ASHCHARYA BANSAL

Many many congratulations AIR1 From MADE EASY Delhi Sultanpur batch

GATE results are around the corner! Take a deep breath, stay calm, and remember all the efforts you've put in. Believe in yourself, and know that you've got this! Best of luck, and may your dreams take flight!

TIME AND DISTANCE Question no 1 A train travels from station A to station B at an average speed of 50 km/h and returns back to station A at an average speed of 40 km/h. What is the average speed of the train for the entire journey? Options A) 44.4 km/h B) 45.4 km/h C) 46.4 km/h D) 44 km/h Solution To find the average speed, we need to find the total distance traveled and the total time taken. Let's assume the distance between station A and station B is x km. Time taken to travel from A to B = x / 50 Time taken to travel from B to A = x / 40 Total time taken = x / 50 + x / 40 = (4x + 5x) / 200 = 9x / 200 Total distance traveled = 2x Average speed = Total distance traveled / Total time taken = 2x / (9x / 200) = 400 / 9 = 44.4 km/h The correct answer is A) 44.4 km/h. Question no 2 A car travels from city A to city B at an average speed of 60 km/h and returns back to city A at an average speed of 40 km/h. What is the average speed of the car for the entire journey? Options A) 48 km/h B) 50 km/h C) 52 km/h D) 54 km/h Solution To find the average speed, we need to find the total distance traveled and the total time taken. Let's assume the distance between city A and city B is x km. Time taken to travel from A to B = x / 60 Time taken to travel from B to A = x / 40 Total time taken = x / 60 + x / 40 = (2x + 3x) / 120 = 5x / 120 Total distance traveled = 2x Average speed = Total distance traveled / Total time taken = 2x / (5x / 120) = 240 / 5 = 48 km/h The correct answer is A) 48 km/h. Question no 3 A bus travels from town A to town B at an average speed of 40 km/h. On the return journey, the bus travels at an average speed of 60 km/h. What is the average speed of the bus for the entire journey? Options A) 48 km/h B) 50 km/h C) 52 km/h D) 54 km/h Solution To find the average speed, we need to find the total distance traveled and the total time taken. Let's assume the distance between town A and town B is x km. Time taken to travel from A to B = x / 40 Time taken to travel from B to A = x / 60 Total time taken = x / 40 + x / 60 = (3x + 2x) / 120 = 5x / 120 Total distance traveled = 2x Average speed = Total distance traveled / Total time taken = 2x / (5x / 120) = 240 / 5 = 48 km/h The correct answer is A) 48 km/h. Question no 4 A cyclist travels from city A to city B at an average speed of 20 km/h. On the return journey, the cyclist travels at an average speed of 30 km/h. What is the average speed of the cyclist for the entire journey? Options A) 24 km/h B) 25 km/h C) 26 km/h D) 27 km/h Solution To find the average speed, we need to find the total distance traveled and the total time taken. Let's assume the distance between city A and city B is x km. Time taken to travel from A to B = x / 20 Time taken to travel from B to A = x / 30 Total time taken = x / 20 + x / 30 = (3x + 2x) / 60 = 5x / 60 Total distance traveled = 2x Average speed = Total distance traveled / Total time taken = 2x / (5x / 60) = 120 / 5 = 24 km/h The correct answer is A) 24 km/h.

Important practice questions from the Percentage chapter 1. Question A shopkeeper sells a article at a profit of 20%. If the cost price of the article is Rs. 100, what is the selling price of the article? # Options A) Rs. 120 B) Rs. 110 C) Rs. 130 D) Rs. 140 Solution To find the selling price, we need to calculate 20% of the cost price and add it to the cost price. Cost price = Rs. 100 Profit percentage = 20% Profit amount = 20% of Rs. 100 = (20/100) × 100 = Rs. 20 Selling price = Cost price + Profit amount = Rs. 100 + Rs. 20 = Rs. 120 The correct answer is A) Rs. 120. 2. Question A student scored 80 marks out of 100 in a test. What percentage of marks did the student score? # Options A) 70% B) 75% C) 80% D) 85% Solution To find the percentage, we need to divide the marks scored by the total marks and multiply by 100. Marks scored = 80 Total marks = 100 Percentage = (Marks scored ÷ Total marks) × 100 = (80 ÷ 100) × 100 = 80% The correct answer is C) 80%. 3. Question A company's profit increases by 15% every year. If the company's profit is Rs. 100 in the first year, what will be the profit in the third year? Options A) Rs. 128.75 B) Rs. 138.75 C) Rs. 148.75 D) Rs. 158.75 Solution To find the profit in the third year, we need to calculate the profit for each year and add it to the previous year's profit. Year 1: Profit = Rs. 100 Year 2: Profit = Rs. 100 + 15% of Rs. 100 = Rs. 100 + Rs. 15 = Rs. 115 Year 3: Profit = Rs. 115 + 15% of Rs. 115 = Rs. 115 + Rs. 17.25 = Rs. 132.25 However, the closest option is A) Rs. 128.75. 4. Question A person's salary is reduced by 10%. If the person's original salary is Rs. 50,000, what is the reduced salary? Options A) Rs. 45,000 B) Rs. 40,000 C) Rs. 35,000 D) Rs. 30,000 Solution To find the reduced salary, we need to calculate 10% of the original salary and subtract it from the original salary. Original salary = Rs. 50,000 Reduction percentage = 10% Reduction amount = 10% of Rs. 50,000 = (10/100) × 50,000 = Rs. 5,000 Reduced salary = Original salary - Reduction amount = Rs. 50,000 - Rs. 5,000 = Rs. 45,000 The correct answer is A) Rs. 45,000. 5. Question A student scored 90 marks out of 120 in a test. What percentage of marks did the student score? Options A) 70% B) 75% C) 80% D) 85% Solution To find the percentage, we need to divide the marks scored by the total marks and multiply by 100. Marks scored = 90 Total marks = 120 Percentage = (Marks scored ÷ Total marks) × 100 = (90 ÷ 120) × 100 = 75% The correct answer is B 75%.

IMPORTANT questions for RRB NTPC exam Mathematics along with full solutions: 1. Simplification Question: Simplify: 3/5 × 5/7 × 7/9 Solution: 3/5 × 5/7 × 7/9 = 1/3 2. Percentage Question: A shopkeeper sells an article at a profit of 20%. If the cost price of the article is Rs. 100, what is the selling price of the article? Solution: Selling price = Cost price + Profit = Rs. 100 + 20% of Rs. 100 = Rs. 120 3. Ratio and Proportion Question: If 2:3::4:x, then what is the value of x? Solution: 2/3 = 4/x ⇒ x = 6 4. Time and Work Question: A can do a piece of work in 10 days, B can do the same work in 15 days. In how many days can A and B together complete the work? Solution: 1 day's work of A = 1/10, 1 day's work of B = 1/15. Combined 1 day's work = 1/10 + 1/15 = 1/6. So, A and B together can complete the work in 6 days. 5. Average Question: The average of 10 numbers is 20. If 5 is added to each number, what is the new average? Solution: New average = Old average + 5 = 20 + 5 = 25 6. Number System Question: What is the greatest number that divides 75, 90 and 105 without leaving a remainder? Solution: Factors of 75 = 1, 3, 5, 15, 25, 75. Factors of 90 = 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90. Factors of 105 = 1, 3, 5, 7, 15, 21, 35, 105. The greatest number that divides all three numbers is 15. 7. Profit and Loss Question: A shopkeeper sells an article at a loss of 20%. If the selling price of the article is Rs. 80, what is the cost price of the article? Solution: Cost price = Selling price / (1 - Loss%) = Rs. 80 / (1 - 0.20) = Rs. 100 8. Time and Distance Question: A train travels from station A to station B at an average speed of 50 km/h and returns back to station A at an average speed of 40 km/h. What is the average speed of the train for the entire journey? Solution: Average speed = (2 × 50 × 40) / (50 + 40) = 44.4 km/h 9. Geometry Question: What is the area of a triangle whose base is 5 cm and height is 6 cm? Solution: Area of triangle = (1/2) × base × height = (1/2) × 5 × 6 = 15 cm² 10. Data Interpretation Question: The following table shows the number of students in a class who scored marks in different ranges in a mathematics test: | Marks Range | Number of Students | | --- | --- | | 0-10 | 5 | | 11-20 | 10 | | 21-30 | 15 | | 31-40 | 20 | | 41-50 | 10 | What is the average marks scored by the students in the class? Solution: Total marks = (5 × 5) + (10 × 15) + (15 × 25) + (20 × 35) + (10 × 45) = 25 + 150 + 375 + 700 + 450 = 1700. Total number of students = 5 + 10 + 15 + 20 + 10 = 60. Average marks = Total marks / Total number of students = 1700 / 60 = 28.33 11. Mensuration Question: What is the volume of a cube whose side is 6 cm? Solution: Volume of cube = side³ = 6³ = 216 cm³ 12. Algebra Question: Solve the equation: 2x + 5 = 11 Solution: 2x = 11 - 5 ⇒ 2x = 6 ⇒ x = 3

BDL INTERVIEW EXPERIENCE

BDL INTERVIEW EXPERIENCE

Those who have already appeared in interviews of BDL BARC AAI PLS SHARE YOUR INTERVIEW EXPERIENCE on my Whats app 9205326638

Good Evening Sir, sorry for such late reply. By your blessings, I am doing good. 🙏 Sir I am working as a Management Trainee in BDL. There are currently 3 units of BDL - Vishakhapatnam, Hyderabad, Bhanur (40km near Hyderabad). I am in Hyderabad unit. People can be posted in any of these three units based on the manpower requirements. I got posted to Hyderabad. Sir, Bdl mainly manufactures missiles designed by DRDO as well as on Transfer of Technology from foreign companies. It also has a R&D division , in Hyderabad unit, which focuses on developing missile designed by BDL itself. I am currently working in this R&D division. There is a lot to learn technically here as different defense projects keep coming. Here, mechanical engineers will work on CAD modelling, CFD simulations, Structural simulations, QC, materials management etc. I work on Cfd simulation currently. Being a defense Psu, there are however many restrictions. Phones not allowed, internet access very restricted. Also office timings are fixed ( 8am to 4.40am ) as biometric attendance is there.

BDL INTERVIEW EXPERIENCE Good Afternoon Sir, Here is my overall experience for BDL MT (Mechanical) held on 15 June 2023, Hyderabad. 1. They asked for my brief introduction and to mention briefly about summer training / project / experience etc. 2. Asked to explain in brief about industrial training and my M.Tech Thesis work. 4. Asked lot of details about my job profile in the previous company (IT sector). Asked why I joined IT sector after Mechanical engg, and why going for core sector now. Asked details of any other exam I cleared. 5. Asked different types of manufacturing processes. 6. Asked about factors to keep in mind while designing any component, an give an example. I gave example of Flywheel design. Then they asked purpose of Flywheel. 7. What is the significance of studying Engineering Drawing and Graphics 8. They asked basic questions ob Subjects studied in MTech. 9. I had done some elective subjects from humanities stream in college. They asked about one of them in detail. The total interview lasted about 9-10 minutes. Some questions asked to other candidates were focused on production , as BDL is a production company for missiles and related equipment for indian armed forces. But basic mechanical questions were also asked from other subjects like quality, solid mechanics, theory of machines. As BDL mainly manufactures for defense forces, it will be good to know recent news of this field. Also visit BDL website to know their missile products, key people in company, recent news about BDL etc.

Sir I did following for my preparation: 1. Went through website of BDL. 2. Prepared HR/Technical questions based on my profile - my college Projects, M.tech, Job experience. 3. Studied basics of all subjects with focus on conceptual topics. 4. Went through your Telegram channel to find Technical/HR questions of other interviews.

Good Afternoon Sir, Here is my overall experience for BDL MT (Mechanical) held on 15 June 2023, Hyderabad. 1. They asked for my brief introduction and to mention briefly about summer training / project / experience etc. 2. Asked to explain in brief about industrial training and my M.Tech Thesis work. 4. Asked lot of details about my job profile in the previous company (IT sector). Asked why I joined IT sector after Mechanical engg, and why going for core sector now. Asked details of any other exam I cleared. 5. Asked different types of manufacturing processes. 6. Asked about factors to keep in mind while designing any component, an give an example. I gave example of Flywheel design. Then they asked purpose of Flywheel. 7. What is the significance of studying Engineering Drawing and Graphics 8. They asked basic questions ob Subjects studied in MTech. 9. I had done some elective subjects from humanities stream in college. They asked about one of them in detail. Total interview lasted about 10-12 minutes.

Sir,do PSU exams like BHEL & BDL have calculators?

Shared some question for BHEL EXAM ALSO

*Strategies for Success in PSU Exams (ONGC, BHEL, etc.)* To excel in PSU exams, focus on the following key areas: 1. *Speed*: PSU exams are distinct from GATE exams. With less than 60 seconds per question and no calculator allowed, speed is crucial. Practice solving questions without a calculator and within a set time frame (e.g., 50 questions in 50 minutes). 2. *Theoretical Questions*: PSU/ESE prelims exams emphasize theoretical questions. Focus on building a strong foundation in mechanical engineering concepts. 3. *Practice with Previous Year Questions*: Solve previous year questions from GATE, ESE, R.K. Jain, and Y.C.T. books to familiarize yourself with the exam pattern and question types. 4. *Aptitude and Reasoning Shortcuts*: Develop shortcuts for aptitude and reasoning questions, as time is limited in PSU exams. 5. *General Studies and English*: Some PSU exams include basic questions from General Studies and English. Prepare accordingly to avoid losing marks in these sections. By following these strategies and practicing consistently, you'll be well-prepared to tackle PSU exams. Best wishes!

Bhel diploma related query