allcoding1_official

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India3 495 Technologies & Applications1 498...

📈 Analytical overview of Telegram channel allcoding1_official

Channel allcoding1_official (@allcoding1_official) in the English language segment is an active participant. Currently, the community unites 84 853 subscribers, ranking 1 498 in the Technologies & Applications category and 3 495 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 84 853 subscribers.

According to the latest data from 05 July, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -1 533 over the last 30 days and by -100 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 3.06%. Within the first 24 hours after publication, content typically collects 0.93% reactions from the total number of subscribers.
Post reach: On average, each post receives 2 596 views. Within the first day, a publication typically gains 790 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 1.
Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, dev.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 06 July, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

84 853

Subscribers

-10024 hours

-3817 days

-1 53330 days

2 596

Post views

~ 79024 hours

~ 1 11648 hours

3.06%

Engagement rate

~ 1

Posts per day

Ads index

beta

Posts Archive

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Minimum Discomfort C++ language

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Longest Range C++ language Telegram:-

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n=int(input()) 4 a,c=[],o for i in range(n): I b=int(input()) a.append(b) for i in range(n-1): for j in range (i + 1, n) : if a[i] > a[j] : C+=1 a[i] , a[j] = a[j] , a[i] print(c) Telegram:-

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Python3 telegram:- @allcoding1_official

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Python3 telegram:- @allcoding1_official

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Python3

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Array AR of size N code Python3 telegram:-@allcoding1

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C++ language Beautiful number All test cases are passed Telegram:-@allcoding1

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#include<bits/stdc++.h> using namespace std; int main(){ int t; cin>>t; while(t--){ string str; cin >> str; int n = str.length(), ans = 0; for(int i = 0; i < n; i++){ if(str[i] == '5' || str[i] == '6') continue; else ans += 1; } cout << ans << endl; } return 0; } Beautiful Number Telegram:- @allcoding1_official

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Python minimum operatios required to sort A code Telegram -

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Infosys Python 3✅

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Stone bucket code Python 3 Telegram:- @allcoding1

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Python Telegram - @allcoding1

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Python 3 All test cases are pass Telegram:-

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array AR of size N perfect_sum(arr, s, result) : x = [0]*len(arr) j = len(arr) - 1 while (s > 0) : x[j] = s % 2 s = s // 2 j -= 1 sum = 0 for i in range(len(arr)) : if (x[i] == 1) : sum += arr[i] if (sum == result) : print("{",end=""); for i in range(len(arr)) : if (x[i] == 1) : print(arr[i],end= ", "); print("}, ",end="") def print_subset(arr, K) : x = pow(2, len(arr)) for i in range(1, x): perfect_sum(arr, i, K) # Driver code arr = [ ] n = int(input("Enter length of array : ")) s=int(input("Enter sum : ")) for i in range(n): ele=int(input("Enter element : ")) arr.append(ele) print_subset(arr, s) Python Telegram:- @allcoding1_

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def minOperations(arr1, arr2, i, j): # Base Case if arr1 == arr2: return 0 if i >= len(arr1) or j >= len(arr2): return 0 # If arr[i] < arr[j] if arr1[i] < arr2[j]: # Include the current element return 1 \ + minOperations(arr1, arr2, i + 1, j + 1) # Otherwise, excluding the current element return max(minOperations(arr1, arr2, i, j + 1), minOperations(arr1, arr2, i + 1, j)) # Function that counts the minimum # moves required to sort the array def minOperationsUtil(arr): brr = sorted(arr); # If both the arrays are equal if(arr == brr): # No moves required print("0") # Otherwise else: # Print minimum operations required print(minOperations(arr, brr,) Python Q) minimum operations Telegram - @allcoding1_official

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# A Naive recursive python program to find minimum of coins # to make a given change V import sys # m is size of coins array (number of different coins) def minCoins(coins, m, V): # base case if (V == 0): return 0 # Initialize result res = sys.maxsize # Try every coin that has smaller value than V for i in range(0, m): if (coins[i] <= V): sub_res = minCoins(coins, m, V-coins[i]) # Check for INT_MAX to avoid overflow and see if # result can minimized if (sub_res != sys.maxsize and sub_res + 1 < res): res = sub_res + 1 return res # Driver program to test above function coins = [9, 6, 5, 1] m = len(coins) V = 11 print("Minimum coins required is",minCoins(coins, m, V)) Python 3 Telegram:- @allcoding1_official

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