Data Interpertation & airthmatic
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#quadratic #equations
I. xΒ² β 27x + 152 = 0
II. yΒ² + 7y β 120 = 0
I. xΒ² β 16x + 55 = 0
II. yΒ² β 26y + 165 = 0
I. xΒ² β 14x + 45 = 0
II. yΒ² + 6y β 55 = 0
I. xΒ² β 25x + 150 = 0
II. yΒ² β 18y + 80 = 0
I. xΒ²β 19x + 48 = 0
II. yΒ² +12y - 45 = 0
I. xΒ² + 14x - 95 = 0
II. yΒ² β 16y + 60 = 0
I. xΒ² + 19x + 90 = 0
II. yΒ² + 23y + 132 = 0
I. xΒ² + 11x + 30 = 0
II. yΒ² + 15y + 56 = 0
I. xΒ² β 17x + 52 = 0
II. yΒ² + 8y β 48 = 0
I. xΒ² β 17x + 60 = 0
II. yΒ² β 25y + 156 = 0
@quant_material
(β4)Β³x (β16)β΄ Γ· 8Β² = 2?
A. 8
B. 5
C. 9
D. 7
E. None of these
22% of 350 - 12% of 50 = ? - 74
A. 125
B. 130
C. 145
D. 165
E. 205
119.98 x 12.017 x 90.11 + ? = 159996
A. 30130
B. 30396
C. 32560
D. 31586
E. 30400
β3248 x (4095)β
+ (19683)β
+ β2405 = ? - 870.001
A. 1487
B. 1858
C. 1658
D. 1530
E. 1288
3356.007 x 6.001 - 1899.98 + 1128.007 + 429.96 = ? - (45 x 12.01)
A. 24926
B. 20334
C. 26534
D. 29426
E. 26426
472.03 x 91.02 + 336.98 + 472.03 - 137.003 x 7.5003 Γ· 2.45 = ?
A. 43350
B. 44625
C. 48925
D. 49750
E. 47150
7777.1 x 11 + 3333.1 x 11.01 + 4444.1 x 11.01 - 5555 x 10.99 = ?
A. 78789
B. 87879
C. 85589
D. 99089
E. 109989
1. The number of candidates who did not qualified Pre β exam from Punjab is how much more or less than number of candidates who did not qualified Pre βexam from West Bengal?
(A)410
(B)411
(C)408
(D)402
(E)None of these
2. The number of candidates from Haryana who did not qualify the Pre β exam is what percent of total number of candidates who did not qualify the Pre β exam from all states?
(A)28.42%
(B)21.47%
(C)28.67%
(D)24.56%
(E)None of these
3. If 25% candidate from Rajasthan who qualified Pre β exam has also qualified Mains exam and 31.25% candidate from West Bengal who qualified Pre βexam has also qualified Mains exam, then the sum of candidates who did not qualified Mains exam from Rajasthan and West Bengal both are what percent more or less than number of candidates from West Bengal who applied for the examination?
(A)22% more
(B)34% less
(C)28% more
(D)35% less
(E)None of these
4. Find the ratio between number of candidates from Rajasthan who qualify the Pre β exam and number of candidates from West Bengal who did not qualify the Pre β exam.
(A)41 : 43
(B)34 : 35
(C)32 : 39
(D)31 : 32
(E)None of these
5. Find the average number of candidates who qualify the Pre β exam from all five states.
(A)1218
(B)1348
(C)1321
(D)1431
(E)None of these
graph shows the percentage distribution of candidates applied
for an examination and percentage of candidates who qualified Pre β exam from five different states. Read the data and answer the following questions.
Note : The number of candidate who did not qualified Pre β exam from Rajasthan is 1152.
#missing #series
1. ππ, ? , ππ, πππ, πππ, πππ
a.21
b.25
c.29
d.33
e.43
2. πππ, ππππ, ? , ππππ, ππππ, ππππ
a.7341
b.7141
c.6741
d.7541
e.7841
3. ππππ, ππππ, ππππ, ? , ππ, π. π
a.204
b.408
c.510
d.255
e.170
4. ππ, ππ, ? , πππ, πππ, πππ
a.109
b.99
c.119
d.89
e.129
5. ? , ππ, ππ, ππ, πππ, πππ
a.15
b.9
c.12
d.24
e.6
6. ππ, ππ, ? , πππ, πππ, πππ
a.105
b.109
c.113
d.101
e.97
7. ππ, ππ, ππ, ππ, ? , πππ
a.104
b.204
c.304
d.154
e.184
8. ππ, πππ, πππ, ? , ππππ, ππππ
a.935
b.835
c.635
d.535
e.735
9. ππ, ππ, ? , ππ, ππ, ππ
a.37
b.45
c.43
d.41
e.39
10.πππ, πππ, πππ, ? , ππππ, ππππ
a.519
b.549
c.609
d.649
e.709
#wrong #series
1. πππ, ππππ, πππ, ππππ, πππ, ππππ
a.989
b.1008
c.970
d.2908
e.1080
2. ππ, ππ, ππ, ππ, ππ, ππ
a.14
b.90
c.18
d.36
e.24
3. ππ, ππ, πππ, πππ, πππ, πππ
a.57
b.112
c.512
d.313
e.186
4. πππ, πππ, πππ, πππ, ππππ, ππππ
a.109
b.984
c.2209
d.132
e.4234
5. π, ππ, ππ, ππ, πππ, πππ
a.10
b.234
c.43
d.109
e.18
6. π, π, ππ, ππ, πππ, ππππ
a.8
b.19
c.1251
d.249
e.63
7. ππ, ππππ, πππππ, πππππ, πππππ, πππππ
a.11326
b.9454
c.12028
d.11940
e.94
8. ππ, πππ, πππ, πππ, πππ, πππ
a.199
b.711
c.489
d.81
e.320
9. ππ, ππ, ππ, ππ, ππ, ππ
a.48
b.24
c.10
d.60
e.32
10.ππ, πππ, πππ, πππ, ππππ, ππππ
a.446
b.2367
c.91
d.109
e.190
10.I.ππ β π. ππ + π. π = π
II.ππππ = ππππ β πππ
a. π > π
b. π < π
c. π β₯ π
d. π β€ π
e. π± = π² π¨π« π«ππ₯πππ’π¨π§ πππ§π ππ ππ¬ππππ₯π’π¬π‘ππ
9. I.ππ + πππ + πππ = π
II.ππ β π β πππ = π
a. π > π
b. π < π
c. π β₯ π
d. π β€ π
e. π± = π² π¨π« π«ππ₯πππ’π¨π§ πππ§π ππ ππ¬ππππ₯π’π¬π‘ππ
8. I.ππ + πβππ + ππ = π
II.ππ + πβππ β ππ = π
a. π > π
b. π < π
c. π β₯ π
d. π β€ π
e. π± = π² π¨π« π«ππ₯πππ’π¨π§ πππ§π ππ ππ¬ππππ₯π’π¬π‘ππ
7. I.ππ + πππ + πππ = π
II.ππ β πππ + πππ = π
a. π > π
b. π < π
c. π β₯ π
d. π β€ π
e. π± = π² π¨π« π«ππ₯πππ’π¨π§ πππ§π ππ ππ¬ππππ₯π’π¬π‘ππ
6. I.πππ + πππ + ππ = π
II.πππ + πππ + ππ = π
a. π > π
b. π < π
c. π β₯ π
d. π β€ π
e. π± = π² π¨π« π«ππ₯πππ’π¨π§ πππ§π ππ ππ¬ππππ₯π’π¬π‘ππ
