Coding Interview Resources
This channel contains the free resources and solution of coding problems which are usually asked in the interviews. Managed by: @love_data
Show more๐ Analytical overview of Telegram channel Coding Interview Resources
Channel Coding Interview Resources (@crackingthecodinginterview) in the English language segment is an active participant. Currently, the community unites 52 132 subscribers, ranking 2 574 in the Technologies & Applications category and 7 288 in the India region.
๐ Audience metrics and dynamics
Since its creation on ะฝะตะฒัะดะพะผะพ, the project has demonstrated rapid growth, gathering an audience of 52 132 subscribers.
According to the latest data from 04 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 183 over the last 30 days and by 8 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 1.84%. Within the first 24 hours after publication, content typically collects 0.82% reactions from the total number of subscribers.
- Post reach: On average, each post receives 960 views. Within the first day, a publication typically gains 425 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
- Thematic interests: Content is focused on key topics such as array, stack, algorithm, programming, sort.
๐ Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
โThis channel contains the free resources and solution of coding problems which are usually asked in the interviews.
Managed by: @love_dataโ
Thanks to the high frequency of updates (latest data received on 05 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
function findDuplicates(arr) {
const seen = new Set();
const dups = new Set();
for (let num of arr) {
if (seen.has(num)) dups.add(num);
else seen.add(num);
}
return Array.from(dups);
}
Space optimized: Sort O(n log n) then scan adjacent equals.
๐ 5๏ธโฃ What is binary search and when would you use it?
โ
Answer:
Binary search finds target in sorted array in O(log n) by repeatedly dividing search interval in half:
mid = (left + right) / 2
If arr[mid] == target return mid
If arr[mid] < target search right half
Else search left half
Use when: Data naturally sorted or sorting cost acceptable. Iterative version avoids recursion stack overflow.
๐ 6๏ธโฃ How do you reverse a linked list?
โ
Answer:
Iterative O(n) solution flipping next pointers:function reverseList(head) {
let prev = null, curr = head;
while (curr) {
let nextTemp = curr.next;
curr.next = prev;
prev = curr;
curr = nextTemp;
}
return prev;
}
Recursive: reverseList(curr.next).then(curr.next.prev = curr, curr.next = null).
๐ 7๏ธโฃ What is recursion and why is the base case important?
โ
Answer:
Recursion is a function calling itself with modified arguments until base case stops it. Without base case โ stack overflow.
Example Fibonacci:function fib(n) {
if (n <= 1) return n; // Base case
return fib(n-1) + fib(n-2);
}
Memoization optimizes overlapping subproblems.
๐ 8๏ธโฃ How do you merge two sorted arrays?
โ
Answer:
Two-pointer technique O(n+m):function mergeSorted(a1, a2) {
let i=0, j=0, result = [];
while (i < a1.length && j < a2.length) {
if (a1[i] < a2[j]) result.push(a1[i++]);
else result.push(a2[j++]);
}
return result.concat(a1.slice(i)).concat(a2.slice(j));
}
Handles unequal lengths cleanly.
๐ง 9๏ธโฃ How do you detect a cycle in a linked list?
โ
Answer:
Floyd's Tortoise & Hare: Slow moves 1 step, fast moves 2. If they meet โ cycle.
To find start: Reset slow to head, move both 1 step until meet.function hasCycle(head) {
let slow = head, fast = head;
while (fast && fast.next) {
slow = slow.next;
fast = fast.next.next;
if (slow === fast) return true;
}
return false;
}5 == '5' is true, but 5 === '5' is false.
3๏ธโฃ Q: Explain the Box Model in CSS.
A: The CSS Box Model consists of:
- *Content* โ The actual text/image
- *Padding* โ Space around content
- *Border* โ Around the padding
- *Margin* โ Space outside the border
4๏ธโฃ Q: What are the different HTTP methods?
A: Common methods:
- *GET* โ Retrieve data
- *POST* โ Send data
- *PUT* โ Update existing data
- *DELETE* โ Remove data
5๏ธโฃ Q: What is the difference between null and undefined in JavaScript?
A:
- null โ Assigned value meaning โno valueโ
- undefined โ A variable that has been declared but not assigned a value
6๏ธโฃ Q: What is responsive design?
A: It makes web pages look good on all devices (mobile, tablet, desktop) using CSS media queries and flexible layouts.
7๏ธโฃ Q: What is the role of JavaScript in web development?
A: JavaScript adds interactivity to web pages โ like dropdowns, sliders, form validation, etc.
8๏ธโฃ Q: What is DOM?
A: The Document Object Model represents the page structure in a tree format, allowing JavaScript to interact with and manipulate HTML/CSS dynamically.
๐ Tap โค๏ธ for more!Dear [Recruiterโs Name],
I hope this email finds you doing well. I wanted to take a moment to express my sincere gratitude for the time and consideration you have given me throughout the recruitment process for the [position] role at [company].
I understand that you must be extremely busy and receive countless applications, so I wanted to reach out and follow up on the status of my application. If itโs not too much trouble, could you kindly provide me with any updates or feedback you may have?
I want to assure you that I remain genuinely interested in the opportunity to join the team at [company] and I would be honored to discuss my qualifications further. If there are any additional materials or information you require from me, please donโt hesitate to let me know.
Thank you for your time and consideration. I appreciate the effort you put into recruiting and look forward to hearing from you soon.
Warmest regards,
(Tap to copy)
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