en
Feedback
Data Interpertation & airthmatic

Data Interpertation & airthmatic

Open in Telegram

❣Link for all our imp channels❣ For maths:- @quant_material For reasoning :- @reasoning_material For english:- @english_mcqs_quizzes For ca quizzes :- @current_affairs_bank_ssc_upsc Query ? Promotions? Contact us - @ask_agriguruji

Show more
7 903
Subscribers
No data24 hours
-327 days
-11630 days
Posts Archive
#missing #no. #series

#quadratic #equations I. xΒ² – 27x + 152 = 0 II. yΒ² + 7y – 120 = 0 I. xΒ² – 16x + 55 = 0 II. yΒ² – 26y + 165 = 0 I. xΒ² – 14x + 45 = 0 II. yΒ² + 6y – 55 = 0 I. xΒ² – 25x + 150 = 0 II. yΒ² – 18y + 80 = 0 I. x²– 19x + 48 = 0 II. yΒ² +12y - 45 = 0 I. xΒ² + 14x - 95 = 0 II. yΒ² – 16y + 60 = 0 I. xΒ² + 19x + 90 = 0 II. yΒ² + 23y + 132 = 0 I. xΒ² + 11x + 30 = 0 II. yΒ² + 15y + 56 = 0 I. xΒ² – 17x + 52 = 0 II. yΒ² + 8y – 48 = 0 I. xΒ² – 17x + 60 = 0 II. yΒ² – 25y + 156 = 0 @quant_material

(√4)³x (√16)⁴ ÷ 8² = 2? A. 8 B. 5 C. 9 D. 7 E. None of these

22% of 350 - 12% of 50 = ? - 74 A. 125 B. 130 C. 145 D. 165 E. 205

119.98 x 12.017 x 90.11 + ? = 159996 A. 30130 B. 30396 C. 32560 D. 31586 E. 30400

√3248 x (4095)β…“ + (19683)β…“ + √2405 = ? - 870.001 A. 1487 B. 1858 C. 1658 D. 1530 E. 1288

3356.007 x 6.001 - 1899.98 + 1128.007 + 429.96 = ? - (45 x 12.01) A. 24926 B. 20334 C. 26534 D. 29426 E. 26426

472.03 x 91.02 + 336.98 + 472.03 - 137.003 x 7.5003 Γ· 2.45 = ? A. 43350 B. 44625 C. 48925 D. 49750 E. 47150

7777.1 x 11 + 3333.1 x 11.01 + 4444.1 x 11.01 - 5555 x 10.99 = ? A. 78789 B. 87879 C. 85589 D. 99089 E. 109989

(√? ÷ 2⁴) x 512 = 288 A. 9 B. 8 C. 81 D. 64 E.49

65% of 450 + ?% of 360 = 389.7 A. 25 B. 27 C. 30 D. 28 E. 32

1. The number of candidates who did not qualified Pre – exam from Punjab is how much more or less than number of candidates who did not qualified Pre –exam from West Bengal? (A)410 (B)411 (C)408 (D)402 (E)None of these 2. The number of candidates from Haryana who did not qualify the Pre – exam is what percent of total number of candidates who did not qualify the Pre – exam from all states? (A)28.42% (B)21.47% (C)28.67% (D)24.56% (E)None of these 3. If 25% candidate from Rajasthan who qualified Pre – exam has also qualified Mains exam and 31.25% candidate from West Bengal who qualified Pre –exam has also qualified Mains exam, then the sum of candidates who did not qualified Mains exam from Rajasthan and West Bengal both are what percent more or less than number of candidates from West Bengal who applied for the examination? (A)22% more (B)34% less (C)28% more (D)35% less (E)None of these 4. Find the ratio between number of candidates from Rajasthan who qualify the Pre – exam and number of candidates from West Bengal who did not qualify the Pre – exam. (A)41 : 43 (B)34 : 35 (C)32 : 39 (D)31 : 32 (E)None of these 5. Find the average number of candidates who qualify the Pre – exam from all five states. (A)1218 (B)1348 (C)1321 (D)1431 (E)None of these

graph shows the percentage distribution of candidates applied for an examination and percentage of candidates who qualified P
graph shows the percentage distribution of candidates applied for an examination and percentage of candidates who qualified Pre – exam from five different states. Read the data and answer the following questions. Note : The number of candidate who did not qualified Pre – exam from Rajasthan is 1152.

#missing #series 1. πŸπŸ—, ? , πŸ’πŸ—, πŸπŸŽπŸ—, πŸπŸπŸ—, πŸ’πŸ‘πŸ— a.21 b.25 c.29 d.33 e.43 2. 𝟏𝟎𝟏, πŸ“πŸπŸ”πŸ, ? , πŸ–πŸ•πŸŽπŸ, πŸ–πŸ—πŸπŸ”, πŸ–πŸ—πŸ“πŸ— a.7341 b.7141 c.6741 d.7541 e.7841 3. πŸ”πŸπŸπŸŽ, πŸ‘πŸŽπŸ”πŸŽ, 𝟏𝟎𝟐𝟎, ? , πŸ“πŸ, πŸ–. πŸ“ a.204 b.408 c.510 d.255 e.170 4. πŸπŸ—, πŸ’πŸ“, ? , πŸπŸ“πŸ‘, πŸ“πŸŽπŸ—, πŸ—πŸŽπŸ— a.109 b.99 c.119 d.89 e.129 5. ? , πŸπŸ–, πŸ‘πŸ”, πŸ—πŸŽ, πŸπŸ•πŸŽ, πŸ—πŸ’πŸ“ a.15 b.9 c.12 d.24 e.6 6. πŸ‘πŸ‘, πŸ”πŸ‘, ? , πŸπŸ”πŸ, πŸπŸ‘πŸ‘, πŸ‘πŸπŸ‘ a.105 b.109 c.113 d.101 e.97 7. πŸ’πŸ–, πŸ’πŸ—, πŸ“πŸ’, πŸ•πŸ—, ? , πŸ–πŸπŸ— a.104 b.204 c.304 d.154 e.184 8. πŸ”πŸ—, πŸπŸ–πŸŽ, πŸ’πŸŽπŸ, ? , πŸπŸπŸ•πŸ—, πŸπŸ•πŸ‘πŸ’ a.935 b.835 c.635 d.535 e.735 9. πŸπŸ”, πŸ‘πŸ’, ? , πŸ’πŸ”, πŸ“πŸ”, πŸ”πŸ• a.37 b.45 c.43 d.41 e.39 10.πŸπŸŽπŸ“, πŸπŸ”πŸ, πŸπŸ•πŸ‘, ? , πŸπŸ—πŸ“πŸ‘, πŸ–πŸ”πŸ•πŸ‘ a.519 b.549 c.609 d.649 e.709

#wrong #series 1. πŸ—πŸ–πŸ—, πŸπŸŽπŸŽπŸ–, πŸ—πŸ•πŸŽ, πŸπŸŽπŸ–πŸŽ, πŸ”πŸπŸ–, πŸπŸ—πŸŽπŸ– a.989 b.1008 c.970 d.2908 e.1080 2. πŸπŸ’, 𝟏𝟐, πŸπŸ’, πŸπŸ–, πŸ‘πŸ”, πŸ—πŸŽ a.14 b.90 c.18 d.36 e.24 3. πŸ“πŸ•, πŸ•πŸ”, 𝟏𝟏𝟐, πŸπŸ–πŸ”, πŸ‘πŸπŸ‘, πŸ“πŸπŸ a.57 b.112 c.512 d.313 e.186 4. πŸπŸŽπŸ—, πŸπŸ‘πŸ, πŸ‘πŸ“πŸ—, πŸ—πŸ–πŸ’, πŸπŸπŸŽπŸ—, πŸ’πŸπŸ‘πŸ’ a.109 b.984 c.2209 d.132 e.4234 5. πŸ—, 𝟏𝟎, πŸπŸ–, πŸ’πŸ‘, πŸπŸŽπŸ—, πŸπŸ‘πŸ’ a.10 b.234 c.43 d.109 e.18 6. πŸ”, πŸ–, πŸπŸ—, πŸ”πŸ‘, πŸπŸ’πŸ—, πŸπŸπŸ“πŸ a.8 b.19 c.1251 d.249 e.63 7. πŸ—πŸ’, πŸ—πŸ’πŸ“πŸ’, πŸπŸπŸ‘πŸπŸ”, πŸπŸπŸ•πŸ—πŸ’, πŸπŸπŸ—πŸ’πŸŽ, πŸπŸπŸŽπŸπŸ– a.11326 b.9454 c.12028 d.11940 e.94 8. πŸ–πŸ, πŸπŸπŸ—, πŸπŸ—πŸ—, πŸ‘πŸπŸŽ, πŸ’πŸ–πŸ—, πŸ•πŸπŸ a.199 b.711 c.489 d.81 e.320 9. πŸ‘πŸ, πŸπŸ”, πŸ’πŸ–, πŸπŸ’, πŸ”πŸŽ, 𝟏𝟎 a.48 b.24 c.10 d.60 e.32 10.πŸ—πŸ, πŸπŸŽπŸ—, πŸπŸ—πŸŽ, πŸ’πŸ’πŸ”, πŸπŸŽπŸ•πŸ, πŸπŸ‘πŸ”πŸ• a.446 b.2367 c.91 d.109 e.190

10.I.π’™πŸ βˆ’ πŸ‘. πŸ’π’™ + 𝟐. πŸ– = 𝟎 II.πŸπŸπ’šπŸ = πŸ‘πŸ‘πŸ•πŸ“ βˆ’ πŸ‘π’šπŸ a. 𝒙 > π’š b. 𝒙 < π’š c. 𝒙 β‰₯ π’š d. 𝒙 ≀ π’š e. 𝐱 = 𝐲 𝐨𝐫 𝐫𝐞π₯𝐚𝐭𝐒𝐨𝐧 𝐜𝐚𝐧𝐭 π›πž πžπ¬π­πšπ›π₯𝐒𝐬𝐑𝐞𝐝

9. I.π’™πŸ + πŸ’πŸ”π’™ + πŸ“πŸπŸ– = 𝟎 II.π’šπŸ βˆ’ π’š βˆ’ πŸ’πŸπŸŽ = 𝟎 a. 𝒙 > π’š b. 𝒙 < π’š c. 𝒙 β‰₯ π’š d. 𝒙 ≀ π’š e. 𝐱 = 𝐲 𝐨𝐫 𝐫𝐞π₯𝐚𝐭𝐒𝐨𝐧 𝐜𝐚𝐧𝐭 π›πž πžπ¬π­πšπ›π₯𝐒𝐬𝐑𝐞𝐝

8. I.π’™πŸ + πŸ–βˆšπŸ‘π’™ + πŸ’πŸ“ = 𝟎 II.π’šπŸ + πŸβˆšπŸ‘π’š βˆ’ πŸ’πŸ“ = 𝟎 a. 𝒙 > π’š b. 𝒙 < π’š c. 𝒙 β‰₯ π’š d. 𝒙 ≀ π’š e. 𝐱 = 𝐲 𝐨𝐫 𝐫𝐞π₯𝐚𝐭𝐒𝐨𝐧 𝐜𝐚𝐧𝐭 π›πž πžπ¬π­πšπ›π₯𝐒𝐬𝐑𝐞𝐝

7. I.π’™πŸ + πŸ‘πŸπ’™ + πŸπŸ’πŸŽ = 𝟎 II.π’šπŸ βˆ’ πŸ’πŸπ’š + πŸπŸ–πŸŽ = 𝟎 a. 𝒙 > π’š b. 𝒙 < π’š c. 𝒙 β‰₯ π’š d. 𝒙 ≀ π’š e. 𝐱 = 𝐲 𝐨𝐫 𝐫𝐞π₯𝐚𝐭𝐒𝐨𝐧 𝐜𝐚𝐧𝐭 π›πž πžπ¬π­πšπ›π₯𝐒𝐬𝐑𝐞𝐝

6. I.πŸ–π’™πŸ + πŸπŸŽπ’™ + 𝟏𝟐 = 𝟎 II.πŸ’π’šπŸ + πŸπŸ•π’š + πŸπŸ– = 𝟎 a. 𝒙 > π’š b. 𝒙 < π’š c. 𝒙 β‰₯ π’š d. 𝒙 ≀ π’š e. 𝐱 = 𝐲 𝐨𝐫 𝐫𝐞π₯𝐚𝐭𝐒𝐨𝐧 𝐜𝐚𝐧𝐭 π›πž πžπ¬π­πšπ›π₯𝐒𝐬𝐑𝐞𝐝