Coding Interview Resources
This channel contains the free resources and solution of coding problems which are usually asked in the interviews. Managed by: @love_data
Show more📈 Analytical overview of Telegram channel Coding Interview Resources
Channel Coding Interview Resources (@crackingthecodinginterview) in the English language segment is an active participant. Currently, the community unites 52 248 subscribers, ranking 2 474 in the Technologies & Applications category and 6 815 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 52 248 subscribers.
According to the latest data from 26 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 31 over the last 30 days and by -3 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 1.85%. Within the first 24 hours after publication, content typically collects 0.76% reactions from the total number of subscribers.
- Post reach: On average, each post receives 966 views. Within the first day, a publication typically gains 398 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
- Thematic interests: Content is focused on key topics such as array, stack, algorithm, programming, sort.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“This channel contains the free resources and solution of coding problems which are usually asked in the interviews.
Managed by: @love_data”
Thanks to the high frequency of updates (latest data received on 27 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
class Node:
def __init__(self, data):
self.data = data
self.next = None
def reverse(head):
prev = None
current = head
while current:
next_node = current.next
current.next = prev
prev = current
current = next_node
return prev
🔹 Complexity
Time → O(n)
Space → O(1)
🔹 Interview Tip
This is one of the most important linked-list questions.
🚀 22. How do you detect a cycle in a linked list?
Use Floyd’s Cycle Detection Algorithm.
Also called: Tortoise and Hare Algorithm
🔹 Idea
• Slow pointer moves 1 step
• Fast pointer moves 2 steps
• If they meet → cycle exists
🔹 Python Solution
def has_cycle(head):
slow = fast = head
while fast and fast.next:
slow = slow.next
fast = fast.next.next
if slow == fast:
return True
return False
🔹 Complexity
Time → O(n)
Space → O(1)
🔹 Interview Tip
Very common interview question.
🚀 23. How do you find the middle node of a linked list?
Use two pointers.
🔹 Approach
• Slow pointer → moves 1 step
• Fast pointer → moves 2 steps
When fast reaches end:
slow = middle
🔹 Python Solution
def middle_node(head):
slow = fast = head
while fast and fast.next:
slow = slow.next
fast = fast.next.next
return slow
🔹 Complexity
Time → O(n)
Space → O(1)
🔹 Interview Tip
Two-pointer technique is heavily used in linked lists.
🚀 24. How do you merge two sorted linked lists?
🔹 Example
1 → 3 → 5
2 → 4 → 6
Merged:
1 → 2 → 3 → 4 → 5 → 6
🔹 Python Solution
def merge_lists(l1, l2):
dummy = Node(0)
current = dummy
while l1 and l2:
if l1.data < l2.data:
current.next = l1
l1 = l1.next
else:
current.next = l2
l2 = l2.next
current = current.next
current.next = l1 or l2
return dummy.next
🔹 Complexity
Time → O(n + m)
Space → O(1)
🔹 Interview Tip
This problem is the base concept behind merge sort on linked lists.
🚀 25. How do you find and remove a duplicate in a list?
🔹 Using HashSet
def remove_duplicates(head):
seen = set()
current = head
prev = None
while current:
if current.data in seen:
prev.next = current.next
else:
seen.add(current.data)
prev = current
current = current.next
return head
🔹 Complexity
Time → O(n)
Space → O(n)
🔹 Without Extra Space
Can also be solved using nested loops: O(n²)
🔹 Interview Tip
Interviewers may ask: Can you solve it without extra memory?
🚀 26. How do you implement a dummy head in linked-list problems?
A dummy node simplifies edge cases.
🔹 Why Useful?
Without dummy node: Handling head insertion/deletion becomes complex
With dummy node: Logic becomes cleaner
🔹 Example
dummy = Node(0)
dummy.next = head
🔹 Use Cases
✅ Remove nodes
✅ Merge lists
✅ Partition lists
✅ Reverse sublists
🔹 Interview Tip
Using dummy nodes often makes solutions cleaner and bug-free.
🚀 27. How do you delete a node given only that node (no head)?
Important constraint: No access to head pointer
🔹 Trick
Copy next node value into current node.
🔹 Python Solution
def delete_node(node):
node.data = node.next.data
node.next = node.next.next
🔹 Limitation
Cannot delete last node because no next node exists.
🔹 Interview Tip
Classic interview trick question.
🚀 28. How do you implement a circular linked list?
In a circular linked list: Last node → points to head instead of NULL.
🔹 Visualization
1 → 2 → 3
↑ ↓
← ← ← ←
🔹 Python Example
class Node:
def init(self, data):
self.data = data
self.next = None