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allcoding1_official

allcoding1_official

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📈 Analytical overview of Telegram channel allcoding1_official

Channel allcoding1_official (@allcoding1_official) in the English language segment is an active participant. Currently, the community unites 78 877 subscribers, ranking 1 622 in the Technologies & Applications category and 3 839 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 78 877 subscribers.

According to the latest data from 27 October, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -1 611 over the last 30 days and by -26 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 2.10%. Within the first 24 hours after publication, content typically collects 0.61% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 659 views. Within the first day, a publication typically gains 478 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
  • Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, dev.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 28 October, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

78 877
Subscribers
-2624 hours
-3827 days
-1 61130 days
Posts Archive
4690

Small program

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Reopening ans👇

Near

Only conclusion I follow

Husband

Cat : feline

F

Accenture exam Answer 2/4/24 1) I got sick, I have _ As) an 2) A) but everyone B) government C) an should D) global.. As) DBAC 3) ocean : shallow As) infinite 4) I comb my hair.... As) I used to 5) antonym word " ACCURATE " As) invalid 6) Continue As) prolong 7) we felt____missing the farewell party As) didn't feel good @allcoding1_official 8) horizontal bar represent As) date input/output 9) charvi is the mother of sara... As) sister in law 10) by the time we arrived they____ (to leave) As) had left 11) 1) it is possible to determine.... 2) no other mobile brand.... As) both conclusion follow Telegram:- @allcoding1_official

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int main() {     string text;     getline(cin, text);     int index = 0;  &
int main() {     string text;     getline(cin, text);     int index = 0;     while (index + 13 < text.length() && (index = text.rfind(" ", index + 13)) != string::npos) {         text.replace(index, 1, "\n");     }     cout << text << endl;     return 0; } INFA thon 4.0

#include using namespace std; typedef long long LL; #define max_v 25 bool f(double A,double B,double a,double b) { &nbsp;&nbs
#include<bits/stdc++.h> using namespace std; typedef long long LL; #define max_v 25 bool f(double A,double B,double a,double b) {     double d=sqrt(a*a+b*b);     double a1=asin(A/d);     double a2=asin(b/d)*2.0;     double h=cos(a1-a2)*d;     if(B>h)         return true;     else         return false; } int main() {     int t;     bool flag;     cin >> t;     while(t--)     {         double A,B,a,b;         cin >> A >> B >> a >> b;         if(A<B)             swap(A,B);         if(a<b)             swap(a,b);         if(A>a&&B>b)         {             flag=true;         }         else if(A*B<=a*b||b>=B)         {             flag=false;         }else         {             flag=f(A,B,a,b);         }         if(flag)         {             cout << "Escape is possible." << endl;         }else         {             cout << "Box cannot be dropped." << endl;         }     }     return 0; } INFAthon 4.0

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#include<bits/stdc++.h> using namespace std; const int MOD = 1e9 + 7; vector<vector<vector<string>>> dp; vector<string> solve(string& alice, string& bob, int i, int j) {     if(i == alice.size() || j == bob.size()) {         return {""};     }     if(dp[i][j].size() != 0) {         return dp[i][j];     }     if(alice[i] == bob[j]) {         vector<string> tmp = solve(alice, bob, i+1, j+1);         for(string& s : tmp) {             s = alice[i] + s;         }         return dp[i][j] = tmp;     }     vector<string> left = solve(alice, bob, i+1, j);     vector<string> right = solve(alice, bob, i, j+1);     if(left[0].size() > right[0].size()) {         return dp[i][j] = left;     }     if(left[0].size() < right[0].size()) {         return dp[i][j] = right;     }     left.insert(left.end(), right.begin(), right.end());     sort(left.begin(), left.end());     left.erase(unique(left.begin(), left.end()), left.end());     return dp[i][j] = left; } int main() {     int T;     cin >> T;     while(T--) {         string alice, bob;         cin >> alice >> bob;         dp = vector<vector<vector<string>>>(alice.size(), vector<vector<string>>(bob.size()));         vector<string> trips = solve(alice, bob, 0, 0);         for(string& trip : trips) {             cout << trip << endl;         }     }     return 0; }

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#include <iostream> #include <vector> #include <algorithm> using namespace std; class Solution { public:     int maxSumOptimalArrangement(vector<int>& coins) {         vector<int> positive;         vector<int> negative;         for (int coin : coins) {             if (coin >= 0)                 positive.push_back(coin);             else                 negative.push_back(coin);         }         sort(positive.rbegin(), positive.rend());                 sort(negative.begin(), negative.end());         int totalSum = 0;         for (size_t i = 0; i < max(positive.size(), negative.size()); ++i) {             if (i < positive.size())                 totalSum += positive[i];             if (i < negative.size())                 totalSum -= negative[i];         }         return totalSum;     } }; ZS campus beat code Circuit Board Telegram:- @allcoding1_official