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allcoding1_official

allcoding1_official

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📈 Analytical overview of Telegram channel allcoding1_official

Channel allcoding1_official (@allcoding1_official) in the English language segment is an active participant. Currently, the community unites 78 624 subscribers, ranking 1 628 in the Technologies & Applications category and 3 762 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 78 624 subscribers.

According to the latest data from 02 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -1 632 over the last 30 days and by -57 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 1.85%. Within the first 24 hours after publication, content typically collects 0.60% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 452 views. Within the first day, a publication typically gains 471 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
  • Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, dev.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 03 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

78 624
Subscribers
-5724 hours
-3377 days
-1 63230 days
Posts Archive
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Repost from allcoding1
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string getLongestRegex(string a, string b, string c) {   const size_t n = a.size();   int idx = -1;   for (int
+1
string getLongestRegex(string a, string b, string c) {   const size_t n = a.size();   int idx = -1;   for (int i = 0; i < n; i++) {     if (c[i] != a[i] && c[i] != b[i]) { idx = i; }   }   if (idx == -1) return "-1";   string res;   for (int i = 0; i < n; i++) {         if (i == idx) {       string cur = "[";       for (int j = 'A'; j <= 'Z'; j++)  if (j != c[i]) cur += j;       cur += "]";       res += cur;     } else {       res += "[ABCDEFGHIJKLMNOPQRSTUVWXYZ]";     }   }   return res; } C++ Amazon

def minimumCost(price): n = len(price) price.append(0) ans = float('inf') last = {price[0]: 0} for i in range(1, n): v = pric
def minimumCost(price):     n = len(price)     price.append(0)     ans = float('inf')     last = {price[0]: 0}     for i in range(1, n):         v = price[i]         price[i] += price[i - 1]         if last.get(v) != None:             ans = min(ans, price[i] - price[last[v]] + v)         last[v] = i     return ans if ans != float('inf') else -1 n = int(input()) price = list(map(int,input().split(' '))) print(minimumCost(price)) Python 3 Amazon

#include <bits/stdc++.h> using namespace std; bool checkbit(int n,int i){     return n&(1<<i); } bool cmp(const pair<int,int> &a,const pair<int,int>&b){     return a.second<b.second; } int main() {     int n;cin>>n;   int a[n];   for(int i=0;i<n;i++) cin>>a[i];   vector<pair<int,int>> v;   for(int i=0;i<n;i++){       int c=0;       for(int j=0;j<31;j++){           if(checkbit(a[i],j)) c++;       }       v.push_back({a[i],c});   }   int idx = 0;   sort(v.begin(),v.end(),cmp);   for(auto it : v){       a[idx++] = it.first;       cout<<it.second<<" ";   }   for(int i=0;i<n;i++){       cout<<a[i]<<" ";   }   return 0; } C++ Telegram:- @allcoding1_official

def cardinalitySort(nums): return sorted(nums, key=lambda num: [bin(num).count('1'), num]) Cardinality sorting
def cardinalitySort(nums):     return sorted(nums, key=lambda num: [bin(num).count('1'), num]) Cardinality sorting

Distinct digital number Python 3 JP Morgan
Distinct digital number Python 3 JP Morgan

#include <bits/stdc++.h> using namespace std; bool checkbit(int n,int i){     return n&(1<<i); } bool cmp(const pair<int,int> &a,const pair<int,int>&b){     return a.second<b.second; } int main() {   // your code goes here   int n;cin>>n;   int a[n];   for(int i=0;i<n;i++) cin>>a[i];   vector<pair<int,int>> v;   for(int i=0;i<n;i++){       int c=0;       for(int j=0;j<31;j++){           if(checkbit(a[i],j)) c++;       }       v.push_back({a[i],c});   }   int idx = 0;   sort(v.begin(),v.end(),cmp);   for(auto it : v){       a[idx++] = it.first;       cout<<it.second<<" ";   }   for(int i=0;i<n;i++){       cout<<a[i]<<" ";   }   return 0; } C++

def cardinalitySort(nums): return sorted(nums, key=lambda num: [bin(num).count('1'), num]) Cardinality sorting JP Morgan
def cardinalitySort(nums):     return sorted(nums, key=lambda num: [bin(num).count('1'), num]) Cardinality sorting JP Morgan

def gameWinner(colors):     currPlayer = "wendy"     prevPlayer = ""     winner = ""     while True:         moveMade = False         if currPlayer == "wendy":             whiteIndex = colors.find("www")             if whiteIndex = -1:                 # 3 consecutive whites found, remove the middle one                 colorsBuilder = list(colors)                 colorsBuilder.pop(whiteIndex + 1)                 colors = "".join(colorsBuilder)                 moveMade = True                 prevPlayer = currPlayer                 currPlayer = "bob"         else:             blackIndex = colors.find("bbb")             if blackIndex != -1:                 # 3 consecutive blacks found, remove the middle one                 colorsBuilder = list(colors)                 colorsBuilder.pop(blackIndex + 1)                 colors = "".join(colorsBuilder)                 moveMade = True                 prevPlayer = currPlayer                 currPlayer = "wendy"         # if no moves possible break         if not moveMade:             winner = prevPlayer             break     return winner print(gameWinner("wwwbb")) Python 3 Game Winner JP Morgan

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