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NEET Short Notes
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| 3 | GYMNOSPERM
• tap roots
• naked seeds🌰
• thick cuticle & sunken stomats also reduce water loss
• unlike pteridophytes, these have not an independent free living existence. | 1 580 |
| 4 | Baacho aapki sab problems solve 👍❤️
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Each Chapter explained in 2-3 pages
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| 6 | NEET Study materials shortcuts
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| 7 | 🎯🎯 Points to remember🎯🎯
🔥Extra edge of ncert🔥
1. Triple helical model of collagen was given by G.N. Ramachandran
2. Ramachandran was influenced by Linus Pauling
3. Darwin was influenced by Malthus
4. P. Maheshwari was influenced by Dr. W. Dudegon
5. a- helix & b- sheet structures was published by Linus Pauling
💐💐💐💐💐💐💐💐💐💐💐💐💐
1. Anton von Leeuwenhoek first saw & described a live cell.
2. Cell theory was given by Schleiden & Schwann.
3. Cell theory was modified by Rodolf Virchow (1855)
4. Fluid mosaic model was given by Singer & Nicholson(1972)
5. G.B. discovered by Camillo Golgi (1898) | 2 408 |
| 8 | ⚠️ ALERT ⚠️NEET 2023😷 ASPIRANTS📢
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| 9 | 🌀Notes on Special Theory of Relativity:-
Frame of reference:- A system of coordinates whose axes can be suitably chosen is said to be a frame of reference.
Inertial frame:- A frame of reference either at rest or moving with a uniform velocity (zero acceleration) is known as inertial frame.
Non-inertial or accelerated frame:- It is a frame of reference which is either having a uniform linear acceleration or is being rotated with a uniform speed.
Galilean transformation:-
(a) Transformation of position:-
x' = x – vt
y' = y
z' = z
t' = t
Inverse transformation,
x = x'+ vt '
y = y'
z = z'
t = t'
(b) Transformation of distance:-
l ' = l
Here, l = x2-x1 is the length of rod as observed in frame S.
Anything which remains unchanged when observed from the two Galilean frames of reference is known as Galilean invariant.
(c) Transformation of velocity:-
u'= u– v
Inverse transformation:- u = u'+ v
(d) Transformation of acceleration:-
a' = a
Thus, the acceleration of body, as observed by two observers siting in two inertial frames, is same. Hence, acceleration is said to be Galilean invariant.
Law of conservation of momentum:-
It states that the total momentum of an isolated system (no external force) always remains constant.
In S frame:- m1u1 + m2u2 = m1v1 + m2v2
In S ' frame:- m1u'1 + m2 u'2 = m1 v'1 + m2 v'2
Thus, the law of conservation of momentum is valid in S ' also, indicating that the law is Galilean invariant.
Ether and velocity of light:- c' = c ±v
Postulates of special theory of relativity:-
(a) The laws of physical phenomenon are same when stated in terms of two systems of reference in uniform translator motion relative to each other.
(b) The velocity of light in vacuum is constant, independent not only of the direction of propagation but also of the relative velocity of the source and the observer.
Lorentz transformation equations:-
x' = [x - vt]/√[1- v2/c2]
y'= y
z'= z
t' = [t – [(v/c 2) x]]/√[1- v2/c2]
Lorentz inverse transformation equations:-
x= [x' + vt] /√[1- v2/c2]
y = y'
z= z'
t= [t' + [(v/c 2) x']]/√[1- v2/c2]
Length contraction:-
l = l0√[1- v2/c2]
So, l<l0
Here, l0 is the proper or original length in S frame and l is the relativistic length in S' frame.
Time Dilation:-
??t = ??t0/√ [1-v2/c2]
So, ?t > ??t0
Here, ??t0 is the proper or original time in S frame and ?t is the relativistic time in S' frame.
?Thus, the time interval as observed by the moving observer appears to be lengthened.
Frequency:- If f 0 is the natural frequency of a process in frame S, then the frequency f as observed from S ' given by,
f = f0√[1- v2/c2]
Relativistic velocity addition theorem:-
ux' = [ux – v]/[1- [(v/c2)ux]]
uy' = [uy√[1- v2/c2]]/[1- [(v/c2)ux]]
uz' = [uz√[1- v2/c2]]/[1- [(v/c2)ux]]
Relativistic variation of mass:-
m= m0/√[1-v2/c2]
Rest mass energy:-
E0 = m0c2
Total energy (Mass-Energy Equivalence):-
E= mc2 = [m0/√[1-v2/c2]] c2
Kinetic energy:-
EK= E - E0 = (m - m0) c2
Here c is the speed of light, m0 is the rest mass and m is the relativistic mass.
Relativistic momentum:-
p= mv
= [m0/√[1-v2/c2]] v | 2 861 |
| 10 | Reaction Between Aluminum and Bromine
The reaction begins and builds up heat. This heat causes the aluminum to melt and float on top of the liquid bromine (which is producing a cloud of vapor because the heat is also boiling it). Wherever the two elements meet, sparks, heat, and light are given off.
For more follow us👇
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| 12 | Biology Mnemonics for NEET 2023
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IgG – Protects body fluids.
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IgD – Activation of B-lymphocyte
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| 13 | National Symbols Of India
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Each Chapter explained in 2-3 pages
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| 15 | NEET Short Notes
Includes Biology, Physics and Chemistry Short Notes (NCERT based)
Each Chapter explained in 2-3 pages
Know More - https://www.buddycart.in/neet-short-notes/ | 428 |
| 16 | Tricks for Conversions in Organic Chemistry
✅Haloalkanes can give you every possible functional group. They can also help you in increasing the chain size. So you might want to convert your starting material to haloalkanes and then go to the desired product
✅Remember the series of oxidation/reduction: Hydrocarbons (with various substituents) can be oxidised to alcohols, then appropriate carbonyl compounds and lastly carboxylic acids (or their derivatives)
✅Strong oxidizing agents are KMnO4 and K2Cr2O7
✅Mild oxidising agents depending on the situation are CrO4, Ammoniacal AgNO3, Benedicts Solution, Fehling’s solution, Cu or CuO at 573K, Bromine water etc.
✅Any carboxylic acid derivative can be converted back to the carboxylic acid by hydrolysis.
✅There are possibilities of hydride and methyl to get the most stable intermediate (carbocation/free radical)
✅A most common reaction, if your starting material is an alkane, is free-radical halogenation.
✅Saytzeff/Markovnikov's rules must be kept in mind while dealing with alkenes (they are based on the electron displacement effects only)
✅Decarboxylation and ozonolysis could go-to methods for decreasing the number of carbon atoms
✅Grignard reagent gives you the much-needed Alkyl nucleophile, which can be used at appropriate places. | 2 139 |
| 17 | Attractants and rewards are required for | 2 063 |
| 18 | Cell Cycle & Cell Division Quiz | NEET NCERT Biology Class 11 Chapter 10 important questions MCQ
https://youtu.be/FuAgt5gmtLc
https://youtu.be/FuAgt5gmtLc | 1 979 |
| 19 | Biomolecules Quiz | Biology Class 11 Chapter 9 NCERT Important questions MCQ For NEET
https://youtu.be/0lw_PxkZazY
https://youtu.be/0lw_PxkZazY | 2 863 |
| 20 | Tricks for Conversions in Organic Chemistry
✅Haloalkanes can give you every possible functional group. They can also help you in increasing the chain size. So you might want to convert your starting material to haloalkanes and then go to the desired product
✅Remember the series of oxidation/reduction: Hydrocarbons (with various substituents) can be oxidised to alcohols, then appropriate carbonyl compounds and lastly carboxylic acids (or their derivatives)
✅Strong oxidizing agents are KMnO4 and K2Cr2O7
✅Mild oxidising agents depending on the situation are CrO4, Ammoniacal AgNO3, Benedicts Solution, Fehling’s solution, Cu or CuO at 573K, Bromine water etc.
✅Any carboxylic acid derivative can be converted back to the carboxylic acid by hydrolysis.
✅There are possibilities of hydride and methyl to get the most stable intermediate (carbocation/free radical)
✅A most common reaction, if your starting material is an alkane, is free-radical halogenation.
✅Saytzeff/Markovnikov's rules must be kept in mind while dealing with alkenes (they are based on the electron displacement effects only)
✅Decarboxylation and ozonolysis could go-to methods for decreasing the number of carbon atoms
✅Grignard reagent gives you the much-needed Alkyl nucleophile, which can be used at appropriate places. | 2 834 |
