ریاضیات سال دوازدهم اجلالی
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ارتباط با ادمین @kazemejlali @kazemejlali_admin کانال سال یازدهم https://t.me/ejlali_math_11 کانال سال دهم https://t.me/ejlali_math_10
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| Date | Subscriber Growth | Mentions | Channels | |
| 09 November | +2 | |||
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| 01 November | +1 |
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| 5 | پاسخ سوال شماره ۳۱۱ و ۳۱۲
اگر مضارب عدد k رو از دنباله اعداد طبیعی حذف کنیم، جمله عمومی دنباله جملات باقیمانده به صورت زیر است.
a(n)=n+[(n-1)/(k-1)]
در سوال ۳۱۱ :
a(n)=n+[(n-1)/۴]
و در سوال ۳۱۲ :
a(n)=n+[(n-1)/۶] | 727 |
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