I will post remining solutions...fast..💥💥
def sq(matrix, l_x, l_y,side_length):
count=0
for i in range(l_x,l_x+side_length):
for j in range(l_y,l_y+side_length):
if matrix[i][j]==1:
count +=1
else:
return 0
return count
m,n=map(int,input().split())
mark={'X':1,'O':0}
matrix=[[mark[i] for i in input().split()]for _ in range(m)]
Vikram=[]
for l_x in range(m):
for l_y in range(n):
for side_length in range(1,min(n- l_y+1,m- l_x+1)):
Vikram.append(sq(matrix,l_x,l_y,side_length))
print(max(vikram))
Vikram ans L2 IDP ✅
share our channel to ur frds ..✅✅😁
who want ans for l1 and l2
Just share our channel frdss✅💥💥 @Coding_000
share.....@ILOVEU_143
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IDP L2 join this ...share ur questions...
👇👇
https://t.me/idpcoding000
L1 join this...share ur questions
https://t.me/exams_discussion
✅✅ share our channel
Share your questions in this groups..😊
All the best...for everyone..✅
I will help you just share our channel guys...add ur frdss✅👍
Who have tmr IDP L1 or L2
Comment below..👇👇
@Coding_000
and share our channel to ur frds add your frds😁😊
Who have tmr IDP L1 or L2
comment below..
@Coding_000
and share our channel to ur frds add your frds😁😊
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