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Number Of Subsequences Code For Infosys int A[] = {10,13,7,8,14,11}; int n = 6; int memo[6];//initialized with -1s; int count(int currIndex){ if (currIndex == n-1) return 1; if (memo[currIndex] != -1) return memo[currIndex]; int res = 0; for (int i=currIndex+1 ; i<n ; i++){ if (abss(A[currIndex] - A[i]) <= 3){ res += count(i); } } memo[currIndex] = res; return res; } c++ Telegram:- @Infosys_Ans

Infosys exam Ans 29/7/22 at 10AM http://www.joboffersadda.com/2022/01/infosys-exam-answer.html http://www.joboffersadda.com/2022/01/infosys-exam-answer.html Allcoding Ans are available Telegram:- @Infosys_Ans

n = int(input()) A = int(input()) A1 = [] A2= [] A3= [] ans = 0 for i in range(n): A1.append(int(input())) for j in range(n): A2.append(int(input())) for k in range(n): A2.append([p[k], b[k]]) a.sort() for z in a: if a[0] > N: break N += a[1] ans += 1 print(ans) Try this code for this question... Python 3 Telegram:-

Infosys exam Ans 29/7/22 at 10AM http://www.joboffersadda.com/2022/01/infosys-exam-answer.html http://www.joboffersadda.com/2022/01/infosys-exam-answer.html Allcoding Ans are available Telegram:- @Infosys_Ans

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