JavaSkvirt // IT Memes
Розважаємо між комп'ютерними буднями ⛄️ @itua_chat - наш чат @ad_duck - зв’язок
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Network:📈 Analytical overview of Telegram channel JavaSkvirt // IT Memes
Channel JavaSkvirt // IT Memes (@memes_java) in the Ukrainian language segment is an active participant. Currently, the community unites 10 375 subscribers, ranking 11 448 in the Technologies & Applications category and 5 644 in the Ukraine region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 10 375 subscribers.
According to the latest data from 30 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -49 over the last 30 days and by -4 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 41.36%. Within the first 24 hours after publication, content typically collects 26.44% reactions from the total number of subscribers.
- Post reach: On average, each post receives 4 292 views. Within the first day, a publication typically gains 2 743 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 121.
- Thematic interests: Content is focused on key topics such as тімлід, ethereum, github, дедлайн, комп'ютер.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“Розважаємо між комп'ютерними буднями ⛄️
@itua_chat - наш чат
@ad_duck - зв’язок”
Thanks to the high frequency of updates (latest data received on 31 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
while :;do echo $LINES $COLUMNS $((RANDOM%COLUMNS)) "$(printf "\U$((RANDOM%500+1000))")";sleep 0.05;done|gawk '{a[$3]=0;for(x in a){o=a[x];a[x]=a[x]+1;c=int(rand()*5);if(c==0)col="\033[1;32m";else if(c==1)col="\033[0;32m";else if(c==2)col="\033[1;36m";else if(c==3)col="\033[1;31m";else col="\033[1;37m";printf "\033[%s;%sH%s%s",o,x,col,$4;printf "\033[%s;%sH\033[0m",a[x],x;if(a[x]>=$1)a[x]=0;}}'
