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Hi everyone!
It takes a lot of work to find and share useful opportunities every day. Can you help me by telling your college friends about our channel. Your support keeps me going and encourages me to share more opportunities. Just taking a few seconds to spread the word can make a big difference!
Thanks a lot😊🌟
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Job Updates:
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Share above all channels to your friends 😍✅✅
How many of u 2024 Batch
Join below 👇👇 and share to Ur friends 😊😊
https://t.me/Coding_2024
https://t.me/Coding_2024
https://t.me/Coding_2024
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Team @Coding_000❤️
Repost from WhiteHat Coding
Meesho Answer PDF
Round 1 All Answers with quesMeesho Screening Test All Details:
You need to login using your registered email id and mobile number on NextLevel App and upload resume in that app. After that you can give the test on NextLevel App.
Camera and Mic will be ON.
You can give your test using your Smart Phone.
This test is like an AI screening in which AI is used to ask you questions and you have to answer the questions verbally similar to interviews.
Questions like, what is polymorphism, time complexity of merge sort etc.
You have to answer them verbally like an interview.
Topics: OOPS, Operating Systems, Data Structures, Algorithms, DBMS, Networking, Error Handling,
There will be MCQ based questions, Answer based questions and output based questions.
Sequential and concept wise questions will be asked.
Don’t do any mistake like moving away your face out of camera (screen) during AI Interview, etc. else your test will be auto submitted.
There will be in total 30 minutes for 26 questions.
Particular time is allotted for each question.✅
All the best .😊 Share @coding_000❤️Repost from WhiteHat Coding
Meesho Answer PDF
Round 1 All Answers with quesHow many Of u writing IBM EXam Today ? Give reactions....❤️
Based on reactions i will help...✅
How many u have IBM TODAY...?
Hit like..👍👍
string solve(string bs) {
map nb = {
{"001", "C"},
{"010", "G"},
{"011", "A"},
{"101", "T"},
{"110", "U"},
{"000", "DNA"},
{"111", "RNA"}
};
string ds = "";
string t = nb[bs.substr(0, 3)];
for(int i = 3; i < bs.length(); i += 3) {
string b = bs.substr(i, 3);
if(nb.find(b) != nb.end()) {
string x = nb[b];
if(t == "DNA" && x == "U") {
x = "T";
}
ds += x;
} else {
ds += "Error";
}
}
return ds;
}
DNA✅
IBM
fill all details 😅
and press login button at :5-08
Guys share and be ready...😊
Exactly -5:08 u need to click login button 👍👍✅
IBM 👇👇
All of u login At - > 05:08 pm before 05-10✅
Share @Coding_000❤️😊
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