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GeeksForGeeks - POTD | GFG POTD Answer

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7th July : C++ Solution ☝🏼

class Solution{ public: //Function to merge the arrays. void merge(long long arr1[], long long arr2[], int n, int m) { int end=n-1; //take end as first array last element int start=0; //start as a first element while(end>=0&&startarr2[start]) //swap to store the all smallest number in the first array swap(arr1[end--],arr2[start++]); else break; } sort(arr1,arr1+n); //sort the all stored small and the large numbers in the both arrays sort(arr2,arr2+m); } };

6th July : C++ Solution ☝🏼

class Solution { public: //Function to sort an array using a quick sort algorithm. void quickSort(int arr[], int low, int high) { if(low < high) { // It gives the correct position for the partition of the array because //The element at this position has smaller elements before it and bigger elements after it int partition_point = partition(arr, low, high); // repeating the same process to sort the smaller elements before partition_point quickSort(arr, low, partition_point - 1); // repeating the same process to sort the bigger elements after partition_point quickSort(arr, partition_point + 1, high); } } public: int partition (int arr[], int low, int high) { //Taking the last element as a pivot int pivot = arr[high]; int j = low - 1; // in this loop smaller elements are placed at starting for(int i = low;i <= high-1; i++) { if(arr[i] < pivot) { j++; // increase the j value when an element is less than the pivot then swap(arr[i],arr[j]); // swap this element to the jth position } } swap(arr[j + 1],arr[high]); // placing the pivot after all the elements smaller than it return j+1; // return the current position of the pivot } };

5th July : C++ Solution ☝🏼

class Solution { public: int stockBuyAndSell(int n, vector &prices) { // code here int ans=0; //set ans variable to store the ans for(int i=0;i

4th July : C++ Solution ☝🏼

class Solution{ public: int countSubArrayProductLessThanK(const vector& a, int n, long long k) { int count = 0; long long int product = 1; int j = 0; for(int i = 0; i < n; i++) { product *= a[i]; while(product >= k && j <= i) { product /= a[j]; j++; } count += (i-j+1); } return count; } };

3rd July : C++ Solution ☝🏼

class Solution{ public: int maxIndexDiff(int arr[], int n) { int i=0; int j=n-1; int diff = 0; while(i

2nd July : C++ Solution ☝🏼

class Solution{ public: int setSetBit(int x, int y, int l, int r){ int temp = 0; for(int pos = l ; pos <= r ; pos++) { if(1 & ( y >> (pos - 1))) { temp = temp | (1 << ( pos - 1)); } } x |= temp; return x; } };

1st July : C++ Solution ☝🏼

class Solution { public: int setBits(int N) { int cnt = 0; while(N){ cnt += (N & 1); N >>= 1; } return cnt; } };

30th June : C++ Solution ☝🏼

class Solution{ public: int isDivisible(string s){ int c=0; int x=1; for(int i=s.size()-1;i>=0;i--) { if(s[i]=='1') c+=x; x=(x==1)?2:1; } return (c%3==0)?1:0; } };

29th June : C++ Solution ☝🏼

class Solution{ public: int nextHappy(int N){ for (int i = N + 1; i < 1000000; i++) { int count = 0; int temp = i; int sum = 0; while (temp) { int r = temp % 10; sum += r * r; temp /= 10; if (sum == 1 && temp == 0) { return i; } if (sum != 0 && temp == 0) { temp = sum; sum = 0; } if (count > 50) { break; } count++; } } } };

Eid-ul-Adha Mubarak ❀️✨ To All Geeks !
Eid-ul-Adha Mubarak ❀️✨ To All Geeks !