Codeforces|Leetcode|Codechef free solutions

void solve() { int a, b, n, m; cin >> a >> b >> n >> m; int x = b * n; int y = a * (n / (m + 1)) * m; y += min(n % (m + 1) * a, n % (m + 1) * b); cout << min(y, x) << endl; } signed main() { rd(t); while (t--) {   solve(); } return 0; }

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Right b code

Codeforces B solution🥳🥳🥳

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