Coding Interview Resources

Open in Telegram

This channel contains the free resources and solution of coding problems which are usually asked in the interviews. Managed by: @love_data

Network:Free Courses with Certificate - Python Programming, Data Science, Java Coding, SQL, Web Development, AI, ML, ChatGPT Expert India7 189 Technologies & Applications2 573...

📈 Analytical overview of Telegram channel Coding Interview Resources

Channel Coding Interview Resources (@crackingthecodinginterview) in the English language segment is an active participant. Currently, the community unites 52 168 subscribers, ranking 2 573 in the Technologies & Applications category and 7 189 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 52 168 subscribers.

According to the latest data from 13 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 174 over the last 30 days and by 29 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 2.17%. Within the first 24 hours after publication, content typically collects 0.87% reactions from the total number of subscribers.
Post reach: On average, each post receives 1 130 views. Within the first day, a publication typically gains 452 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
Thematic interests: Content is focused on key topics such as array, stack, algorithm, programming, sort.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“This channel contains the free resources and solution of coding problems which are usually asked in the interviews. Managed by: @love_data”

Thanks to the high frequency of updates (latest data received on 14 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

52 168

Subscribers

+2924 hours

+507 days

+17430 days

1 130

Post views

~ 45224 hours

~ 60648 hours

2.17%

Engagement rate

~ 1

Posts per day

Ads index

beta

Posts Archive

52 176

17. Offer + Negotiation.zip719.79 MB

52 176

18. Thank You.zip6.87 MB

52 176

19. Extras Google, Amazon, Facebook Interview Questions.zip11.04 MB

52 176

12. Algorithms Recursion.zip607.54 MB

52 176

16. Non Technical Interviews.zip865.17 MB

52 176

15. Algorithms Dynamic Programming.zip380.66 MB

52 176

14. Algorithms Searching + BFS + DFS.zip831.14 MB

52 176

11. Data Structures Graphs.zip331.20 MB

52 176

10. Data Structures Trees.zip875.77 MB

52 176

9. Data Structures Stacks + Queues.zip593.70 MB

52 176

8. Data Structures Linked Lists.zip873.77 MB

52 176

3. Big O.zip1062.69 MB

52 176

6. Data Structures Arrays.zip710.11 MB

52 176

4. How To Solve Coding Problems.zip718.22 MB

52 176

5. Data Structures Introduction.zip409.09 MB

52 176

7. Data Structures Hash Tables.zip706.64 MB

52 176

2. Getting More Interviews.zip1047.97 MB

52 176

1. Introduction.zip132.79 MB

52 176

🔰 Master the Coding Interview: Data Structures + Algorithms ⏱ 19.5 Hours 📦 258 Lessons Ultimate coding interview bootcamp. Get more job offers, negotiate a raise, and learn everything you need to get the job you want! Taught by: Andrei Neagoie Join @crackingthecodinginterview to learn with fun 👇👇

52 176

Solution: The first idea is to enumerate all permutations (either in lexicographical order, or sort them afterwards) and return the k-th one. But this is quite inefficient. Do we really need to generate permutations we don't care about? E.g. what if we need to return the last permutation of a string "abcd" do we need to generate permutations that start with "a"? Probably not, but can we compute what element the k-th permutation will start with? How many permutations will start with the smallest element in the array? The answer is (n-1)! Therefore, we can compute the first element of the permutation we need to compute. But wait, can we do the same for the second character? Yes we can! The number of permutations that start with the fixed first two characters are (n-2)!. So all we need to do is starting with the first character, compute what character will be on each position in the k-th permutation.