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consequtive number code -python✅

Consecutive numbers in an array -java ✅✅

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maximum product

int Children = 0,Adult = 0;         for(int i=0;i

class Solution:     def intersect(self, nums1: List[int], nums2: List[int]) -> List[int]:         dict1 = dict()         for i in nums1:             if i not in dict1:                 dict1[i] = 1             else: @Coding_000                 dict1[i] += 1         ret = []         for i in nums2:             if i in dict1 and dict1[i]>0:                 ret.append(i)                 dict1[i] -= 1         return ret Python QualiTlabs Fresher Hiring 1st Question Telegram:- @Coding_000

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def cond1(s):       for i in range(len(s) - 2):         if (s[i] == s[i + 1] and             s[i + 1] == s[i + 2]):             return True           return False def cond2(s):     for i in range(len(s) - 2):         if ((s[i] < s[i + 1] and              s[i + 1] < s[i + 2]) or             (s[i] > s[i + 1] and              s[i + 1] > s[i + 2])):             return True           return False def cond3(s):     a = [0] * 10     for i in range(len(s)):         a[s[i] - '0'] = a[s[i] - '0'] + 1           for i in range(len(9)):               if (a[i] >= 4):             return True           return False   def isFancy(s):     if (cond1(s) or cond2(s) or cond3(s)):         return True     else:         return False s = input(“ “) if (isFancy(s)):     print("Yes") else:     print("No") Language: Python3

class Solution:     def intersect(self, nums1: List[int], nums2: List[int]) -> List[int]:         dict1 = dict()         for i in nums1:             if i not in dict1:                 dict1[i] = 1             else:                 dict1[i] += 1         ret = []         for i in nums2:             if i in dict1 and dict1[i]>0:                 ret.append(i)                 dict1[i] -= 1         return ret Python3

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