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π»Bu kanalda β‘οΈ Dasturlash tillaridan kerakli kodlar β‘οΈ Competitive Programming boΚΌyicha va β‘οΈ IT sohasiga oid yangiliklar ham yoritilib boriladi. ππππ Admin: @programmer_7 Guruh: Reklama boΚΌlimi: Ta'mirda
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#include <iostream>
#include <math.h>
using namespace std;
int main() {
float i, y, L;
cin>>i>>y;
L=(0.81*cos(i))/(log(y)+2*pow(i,3));
cout<<L;
return 0;
}
C++
#include <iostream>
#include <math.h>
using namespace std;
int main() {
float a, t, y, D;
cin>>a>>t>>y;
D=(7.8*pow(a,2)+3.52*t)/(log(a+2*y)+exp(y));
cout<<D;
return 0;
}
C++
#include <iostream>
#include <math.h>
using namespace std;
int main() {
float w, y, G;
cin>>w>>y;
G=(9.33*pow(w, 3)+sqrt(w))/(log(y+3.5)+sqrt(y));
cout<<G;
return 0;
}
#include <iostream>
#include <math.h>
using namespace std;
int main() {
float k, y, U;
cin>>k>>y;
U=(log(k-y)+pow(y,4))/(exp(y)+2.355*pow(k,2));
cout <<U;
return 0;
}
C++
#include <iostream>
#include <math.h>
using namespace std;
int main() {
float d, y, F;
cin>>d>>y;
F=log(d)+(3.5*pow(d, 2)+1)/cos(2*y);
cout <<F;
return 0;
}
C++
#include <iostream>
#include <math.h>
using namespace std;
int main() {
float G, y, f;
cin>>y>>f;
G=(exp(2*y)+sin(f))/log(3.8*y+f);
cout <<G;
return 0;
}
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