М Е Д И Т Ц И Н А

1.85*16=29.6 32. 1.6-------------x=0.8 29.6 28. 2.4------------x=1.2 1.6+2.4=4------------------2 mol 20*1.85=37 2x-------x ---------2x 2CO + O2--->2 CO2 28*(1.2-2x)+32*(0.8-x)+88x ---------------------------------------------=37 1.2+0.8--3x+2x X=0.4. Mol 0.8-0.4=0.4 O2 ortgan 1.2-0.4*2=0.4 CO ortgan 0.4*2=0.8 CO2 xosil boʻlgan 0.8 -------------*💯%=50% 0.8+0.8 #C

0.1--0.04=0.06 8*4*5=160 m³ =160000 160000*0.06/💯=96 20*16=320 320----------------60 min 96------------------x=18 min

26) -- Yechim : Ikkita aromatik uglevodorodlar bir biriga izomer ✅ Savolni kerakli joyi C soni teng deb aytmoqda C6H5---R ----> C6H5-COOH + xCO2 C6H5--R -->C6H4-(COOH)2 +x-1CO2 0.5=x--------53 2NaOH + CO2---> Na2CO3+ H20 1 mol -------- 106 Benzoy kislatada jami C soni 7 ta Terftar kislatada jami C soni 8 ta 24.4/122=0.2 mol Benzoy kislata 0.2--------------------0.2x C6H5-COOH + x CO2 0.1---------------------------0.1x - 0.1 mol C6H4-(COOH)2 + (x - 1) CO2 0.2x + 0.1x - 0.1 = 0.5 0.3x = 0.6 X = 2 Benzoy kislatadan 2 CO2 xosil bolgan Tereftal dan esa 1 CO2 xosil bolgan Demak Xulosa C6H5-COOH + 2CO2--> C6H5--C3H7 C6H4-(COOH)2 + CO2------> ----> C6H4(CH3)2--CH3 Jami C soni teng demak toʻgri keladi Tereftal massasini soʻragan C6H4-(COOH)2 Mr = 120 120*0.1=12 #A

28) --- Yechim : CnH2n ----> 1 mol O 2----------> 6 mol N2 ----------> 3 mol 1--------------1.5n----------n CnH2n+1.5nO2----> nCO2+nH20 O2 ortgan N kirishmagan 16*2.2=35.2 28*3+32*(6-1.5n)+44n -------------------------------------=35.2 3+6--1.5n + n n=3 C3H6 1-----------4.5----------3 C3H6 + 4.5O2---> 3CO2 6-4.5=1.5 ortgan 3 xosil boʻlgan 3 -------------*💯%=40% 3+3+1.5 #B

10.24.6 ) -- Yechim : 1- qismini yarmi NaOH bilan ketgan qolgani esa yongan NaOH + C = ❌ 0.2=x--------------------------8.96 2NaOH + Si + H20--> Na2SiO3 + 2H2 1 mol ---------------------2*22.4 2- qism bunda toʻliq yongan C + O2---> CO2 0.4----------x=24 Si + O2---> SiO2 1----------------60 41.6--24 = 17.6 bu CO2 17.6 : 44 = 0.4 mol Demak xulosa 1 - teng miqdorda 2 ga bolingan 1- Si yarmi yongan yarimi esa NaOH bilan reaksiya ketgan 0.4 va 0.4 ekan demak bu teng yarmi bolsa 0.4*2=0.8 mol Si 0.4*2=0.8 mol C 28*0.8+12*0.8= 32 gr Javob : #32

Yechim : Prapan ❌ emas prapen ✅ X+y = 1 42x + 2y = 22 X=0.5 Y=0.5 mol 0.5*4=2 2*1.8=3.6 3.6 C3H6 + H2----> C3H8 12 ta bor 3.6/12=0.3 mol 0.5--0.3=0.2 0.2 -------=2.5 X X=0.08 min 0.08*60=4.8 sek Toʻgʻri mi : B✅

241 ga qaravorila

Yechim : 69.6/87=0.8 408.156/6.02=67.8 0.8-------116.8----100.8---1.6 MnO2+ 4HCl= MnCl2+ Cl2 + 2H20 116.8+36.5x/0.292=400+125x 0.8*3+0.8*2*3=7.2 67.8--7.2=60.6 2x + 14.75x =13.4 X=0.8 0.8+0.8*4=4 4*36.5/0.292=500 500+69.6--0.8*71=512.8 100.8 -----------*💯%=19.6 512.8 #A

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