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Infosys exam Ans 30/7/22 at 10AM http://www.joboffersadda.com/2022/01/infosys-exam-answer.html http://www.joboffersadda.com/2022/01/infosys-exam-answer.html Allcoding Ans are available Telegram:- @Infosys_Ans

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Infosys exam Ans 29/7/22 at 10AM http://www.joboffersadda.com/2022/01/infosys-exam-answer.html http://www.joboffersadda.com/2022/01/infosys-exam-answer.html Allcoding Ans are available Telegram:- @Infosys_Ans

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Lexographically smallest question code in C++ 17 Telegram:-

array AR of size N perfect_sum(arr, s, result) : x = [0]*len(arr) j = len(arr) - 1 while (s > 0) : x[j] = s % 2 s = s // 2 j -= 1 sum = 0 for i in range(len(arr)) : if (x[i] == 1) : sum += arr[i] if (sum == result) : print("{",end=""); for i in range(len(arr)) : if (x[i] == 1) : print(arr[i],end= ", "); print("}, ",end="") def print_subset(arr, K) : x = pow(2, len(arr)) for i in range(1, x): perfect_sum(arr, i, K) # Driver code arr = [ ] n = int(input("Enter length of array : ")) s=int(input("Enter sum : ")) for i in range(n): ele=int(input("Enter element : ")) arr.append(ele) print_subset(arr, s) Python Telegram :- @allcoding1_official

class CountOccurrences { public static void main(String[] args) { String str = "aabbccd"; char a[]=str.toCharArray(); int cnt = 0; for (int i = 0; i < a.length; i++) { for (int j = i + 1; j < a.length; j++) { if ((a[i] == a[j])) { cnt++; } } } System.out.println(cnt); } } Java Telegram:- @allcoding1_official