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đGK STUDY GUIDEâĸđ
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đ www.gkstudyguide.com āĻāĻāĻŋā§ā§ āĻĨāĻžāĻā§ - āĻāĻāĻŋā§ā§ āĻ°āĻžāĻā§ đAll Type Job Releted Study Material Share Here. đđđđđđđđ đ§For Promotion Contact Us:: 9800351351 (Only Whatsapp)
Show moređ Analytical overview of Telegram channel đGK STUDY GUIDEâĸđ
Channel đGK STUDY GUIDEâĸđ (@gkstudyguide) in the Bengali language segment is an active participant. Currently, the community unites 16 815 subscribers, ranking 11 963 in the Education category and 1 331 in the Bangladesh region.
đ Audience metrics and dynamics
Since its creation on ĐŊĐĩвŅĐ´ĐžĐŧĐž, the project has demonstrated rapid growth, gathering an audience of 16 815 subscribers.
According to the latest data from 01 July, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -186 over the last 30 days and by -2 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 7.48%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
đ Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
âđ www.gkstudyguide.com
āĻāĻāĻŋā§ā§ āĻĨāĻžāĻā§ - āĻāĻāĻŋā§ā§ āĻ°āĻžāĻā§
đAll Type Job Releted Study Material Share Here.
đđđđđđđđ
đ§For Promotion Contact Us:: 9800351351 (Only Whatsapp)â
Thanks to the high frequency of updates (latest data received on 02 July, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
16 815
Subscribers
-224 hours
-607 days
-18630 days
Posts Archive
Q. āĻ¸āĻ°ā§āĻŦāĻžāĻ§āĻŋāĻ āĻļāĻā§āĻ¤āĻŋāĻļāĻžāĻ˛ā§ āĻā§āĻ¯āĻŧāĻžāĻ° āĻ¸āĻāĻāĻāĻŋāĻ¤ āĻšāĻ¯āĻŧ â
Q. āĻŽāĻŋāĻ˛āĻŋāĻ¯āĻŧāĻ¨ āĻļāĻŋāĻā§ āĻā§āĻŦā§āĻāĻŋāĻ¤ā§āĻ°āĻ¸ā§āĻāĻ āĻŽāĻžāĻ¨āĻāĻŋāĻ¤ā§āĻ°ā§āĻ° āĻ
āĻā§āĻˇāĻžāĻāĻļ āĻ āĻĻā§āĻ°āĻžāĻāĻŋāĻŽāĻžāĻāĻ¤ āĻŦāĻŋāĻ¸ā§āĻ¤āĻžāĻ° â
Q. āĻāĻžāĻ°āĻ¤ā§ āĻŦā§āĻšāĻ¤ā§āĻ¤āĻŽ āĻŦāĻšā§āĻŽā§āĻā§ āĻ¨āĻĻā§ āĻĒāĻ°āĻŋāĻāĻ˛ā§āĻĒāĻ¨āĻž āĻšāĻ˛ â
Q. āĻļā§āĻ¤āĻ˛ āĻ˛ā§āĻ¯āĻžāĻŦā§āĻ°āĻžāĻĄāĻ° āĻ¸ā§āĻ°ā§āĻ¤ āĻāĻŦāĻ āĻāĻˇā§āĻŖ āĻāĻĒāĻ¸āĻžāĻāĻ°ā§āĻ¯āĻŧ āĻ¸ā§āĻ°ā§āĻ¤ āĻŽāĻŋāĻ˛āĻŋāĻ¤ āĻšāĻ¯āĻŧā§ āĻāĻ¨āĻā§āĻ¯āĻŧāĻžāĻļāĻž āĻ āĻāĻĄāĻŧāĻāĻā§āĻāĻžāĻ° āĻ¸ā§āĻˇā§āĻāĻŋ āĻāĻ°ā§ āĻ¯ā§ āĻāĻĒāĻā§āĻ˛ āĻ
āĻā§āĻāĻ˛ā§ āĻ¤āĻž āĻšāĻ˛ â
Q. āĻāĻžāĻ°āĻ¤ āĻĨā§āĻā§ āĻĒā§āĻ°ā§āĻ°āĻŋāĻ¤ āĻā§āĻ¤ā§āĻ°āĻŋāĻŽ āĻāĻĒāĻā§āĻ°āĻš â
Q. āĻŽāĻ°āĻž āĻā§āĻāĻžāĻ˛ā§āĻ° āĻ¸āĻŽāĻ¯āĻŧ āĻāĻ¨ā§āĻĻā§āĻ° āĻ āĻ¸ā§āĻ°ā§āĻ¯ āĻĒā§āĻĨāĻŋāĻŦā§āĻ° āĻāĻĒā§āĻā§āĻˇā§ āĻāĻ¤ āĻĄāĻŋāĻā§āĻ°āĻŋ āĻā§āĻŖ āĻāĻ°ā§ āĻĨāĻžāĻā§ ?
Q. āĻāĻ˛ āĻ¨āĻŋāĻ¨ā§āĻ° āĻĒā§āĻ°āĻāĻžāĻŦ āĻĻā§āĻāĻž āĻ¯āĻžāĻ¯āĻŧ â
Q. āĻāĻžāĻ°āĻ¤ā§āĻ° āĻ¨āĻŦā§āĻ¨āĻ¤āĻŽ āĻ°āĻžāĻā§āĻ¯āĻāĻŋ āĻšāĻ˛ â
Q. āĻāĻžāĻ°āĻ¤ā§ āĻŽā§āĻ¤ā§āĻ¤āĻŋāĻāĻž āĻ¸āĻāĻ°āĻā§āĻˇāĻŖā§āĻ° āĻāĻāĻāĻŋ āĻĒāĻĻā§āĻ§āĻ¤āĻŋ āĻšāĻ˛ â
Q. āĻāĻžāĻ°āĻ¤ā§āĻ° āĻĻā§āĻ°ā§āĻāĻ¤āĻŽ āĻāĻžāĻ¤ā§āĻ¯āĻŧ āĻ¸āĻĄāĻŧāĻāĻĒāĻĨ āĻšāĻ˛ â
Q. āĻāĻžāĻ°āĻ¤ā§āĻ° āĻāĻāĻāĻŋ āĻ¸ā§āĻĨāĻžāĻ¨ā§āĻ¯āĻŧ āĻŦāĻžāĻ¯āĻŧā§ āĻšāĻ˛ â
Q. āĻāĻŽā§āĻ° āĻāĻāĻāĻŋ āĻāĻā§āĻ āĻĢāĻ˛āĻ¨āĻļā§āĻ˛ āĻŦā§āĻ āĻšāĻ˛ â
Q. āĻāĻļāĻŋāĻ¯āĻŧāĻžāĻ° āĻŦā§āĻšāĻ¤ā§āĻ¤āĻŽ āĻ˛ā§āĻā§āĻ¨ āĻšāĻ˛ â
Q. āĻāĻ¨ā§āĻ¨āĻ¯āĻŧāĻ¨ā§āĻ° āĻā§āĻŦāĻ¨āĻ°ā§āĻāĻž āĻŦāĻ˛āĻž āĻšāĻ¯āĻŧ â
Q. āĻāĻ˛ āĻĒā§āĻ°āĻĒāĻžāĻ¤ā§āĻ° āĻĒāĻžāĻĻāĻĻā§āĻļā§ āĻāĻ āĻŋāĻ¤ āĻā§āĻŽāĻŋāĻ°ā§āĻĒāĻāĻŋ āĻšāĻ˛ â
Q. āĻāĻžāĻ°āĻ¤ā§āĻ° āĻĻāĻā§āĻˇāĻŋāĻŖāĻ¤āĻŽ āĻ¸ā§āĻĨāĻ˛āĻŦāĻŋāĻ¨ā§āĻĻā§ â
đ° āĻ°āĻžāĻ¸āĻžā§āĻ¨āĻŋāĻ āĻ¨āĻžāĻŽ āĻ āĻ¸āĻāĻā§āĻ¤
āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¨ = H2
āĻ
āĻā§āĻ¸āĻŋāĻā§āĻ¨ = O2
āĻ¨āĻžāĻāĻā§āĻ°ā§āĻā§āĻ¨ = N2
āĻā§āĻ˛ā§āĻ°āĻŋāĻ¨ = CI2
āĻŦā§āĻ°ā§āĻŽāĻŋāĻ¨ = Br2
āĻāĻžāĻ°ā§āĻŦāĻ¨ āĻĄāĻžāĻ āĻ
āĻā§āĻ¸āĻžāĻāĻĄ = CO2
āĻāĻ˛ = H2O
āĻĒā§āĻĄāĻŧāĻžāĻā§āĻ¨(āĻā§āĻ¯āĻžāĻ˛āĻļāĻŋāĻ¯āĻŧāĻžāĻŽ āĻ
āĻā§āĻ¸āĻžāĻāĻĄ) = CaO
āĻāĻ˛āĻŋāĻā§āĻ¨(āĻā§āĻ¯āĻžāĻ˛āĻļāĻŋāĻ¯āĻŧāĻžāĻŽ āĻšāĻžāĻāĻĄā§āĻ°āĻā§āĻ¸āĻžāĻāĻĄ) = Ca(OH)2
āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ˛ā§āĻ°āĻŋāĻ āĻ
ā§āĻ¯āĻžāĻ¸āĻŋāĻĄ = HCl
āĻ¸āĻžāĻ˛āĻĢāĻŋāĻāĻ°āĻŋāĻ āĻ
ā§āĻ¯āĻžāĻ¸āĻŋāĻĄ = H2SO4
āĻ¨āĻžāĻāĻā§āĻ°āĻŋāĻ āĻ
ā§āĻ¯āĻžāĻ¸āĻŋāĻĄ = HNO3
āĻāĻžāĻŦāĻžāĻ° āĻ˛āĻŦāĻ¨(āĻ¸ā§āĻĄāĻŋāĻ¯āĻŧāĻžāĻŽ āĻā§āĻ˛ā§āĻ°āĻžāĻāĻĄ) = NaCl
āĻŽāĻŋāĻĨā§āĻ¨ = CH4
āĻ
ā§āĻ¯āĻžāĻŽā§āĻ¨āĻŋā§āĻž = NH3
āĻŽāĻŋāĻĨāĻžāĻ¨āĻ˛ =CH3OH
āĻāĻĨāĻžāĻ¨āĻ˛ = CH3CH2OH
āĻĒā§āĻ°ā§āĻĒāĻžāĻ¨āĻ˛ = CH3CH2CH2OH
āĻ¤ā§āĻāĻ¤ā§ = CuSO4.5H2O
āĻāĻžāĻŦāĻžāĻ° āĻ¸ā§āĻĄāĻž = NaHCO3
āĻ¸ā§āĻĄāĻŋā§āĻžāĻŽ āĻāĻžāĻ°ā§āĻŦāĻ¨ā§āĻ = Na2CO3
āĻŦā§āĻ¨āĻāĻŋāĻ¨ = C6H6
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āĻŽā§āĻ¯āĻžāĻāĻ¨ā§āĻ¸āĻŋā§āĻžāĻŽ āĻ
āĻā§āĻ¸āĻžāĻāĻĄ = MgO
āĻā§āĻ¨āĻžāĻĒāĻžāĻĨāĻ°(āĻā§āĻ¯āĻžāĻ˛āĻļāĻŋāĻ¯āĻŧāĻžāĻŽ āĻāĻžāĻ°ā§āĻŦāĻ¨ā§āĻ) = CaCO3
āĻā§āĻ¯āĻžāĻ˛āĻ¸āĻŋāĻ¯āĻŧāĻžāĻŽ āĻā§āĻ˛ā§āĻ°āĻžāĻāĻĄ = CaCl2
āĻĒāĻāĻžāĻ¸āĻŋā§āĻžāĻŽ āĻĒāĻžāĻ°āĻŽā§āĻ¯āĻžāĻā§āĻāĻžāĻ¨ā§āĻ = KMnO4
āĻĒāĻāĻžāĻ¸āĻŋā§āĻžāĻŽ āĻĄāĻžāĻāĻā§āĻ°ā§āĻŽā§āĻ = K2Cr2O7
āĻāĻŋāĻāĻ āĻ¸āĻžāĻ˛āĻĢā§āĻ = ZnSO4
āĻā§āĻ¯āĻžāĻ˛āĻ¸āĻŋāĻ¯āĻŧāĻžāĻŽ āĻ¸āĻžāĻ˛āĻĢā§āĻ = CaSO4
āĻā§āĻ¯āĻžāĻ˛āĻ¸āĻŋāĻ¯āĻŧāĻžāĻŽ āĻĢāĻ¸āĻĢā§āĻ = Ca3(PO4)2
āĻŽā§āĻ¯āĻžāĻāĻ¨ā§āĻ¸āĻŋā§āĻžāĻŽ āĻ¸āĻžāĻ˛āĻĢā§āĻ = MgSO4
āĻŽā§āĻ¯āĻžāĻāĻ¨ā§āĻ¸āĻŋā§āĻžāĻŽ āĻĢāĻ¸āĻĢā§āĻ = Mg3(PO4)2
āĻ¸ā§āĻĄāĻŋā§āĻžāĻŽ āĻ¸āĻžāĻ˛āĻĢā§āĻ = Na2SO4
āĻĢāĻ¸āĻĢāĻ°āĻžāĻ¸ āĻā§āĻ°āĻžāĻ āĻā§āĻ˛ā§āĻ°āĻžāĻāĻĄ = PCl3
āĻĢāĻ¸āĻĢāĻ°āĻžāĻ¸ āĻĒā§āĻ¨ā§āĻāĻž āĻā§āĻ˛ā§āĻ°āĻžāĻāĻĄ = PCl5
āĻ¸āĻžāĻ˛āĻĢāĻžāĻ° āĻā§āĻ°āĻžāĻ āĻ
āĻā§āĻ¸āĻžāĻāĻĄ = SO3
āĻāĻŋāĻ˛āĻŋ āĻ¸āĻ˛ā§āĻāĻĒāĻŋāĻāĻžāĻ°(āĻ¸ā§āĻĄāĻŋā§āĻžāĻŽ āĻ¨āĻžāĻāĻā§āĻ°ā§āĻ) = NaNO3
āĻ¸ā§āĻĄāĻŋā§āĻžāĻŽ āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¸āĻžāĻāĻĄ = NaOH
āĻĒāĻāĻžāĻļāĻŋāĻ¯āĻŧāĻžāĻŽ āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¸āĻžāĻāĻĄ = KOH
āĻ¸āĻŋāĻ˛āĻāĻžāĻ° āĻ
āĻā§āĻ¸āĻžāĻāĻĄ = Ag2O
āĻ¸āĻŋāĻ˛āĻāĻžāĻ° āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¸āĻžāĻāĻĄ = AgOH
āĻāĻ˛ā§āĻ¨ā§āĻ¸ āĻŦāĻŋāĻāĻžāĻ°āĻ = [Ag(NO3)2]+
āĻŽāĻŋāĻĨāĻžāĻ¨ā§āĻ¯āĻžāĻ˛ = HCHO
āĻāĻĨāĻžāĻ¨ā§āĻ¯āĻžāĻ˛ = CH3CHO
āĻāĻĨāĻžāĻ¨ā§ā§āĻŋāĻ āĻ
ā§āĻ¯āĻžāĻ¸āĻŋāĻĄ = CH3COOH
āĻ¸āĻŋāĻ˛āĻŋāĻāĻ¨
āĻā§āĻā§āĻāĻžāĻā§āĻ˛ā§āĻ°āĻžāĻāĻĄ = SiCl4
āĻ
ā§āĻ¯āĻžāĻ˛ā§āĻŽāĻŋāĻ¨āĻŋā§āĻžāĻŽ āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¸āĻžāĻāĻĄ = Al(OH)3
āĻ¸āĻŋāĻ˛āĻŋāĻāĻ¨ āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¸āĻžāĻāĻĄ = Si(OH)4
āĻĄāĻžāĻāĻŽāĻŋāĻĨāĻžāĻāĻ˛ āĻāĻĨāĻžāĻ° = CH3-O-CH3
āĻ
ā§āĻ¯āĻžāĻŽā§āĻ¨āĻŋā§āĻž āĻ¸āĻžā§āĻžāĻ¨ā§āĻ = NH4CNO
āĻāĻāĻ°āĻŋā§āĻž = NH2-CO-NH2
āĻŽāĻ°āĻŋāĻāĻž = Fe2O3.nH2O
āĻā§āĻ˛ā§āĻā§āĻ = C6H12O6
āĻŽā§āĻ¯āĻžāĻāĻ¨ā§āĻļāĻŋāĻ¯āĻŧāĻžāĻŽ āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¸āĻžāĻāĻĄ = Mg(OH)2
āĻ
ā§āĻ¯āĻžāĻ˛ā§āĻŽāĻŋāĻ¨āĻŋā§āĻžāĻŽ āĻ¸āĻžāĻ˛āĻĢā§āĻ = Al2(SO4)3
āĻ
ā§āĻ¯āĻžāĻ¸āĻŋāĻāĻŋāĻ āĻ
ā§āĻ¯āĻžāĻ¸āĻŋāĻĄ = CH3COOH
āĻĢā§āĻ°āĻžāĻ¸ āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¸āĻžāĻāĻĄ = Fe(OH)2
āĻāĻĨāĻžāĻāĻ˛ āĻā§āĻ˛ā§āĻ°āĻžāĻāĻĄ = CH3CH2Cl
āĻāĻāĻ¨ = O3
āĻāĻžāĻ°ā§āĻŦāĻ¨ āĻŽāĻ¨ā§āĻ
āĻā§āĻ¸āĻžāĻāĻĄ = CO
āĻ¸āĻžāĻ˛āĻĢāĻžāĻ° āĻĄāĻžāĻ āĻ
āĻā§āĻ¸āĻžāĻāĻĄ = SO2
āĻ
ā§āĻ¯āĻžāĻ˛ā§āĻŽāĻŋāĻ¨āĻŋā§āĻžāĻŽ āĻā§āĻ˛ā§āĻ°āĻžāĻāĻĄ = NH4Cl
āĻāĻŋāĻāĻ āĻā§āĻ˛ā§āĻ°āĻžāĻāĻĄ = ZnCl2
āĻŽāĻžāĻ°āĻāĻŋāĻāĻ°āĻžāĻ¸ āĻ
āĻā§āĻ¸āĻžāĻāĻĄ = Hg2O
āĻ˛āĻŋāĻĨāĻŋā§āĻžāĻŽ āĻā§āĻŦāĻžāĻ˛ā§āĻ āĻ
āĻā§āĻ¸āĻžāĻāĻĄ = LiCoO2
āĻ˛ā§āĻĄ āĻ
āĻā§āĻ¸āĻžāĻāĻĄ = PbO2
āĻŽā§āĻ¯āĻžāĻā§āĻāĻžāĻ¨āĻŋāĻ āĻĄāĻžāĻ āĻ
āĻā§āĻ¸āĻžāĻāĻĄ = MnO2
āĻŽā§āĻ¯āĻžāĻāĻ¨ā§āĻļāĻŋāĻ¯āĻŧāĻžāĻŽ āĻā§āĻ˛ā§āĻ°āĻžāĻāĻĄ = MgCl2
āĻ¨āĻžāĻāĻā§āĻ°āĻžāĻ¸ āĻ
ā§āĻ¯āĻžāĻ¸āĻŋāĻĄ = HNO2
āĻ¨āĻžāĻāĻā§āĻ°ā§āĻā§āĻ¨ āĻĄāĻžāĻ āĻ
āĻā§āĻ¸āĻžāĻāĻĄ = NO2
āĻĢā§āĻ°āĻŋāĻ āĻā§āĻ˛ā§āĻ°āĻžāĻāĻĄ = FeCl3
āĻĢā§āĻ°āĻžāĻ¸ āĻā§āĻ˛ā§āĻ°āĻžāĻāĻĄ = FeCl2
āĻ
ā§āĻ¯āĻžāĻ¸āĻŋāĻā§āĻ¨ = CH3COCH3
āĻŽāĻŋāĻĨāĻžāĻ¨ā§āĻ¯āĻŧāĻŋāĻ āĻ
ā§āĻ¯āĻžāĻ¸āĻŋāĻĄ = HCOOH
āĻāĻĨā§āĻ¨ = C2H6
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