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AJAKS TUTORIALS OFFICIAL 🌏πŸ”₯

AJAKS TUTORIALS OFFICIAL 🌏πŸ”₯

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My wonderful subscribers , welcome to Ajaks Tutorials official telegram channel. Ajaks Tutorials is an online Tutorial centered at grooming SSCE , UTME and POST UTME candidates. We are CAC registered (RC : 68855317) https://taplink.cc/ajakstutorials

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πŸ“ˆ Analytical overview of Telegram channel AJAKS TUTORIALS OFFICIAL 🌏πŸ”₯

Channel AJAKS TUTORIALS OFFICIAL 🌏πŸ”₯ (@ajakstutorials) in the English language segment is an active participant. Currently, the community unites 13 532 subscribers, ranking 14 175 in the Education category and 58 874 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 13 532 subscribers.

According to the latest data from 08 September, 2024, the channel demonstrates stable activity. Although there has been a change in the number of participants by 0 over the last 30 days and by 0 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 6.96%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œMy wonderful subscribers , welcome to Ajaks Tutorials official telegram channel. Ajaks Tutorials is an online Tutorial centered at grooming SSCE , UTME and POST UTME candidates. We are CAC registered (RC : 68855317) https://taplink.cc/ajakstutoria...”

Thanks to the high frequency of updates (latest data received on 18 March, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

13 532
Subscribers
No data24 hours
No data7 days
No data30 days
Posts Archive
SOLUTION Horizontal component of the tension ,Fx= 300cos60⁰ = 150⁰ Net force(the effective force doing the work on the box) =Fx - frictional force =150-100 =50⁰ Work done= Net force Γ—distance = 50Γ—4 = 200J

316/400 SECURED BY AJAKS TUTORIALS🀩πŸ”₯πŸ”₯ Congratulations Ajakite Osamudiamen!❀️❀️ Now we have 80 students and still counting
316/400 SECURED BY AJAKS TUTORIALS🀩πŸ”₯πŸ”₯ Congratulations Ajakite Osamudiamen!❀️❀️ Now we have 80 students and still counting with 300+ in Ajaks Tutorials!! Who de breathe??πŸ˜‚πŸ”₯πŸ”₯

Congratulations Ajakite Bright🀩πŸ”₯ 305/400 secured!πŸ”₯ Making it 79 students with 300+ in Ajaks Tutorials😌πŸ”₯ And counting!!!!
Congratulations Ajakite Bright🀩πŸ”₯ 305/400 secured!πŸ”₯ Making it 79 students with 300+ in Ajaks Tutorials😌πŸ”₯ And counting!!!!

POST UTME DAILY BIOLOGY DRILLS A tall plant crossed with a dwarf one produce offsprings of which half are tall and half are dwarf. What are the genotypes of the parents?
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A tall plant crossed with a dwarf one produce offsprings of which half are tall and half are dwarf. What are the genotypes of the parents?
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Ajaks Tutorials 2024 JAMB current top scorers status 1st position - 363/400 2nd position - 352/400 3rd position - 350/400 4th position - 349/400 5th position - 348/400 6th position - 347/400 6th position - 347/400 7th position - 346/400 8th position - 343/400 9 students with 340+πŸ”₯ We have solid results, end of story!

Two brothers from Ajaks TutorialsπŸ˜‚ Omhokhai Jeremiah - 352/400 Omhokhai Joshua - 347/400 Stop playing!!!!πŸ˜‚πŸ˜‚πŸ”₯πŸ”₯ We current
Two brothers from Ajaks TutorialsπŸ˜‚ Omhokhai Jeremiah - 352/400 Omhokhai Joshua - 347/400 Stop playing!!!!πŸ˜‚πŸ˜‚πŸ”₯πŸ”₯ We currently have 78 students with 300+ and counting!! Relax, more loading!!!!πŸ˜‚

JAMB RESULTS FOR THOSE THAT COULDN'T CHECK IS NOW OUT!πŸ”₯πŸ˜‚ Ajakite Bryant Just started my morning with a wonderful results!πŸ”₯
JAMB RESULTS FOR THOSE THAT COULDN'T CHECK IS NOW OUT!πŸ”₯πŸ˜‚ Ajakite Bryant Just started my morning with a wonderful results!πŸ”₯πŸ”₯ 348/400 added to the list of 2024 top Ajakites🀩🀩 Now we have 76 students with 300+ and counting!πŸ”₯ This is Ajaks Tutorials πŸ’ͺπŸ’ͺ

POST UTME DAILY PHYSICS DRILLS
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POST UTME DAILY PHYSICS DRILLS A box of mass 40kg is being dragged along by a rope inclined at 60⁰ to the horizontal. The frictional force between the box and floor is 100N and the tension on the rope is 300N .How much work is done in dragging the box through a distance of 4m?

POST UTME DAILY MATHEMATICS DRILLS A bucket is 20cm in diameter at the open end and 12cm in diameter at the bottom and 15cm deep. What is the capacity of the bucket in litres?(Ο€=3.142)
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POST UTME DAILY ENGLISH DRILLS Aishat had an _ shock when she discovered that she had married a gambler.
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POST UTME DAILY CHEMISTRY DRILLS The greenhouse effect is a climatic condition associated with the presence of excess
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POST UTME DAILY G.K DRILLS Which of these animals is not a member of dog family?
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Intensive classes in Ajaks Tutorials continues today and I'm here to respond to some questions you might have!πŸ”₯πŸ”₯ Q1: When I
Intensive classes in Ajaks Tutorials continues today and I'm here to respond to some questions you might have!πŸ”₯πŸ”₯ Q1: When I enroll, will I have access to every single thing I've missed? A : Definitely Yes, you will as classes holds on Telegram so you'll be able to access previous class notes and questions Q2 : Can I pay in bits? A : No you can't, calmly save up the full ₦6,000 and make payments. Q3 : If I pay today, when will payment expire? A : It is ₦6,000 monthly so simply add 1 month to your data of payment, which is July 25th!πŸ”₯ You have more questions to ask? Make enquiries here : https://wa.me/2348106283215?text You want to make payments? https://wa.me/2348106283215?text=Good+day+Ajaks+I+want+to+make+payment+for+the+2024+post+UTME+tutorials+can+I+have+your+account+details

SOLUTION dA/dt =1.5 dr/dt =? dr/dt =dA/dt Γ—dr/dA A=Ο€rΒ² 2=Ο€rΒ² r=0.7978 From A=Ο€rΒ² dA/dr =2Ο€r dr/dA =1/2Ο€r dr/dt =dA/dt Γ— dr/dA = 1.5 Γ—1/(2Γ—3.142Γ—0.7978) =0.29939 =0.299 to 3s.f

Some of them go chose Darwin now πŸŒšπŸ˜‚

POST UTME DAILY BIOLOGY DRILLS The theory that new organs or characteristics develop in organisms when there is a need for them was postulated by
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INTENSIVE CLASSES CONTINUES TODAY!πŸ’ͺ If you haven’t made payment yet, it’s you that sabi oh! 🌚 Don’t lower your aura by miss
INTENSIVE CLASSES CONTINUES TODAY!πŸ’ͺ If you haven’t made payment yet, it’s you that sabi oh! 🌚 Don’t lower your aura by missing that admission you’ve wanted! The price is just #6,000. Let’s make 2024 your year! 😌πŸ”₯ Make payments hereπŸ‘‡πŸ‘‡ https://wa.me/2348106283215?text=Good+day+Ajaks+I+want+to+make+payment+for+the+2024+post+UTME+tutorials+can+I+have+your+account+details