IIT JEE/MAINS MATH (CHANDRA KANT SIR)
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Channel Posts
| 2 |  3948 | 0 |
| 3 | Solution of challenging problem 1 | 0 |
| 4 | Two Challenging problems
Q1. Find sum if first 2005 terms of the series 1,2,1,2,2,1,2,2,2,1….where number of twos between two consecutive 1s is one more than previous ones
Q2. Find 150th terms of the sequence whos general term is given by [n+sqrt(2n)+0.5] where [.] represents greaters integer function | 0 |
| 5 | No text... | 0 |
| 6 | A U.K.school Olympiad question:
A mathematician, who was born in the 19th century & who died in the same century, was x years old in the year x^2. When was he born?
19th century began with 1801 & ended with 1899.
There happens to be only one square,1849 = 43^2, between 1801&1899.
So,this man was 43 in 1849. Hence he was born in 1806.
Fact check: The mathematician, Augustus De Morgan, born in 1806 in Madurai, Tamil Nadu, in British India,died in 1871 in Cambridge, England. | 0 |
| 7 | No text... | 0 |
| 8 | We are starting a series of weekly challenging problem of maths subject.. we feel that these problems will enhance the understanding of the subject. You can dm the solutions/attempt to me .. enjoy learning🤘 | 0 |
| 9 | No text... | 0 |
| 10 | Dear students and parents,
We are very happy to announce that we are starting a dropper batch from 9th June 2023(tomorrow)
Batch highlights:
1. Highly Experienced faculties
2. Well structured teaching.
3. Planned assignments
4. Rigorous testing and highly competitive environment
5. SYLLABUS COMPLETION BY DECEMBER (before first phase of jee mains)
6. Mentors of several top jee ranked students.
Interested students can contact at +91 85302 00461/462
Team Shikshagurus Academy | 0 |
| 11 | https://www.timesnownews.com/education/jee-main-2023-du-to-introduce-three-btech-programmes-this-year-admission-via-jee-mains-score-article-100769504 | 0 |
| 12 | The 13 digit number, x=ab...lm, base 10, is such that :
1)101| x, &
2) bc...g + 2019= hi...m
Find a.
Discussion:
2)implies h=b,i=c,j-d=2,k=e,l-f =1,&
m-g=9.
In mod101,10^2=-1,10^3=-10, 10^4=1, ...
Hence, x=
a-10b-c+10d+e-10f-g+10h+i-10j-k+10l+m , in mod 101
Plug in the information from 2) to get x=a-1, in mod 101.
But 101|x. Hence a=1.
" Anyone can do Mathematics. All that it needs is perseverance."
-Alonzo Church, who did seminal work in Mathematical logic. | 0 |
| 13 | Russia has a long tradition of fine Mathematics, going back to Empress Catherine.
Q) It is possible to write the integers from 1 through 16 in a line such that the sum of two successive numbers is a square. Indeed,
16, 9, 7, 2, 14, 11, 5, 4, 12,13, 3, 6,10,15, 1, 8 is one such arrangement.
Prove that the integers from 1 through 16 cannot be arranged on a circle so that the sum of two successive numbers is a square.
Discussion: We use the indirect method.
Suppose the integers from 1 through 16 are arranged on a circle such that the sum of two successive numbers is a square.
Pick 16. Let 16 be adjacent to x & y.
Now 16+ x ≥ 16+1=17, 16+y ≤ 16+15= 31 & 16+x, 16+y are both squares. However, the only square from 17 through 31 is 25.
Therefore,16+x= 25 = 16+y, a contradiction. | 0 |
| 14 | Dear students and parents,
We hope you all are healthy and doing well in your respective field/positions. Thanks for your support in last 4 months .
With your blessings , we are starting our** 2nd batch from 7th june** for which we have started admissions. Kindly spread the word and refer the students who wish to appear for jee advance/jee mains/NEET and want healthy atmosphere for learning.
Thanks and we hope that you all will keep supporting us like you have before.
Warm regards,
Team Shikshagurus Academy | 0 |
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| 17 | Very good question for jee adv 2023 aspirants.. all the best guys | 0 |
| 18 | Happy to share our first result ..Plz share among your dear and near ones.. | 0 |
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| 20 | Shikshagurus in todays Maharastra times. We are committed to deliver the best education in Pune | 0 |
