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🇺🇿Mathematicians of Uzbekistan🇺🇿

Assalomu aleykum🙂🙂🙂 🇺🇿Mathematicians of Uzbekistan🇺🇿 kanaliga xush kelibsiz😇😇😇 🎯Maqsad: Bilimlarimizni baham kõrish. 🧩qiziqarli misollar yechimi berib boriladi. 📝shiorimiz:Agar reja ish bermasa rejani õzgartiring🙃🙃🙃maqsadni emas🚀🚀🚀

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#progressiya Õsuvchi arifmetik progressiyani tashkil qiluvchi 3 ta son yiğindisi 51 ga teng.Agar bu sonlardan mos ravishda 1;7;8 sonlari ayirib tashlansa ,hosil bo'lgan sonlar geometrik progressiyani tashkil qiladi.Arfimetik progressiyaning nechta hadi olinganda,ularning yiğindisi 555 ga teng bõladi? Hammadan yechim kutib qolamiz! Kanalimizga dõstlaringizni ham taklif qiling https://t.me/matematika_1009
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🇺🇿Mathematicians of Uzbekistan🇺🇿

Assalomu aleykum🙂🙂🙂 🇺🇿Mathematicians of Uzbekistan🇺🇿 kanaliga xush kelibsiz😇😇😇 🎯Maqsad: Bilimlarimizni baham kõrish. 🧩qiziqarli misollar yechimi berib boriladi. 📝shiorimiz:Agar reja ish bermasa rejani õzgartiring🙃🙃🙃maqsadni emas🚀🚀🚀

#progressiya Geometrik progressiyaning dastlabki uchta hadi yiğindisi 42 ga teng.Bu so lar qandaydir arifmetik progressiyaning birinchi,ikkinchi va oltinchi hadlariga tengdir.Bu sonlarni toping
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Kanaldan chiqib ketayotganlar tashqari juda issiq 😂 @Muslimbek6468
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Awinaqa😌 @Muslimbek6468
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1+sin@-cos@-tg@=? Yechimlarizni izohda qoldiring🤓
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Manimcha bunga ko'pchilik qanday ovoz berishni tushunmagan. Eng pastida ko'k yozuv bilan ''ovoz bering va fikr bildiring'' degan joyini ustiga bosasiz keyin so'rovnoma chiqadi shu so'rovnomadan 56 raqamdagi Regzor mfyga ovoz yig'ishda yordamlashib yuborsangiz yaxshi bo'lardi 🙂
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Assalomu alaykum Sultonov Sobirjonga ovoz beringlar 56-nomerda @Muslimbek6468
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