CODING SOLUTION - Placement Jobs & Materials
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Channel CODING SOLUTION - Placement Jobs & Materials (@codingsolution_it) in the English language segment is an active participant. Currently, the community unites 128 253 subscribers, ranking 157 in the Career category and 1 680 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 128 253 subscribers.
According to the latest data from 08 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -1 995 over the last 30 days and by -103 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 1.50%. Within the first 24 hours after publication, content typically collects 0.43% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 920 views. Within the first day, a publication typically gains 548 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
- Thematic interests: Content is focused on key topics such as t.me/codingsolution_it, vector, codevita, string, graduate.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “
Contact Admin:
Mail me for collab
offcampusjobsindiaadmin@gmail.com
instagram.com/offcampusjobsindia_it
Our Website :
www.offcampusjobsindia.com”
Thanks to the high frequency of updates (latest data received on 09 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Career category.
128 253
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Posts Archive
int n=books.size();
vector<vector<int>> cost(n+1,vector<int>(n+1));
for(int i=1;i<=n;i++)
{
int height=books[i-1][1];
int width=books[i-1][0];
cost[i][i]=height;
for(int j=i+1;j<=n;j++)
{
height=max(height,books[j-1][1]);
width+=books[j-1][0];
if(width<=shelfWidth) cost[i][j]=height;
else cost[i][j]=-1;
}
}
vector<int> ans(n+1);
ans[0]=0;
for(int i=1;i<=n;i++)
{
ans[i]=INT_MAX;
for(int j=1;j<=i;j++)
{
if(cost[j][i]==-1) continue;
if(ans[j-1]!=INT_MAX) ans[i]=min(ans[i],ans[j-1]+cost[j][i]);
}
}
return ans[n]
Python
Murder on book shelf Code
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Python
Distant Palindrome code
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Python
Minimum swap Code
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def isPalindrome(s):
return s == s[::-1]
# Driver code
s = "malayalam"
ans = isPalindrome(s)
if ans:
print("Yes")
else:
print("No")
Python
Palindrome Code
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C++
Build road code
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#include <bits/stdc++.h>
using namespace std;
// Utility method to check whether a character
// is operator or not
bool isOperator(char op)
{
return (op == '+' || op == '*');
}
// method prints minimum and maximum value
// obtainable from an expression
void printMinAndMaxValueOfExp(string exp)
{
vector<int> num;
vector<char> opr;
string tmp = "";
// store operator and numbers in different vectors
for (int i = 0; i < exp.length(); i++)
{
if (isOperator(exp[i]))
{
opr.push_back(exp[i]);
num.push_back(atoi(tmp.c_str()));
tmp = "";
}
else
{
tmp += exp[i];
}
}
// storing last number in vector
num.push_back(atoi(tmp.c_str()));
int len = num.size();
int minVal[len][len];
int maxVal[len][len];
// initializing minval and maxval 2D array
for (int i = 0; i < len; i++)
{
for (int j = 0; j < len; j++)
{
minVal[i][j] = INT_MAX;
maxVal[i][j] = 0;
// initializing main diagonal by num values
if (i == j)
minVal[i][j] = maxVal[i][j] = num[i];
}
}
// looping similar to matrix chain multiplication
// and updating both 2D arrays
for (int L = 2; L <= len; L++)
{
for (int i = 0; i < len - L + 1; i++)
{
int j = i + L - 1;
for (int k = i; k < j; k++)
{
int minTmp = 0, maxTmp = 0;
// if current operator is '+', updating tmp
// variable by addition
if(opr[k] == '+')
{
minTmp = minVal[i][k] + minVal[k + 1][j];
maxTmp = maxVal[i][k] + maxVal[k + 1][j];
}
// if current operator is '*', updating tmp
// variable by multiplication
else if(opr[k] == '*')
{
minTmp = minVal[i][k] * minVal[k + 1][j];
maxTmp = maxVal[i][k] * maxVal[k + 1][j];
}
// updating array values by tmp variables
if (minTmp < minVal[i][j])
minVal[i][j] = minTmp;
if (maxTmp > maxVal[i][j])
maxVal[i][j] = maxTmp;
}
}
}
// last element of first row will store the result
cout << "Minimum value : " << minVal[0][len - 1]
<< ", Maximum value : " << maxVal[0][len - 1];
}
// Driver code to test above methods
int main()
{
string expression = "1+2*3+4*5";
printMinAndMaxValueOfExp(expression);
return 0;
}
C++
Minimum Value Expression
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#include<bits/stdc++.h>
int max(int a, int b);
/* Returns length of LCS for X[0..m-1], Y[0..n-1] */
int lcs( char *X, char *Y, int m, int n )
{
if (m == 0 || n == 0)
return 0;
if (X[m-1] == Y[n-1])
return 1 + lcs(X, Y, m-1, n-1);
else
return max(lcs(X, Y, m, n-1), lcs(X, Y, m-1, n));
}
/* Utility function to get max of 2 integers */
int max(int a, int b)
{
return (a > b)? a : b;
}
/* Driver program to test above function */
int main()
{
char X[] = "AGGTAB";
char Y[] = "GXTXAYB";
int m = strlen(X);
int n = strlen(Y);
printf("Length of LCS is %d", lcs( X, Y, m, n ) );
return 0;
}
C++
Longest Special Subsequences
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