8 113
Subscribers
No data24 hours
No data7 days
-3830 days
Posts Archive
8 113
🎯Deloitte is hiring for EERM
*Location:- Bengaluru, *Hyderabad,gurugram
*Qualification:- BTech/MBA/MCA
*Batch:-2018/2019/2020/2021/2022
*Salary:- 6LPA
Apply:- https://www.joboffersadda.com/2022/05/deloitte.html
Telegram:-@Infosys_Ans
8 113
GlobalLogic is Hiring
Qualifications: B.Tech /B.E / M.Tech/MCA
Branch: CSE, IT, ECE and aligned Branches
Experience: Fresher's to 1 Year
Percentage Criteria: 60% or more starting from 10th until degree
CTC: 4.74 LPA
Apply:-https://www.joboffersadda.com/2022/05/globallogic-off-campus-recruitment-for.html
Job Location: Bangalore
Telegram:-@allcoding1
8 113
Repost from allcoding1_official
def flip( ch):
return '1' if (ch == '0') else '0'
# Utility method to get minimum flips when
# alternate string starts with expected char
def getFlipWithStartingCharcter(str, expected):
flipCount = 0
for i in range(len( str)):
# if current character is not expected,
# increase flip count
if (str[i] != expected):
flipCount += 1
# flip expected character each time
expected = flip(expected)
return flipCount
# method return minimum flip to make binary
# string alternate
def minFlipToMakeStringAlternate(str):
# return minimum of following two
# 1) flips when alternate string starts with 0
# 2) flips when alternate string starts with 1
return min(getFlipWithStartingCharcter(str, '0'),
//allcoding1 getFlipWithStartingCharcter(str, '1'))
//allcoding1
# Driver code to test above method
if name == "main":
str = "0001010111"
print(minFlipToMakeStringAlternate)
Flip or swap code in Python
Telegram:-@allcoding1
8 113
Repost from allcoding1_official
// Java program to find the XOR of
// all elements in the array
class GFG {
// Function to find the XOR of
// all elements in the array
static int xorOfArray(int arr[], int n)
{
// Resultant variable
int xor_arr = 0;
// Iterating through every element in
// the array
for (int i = 0; i < n; i++) {
// Find XOR with the result
xor_arr = xor_arr ^ arr[i];
}
// Return the XOR
return xor_arr;
}
// Driver Code
public static void main (String[] args)
{
int arr[] = { 3, 9, 12, 13, 15 };
int n = arr.length;
// allcoding1
System.out.println(xorOfArray(arr, n));
}
}
Prifix XOR code in Java
Telegram - @allcoding1
8 113
Repost from allcoding1_official
#include <iostream>
using namespace std;
#define ll long long examcell
ll qdSum(ll n){
if (n==0){
return 0;
}
return ((n%10)*(n%10)*(n%10)*(n%10)) + qdSum(n/10);
}
ll getProduct(ll n){
// Base Case
if(n == 0){
return 1 ;
}
// get the last digit and multiply it with remaining digits
return (n%10) * getProduct(n/10) ;
} examcell
ll gcd(ll a, ll b)
{
return b == 0 ? a : gcd(b, a % b);
}
bool isSpecial(ll N){
if(gcd(qdSum(N),getProduct(N)) > 1){
return 1;
}
return 0;
}
int main() {
int T;
cin>>T;
while(T--){
ll N;
cin>>N;
int count=0;
while(N != 1){
if(isSpecial(N)){
count++;
}
N--;
}
cout<<count<<endl;
}
}
C++
Telegram - @allcoding1
8 113
Repost from allcoding1_official
#include <iostream>
using namespace std;
class gas {
public:
int gas;
int distance;
};
int findStartIndex(gas stationQueue[], int n) {
int start_point = 0;
int end_point = 1;
int curr_gas = stationQueue [start_point].gas - stationQueue [start_point].distance;
while (end_point != start_point || curr_gas < 0) {
while (curr_gas < 0 && start_point != end_point) {
curr_gas -= stationQueue[start_point].gas - stationQueue
//allcoding1
[start_point].distance;
start_point = (start_point + 1) % n;
if (start_point == 0)
return -1;
}
curr_gas += stationQueue[end_point].gas - stationQueue [end_point].distance;
end_point = (end_point + 1) % n;
}
return start_point;
}
int main() {
gas gasArray[] = {{4, 6}, {6, 5}, {7, 3}, {4, 5}};
int n = sizeof(gasArray)/sizeof(gasArray [0]);
int start = findStartIndex(gasArray, n);
if(start == -1)
cout<<"No solution";
else
cout<<"Index of first gas station : "<<start;
}
GAS STATION
C++
Telegram - @allcoding1
8 113
Repost from allcoding1_official
def flip( ch):
return '1' if (ch == '0') else '0'
# Utility method to get minimum flips when
# alternate string starts with expected char
def getFlipWithStartingCharcter(str, expected):
flipCount = 0
for i in range(len( str)):
# if current character is not expected,
# increase flip count
if (str[i] != expected):
flipCount += 1
# flip expected character each time
expected = flip(expected)
return flipCount
# method return minimum flip to make binary
# string alternate
def minFlipToMakeStringAlternate(str):
# return minimum of following two
# 1) flips when alternate string starts with 0
# 2) flips when alternate string starts with 1
return min(getFlipWithStartingCharcter(str, '0'),
//allcoding1 getFlipWithStartingCharcter(str, '1'))
# Driver code to test above method
if name == "main":
str = "0001010111"
print(minFlipToMakeStringAlternate)
Python
Telegram - @allcoding1
8 113
INFOSYS, TATA STEEL EXAM ANSWERS (23/4/22)
All Slot
INFOSYS:- http://www.joboffersadda.com/2022/01/infosys-exam-answer.html
TATA STEEL:- http://www.joboffersadda.com/2022/04/tata-steel-exam-ans.html
Telegram - @Infosys_Ans
🔔Unmute this channel to never miss any updates
8 113
Sec 2 - techinal ability
Q1) median of terms
7
C
Q2) avarege of eleven
20
B
Q3) x y means
N p $
C
Q4) Five brothers
B
Muliplex
Q5) harsh
4 days
A
Q6) a fruit
1900
C
Q7) if m n
East
B
Q8) if the second
S
D
Infosys exam Ans
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
8 113
1q)which year born
2 alone
D
2q)profit or loss
Both I nd ii
D
3)q)discount percentage
21500
B
4q)Raghav family
Both I nd ii
D
5)q) population of uttar pradesh
20500
C
7q) sirman failed
Both I nd ii follows
C
8q) some jockets
Some coats
A
9)q) some lines
Some cones
D
10q)conlcusions
Only ii follows
C
11)statement a<b
F>b
C
Infosys exam Ans
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
8 113
Repost from allcoding1_official
477400
Infosys exam Ans
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
8 113
Repost from allcoding1_official
4000
Infosys exam Ans
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
8 113
Repost from allcoding1_official
62500
Infosys exam Ans
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
8 113
Repost from allcoding1_official
3 And after 1 Or 2
Infosys exam Ans
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
8 113
Repost from allcoding1_official
85
Infosys exam Ans
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
8 113
Repost from allcoding1_official
Some second are bikes
Infosys exam Ans
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
8 113
Repost from allcoding1_official
22500
Infosys exam Ans
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
8 113
Repost from allcoding1_official
33.33%
Infosys exam Ans
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
8 113
1q)which year born
2 alone
D
2q)profit or loss
Both I nd ii
D
3)q)discount percentage
21500
B
4q)Raghav family
Both I nd ii
D
5)q) population of uttar pradesh
20500
C
Infosys exam Ans
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
