Tech Track T1 - T15💻

# Python3 code for Maximum size # square sub-matrix with all 1s def printMaxSubSquare(M): R = len(M) # no. of rows in M[][] C = len(M[0]) # no. of columns in M[][] S = [] for i in range(R): temp = [] for j in range(C): if i==0 or j==0: temp += M[i][j], else: temp += 0, S += temp, # here we have set the first row and first column of S same as input matrix, other entries are set to 0 # Update other entries for i in range(1, R): for j in range(1, C): if (M[i][j] == 1): S[i][j] = min(S[i][j-1], S[i-1][j], S[i-1][j-1]) + 1 else: S[i][j] = 0 # Find the maximum entry and # indices of maximum entry in S[][] max_of_s = S[0][0] max_i = 0 max_j = 0 for i in range(R): for j in range(C): if (max_of_s < S[i][j]): max_of_s = S[i][j] max_i = i max_j = j print("Maximum size sub-matrix is: ") for i in range(max_i, max_i - max_of_s, -1): for j in range(max_j, max_j - max_of_s, -1): print (M[i][j], end = " ") print("") # Driver Program M = [[0, 1, 1, 0, 1], [1, 1, 0, 1, 0], [0, 1, 1, 1, 0], [1, 1, 1, 1, 0], [1, 1, 1, 1, 1], [0, 0, 0, 0, 0]] printMaxSubSquare(M)

# Python3 code for Maximum size # square sub-matrix with all 1s def printMaxSubSquare(M): R = len(M) # no. of rows in M[][] C = len(M[0]) # no. of columns in M[][] S = [] for i in range(R): temp = [] for j in range(C): if i==0 or j==0: temp += M[i][j], else: temp += 0, S += temp, # here we have set the first row and first column of S same as input matrix, other entries are set to 0 # Update other entries for i in range(1, R): for j in range(1, C): if (M[i][j] == 1): S[i][j] = min(S[i][j-1], S[i-1][j], S[i-1][j-1]) + 1 else: S[i][j] = 0 # Find the maximum entry and # indices of maximum entry in S[][] max_of_s = S[0][0] max_i = 0 max_j = 0 for i in range(R): for j in range(C): if (max_of_s < S[i][j]): max_of_s = S[i][j] max_i = i max_j = j print("Maximum size sub-matrix is: ") for i in range(max_i, max_i - max_of_s, -1): for j in range(max_j, max_j - max_of_s, -1): print (M[i][j], end = " ") print("") # Driver Program M = [[0, 1, 1, 0, 1], [1, 1, 0, 1, 0], [0, 1, 1, 1, 0], [1, 1, 1, 1, 0], [1, 1, 1, 1, 1], [0, 0, 0, 0, 0]] printMaxSubSquare(M)

Iteration tools 800 Pd.read_csv(get.put(4)) Programming language Numpy.get_error(50) Random.randint(100) Seaborn graph Pie.plot.append(corner=left) Combination.itertools(df.scale())

Next slot 2 in this group 😊 @TCS_DIGITAL_UPDATES

Slot 3 and slot 4 will i cover in this group due to personal reason I'm not covering this slot 2.

TCS DCA python Slot 1 : @TCS_DIGITAL_UPDATES Q) you want to open a text file Ans) r Q) which command is used to print a text.... Ans) plt.annotate() Q) you are give a list of cities Ans) len(cities) Q) how will you save an array in CSV format Ans)pd.save_Csv('number.csv',num, delimiter ="\t" Q) which code snippet would help us Ans) np.ones(4,4) Q) order of operations plays a vital role Ans)((-4)**2)+4 @TCS_DIGITAL_UPDATES Q) you are doing exploratory analysis Ans) scatter plot Q) which command you will use to check the python version Ans) python -v Q) A variable named 'savings: Ans) 800 Q) which keyword we used as a 'no-operation' Ans)pass Q) How to write the given function in one line code Ans) square = [i*i for i in range(10)] Q) you have data frame of shape (140,10) Ans) 35,10 Q) There is a special name of function these type... Ans) Recursive function Q) what will be the following output code ? Result = Lambda x,y,z Ans) 8 Q) In the employees"Performance chart' Ans) ax.barh(people, performance,xerr = error,align='right' @TCS_DIGITAL_UPDATES Q) you are working on the weather forecast data Ans)6,3 @TCS_DIGITAL_UPDATES Q) you have been asked to do certain calculations Ans)pd.to_date('today')-record['year_born] @TCS_DIGITAL_UPDATES

Free advice : change variable, function names to be plagiarism free.

TCS DCA python Slot 1 : Q) you want to open a text file Ans) r Q) which command is used to print a text.... Ans) plt.annotate() Q) you are give a list of cities Ans) len(cities) Q) how will you save an array in CSV format Ans)pd.save_Csv('number.csv',num, delimiter ="\t" Q) which code snippet would help us Ans) np.ones(4,4) Q) order of operations plays a vital role Ans)((-4)**2)+4 Q) you are doing exploratory analysis Ans) scatter plot Q) which command you will use to check the python version Ans) python -v Q) A variable named 'savings: Ans) 800 Q) which keyword we used as a 'no-operation' Ans)pass Q) How to write the given function in one line code Ans) square = [i*i for i in range(10)]

ans=10000000 def solve(a, n, k, index, sum, maxsum): global ans # K=1 is the base Case if (k == 1): maxsum = max(maxsum, sum) sum = 0 for i in range(index,n): sum += a[i] # we update maxsum maxsum = max(maxsum, sum) # the answer is stored in ans ans = min(ans, maxsum) return sum = 0 # using for loop to divide the array into # K-subarray for i in range(index, n): sum += a[i] # for each subarray we calculate sum ans update # maxsum maxsum = max(maxsum, sum) # calling function again solve(a, n, k - 1, i + 1, sum, maxsum) # driver code n=int(input()) k=int(input()) arr=[] for z in range(n): arr.append(int(input())) solve(arr, n, k, 0, 0, 0) print(ans)

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