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HYDERABAD BANGLORE REAL-ESTATE ||STOCKS || INVESTMENTS || PLOTS || RENTS

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DXC Hiring Fresher For Associate Software Engineeer Location : Bangalore Qualification : Bachelor's degree or equivalent combination of education Work Experience : Fresher CTC : 4 LPA Apply Before Expired Apply Link : https://bit.ly/3xzGPkt Telegram Group Link : https://t.me/placementupdatess

Deloitte Off Campus Hiring Fresher For Analyst Location : Hyderabad Qualification : BE/B.Tech Work Experience : Fresher CTC : 6 LPA Apply Before Expired Apply Link :https://jobs2.deloitte.com/ui/en/job/E22ALLIABA-Offcampus Telegram Group Link : https://t.me/placementupdatess

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💢💢💢💢💢💢💢 ADOBE IS HIRING Eligibility: B. Tech(CS/IT/ECE/EEE) Batch: 2021 Job Location: Noida/ Bengaluru Percentage Criteria: 10th & 12th 60%, B-Tech - 70% Apply: https://cntr.click/5y6b1fM Join @placementupdatess on telegram for more useful material and off campus updates 🔥🔥🔥

CPP program to count number of visible boxes. #include <bits/stdc++.h> using namespace std;   // return the minimum number of visible boxes int minimumBox(int arr[], int n) {     queue<int> q;       // sorting the array     sort(arr, arr + n);       q.push(arr[0]);       // traversing the array     for (int i = 1; i < n; i++)  {           int now = q.front();           // checking if current element         // is greater than or equal to         // twice of front element         if (arr[i] >= 2 * now)             q.pop();           // Pushing each element of array         q.push(arr[i]);     }       return q.size(); }   // driver Program int main() {     int arr[] = { 4, 1, 2, 8 };     int n = sizeof(arr) / sizeof(arr[0]);     cout << minimumBox(arr, n) << endl;     return 0; } Telegram:- @placementupdatess Box inside a box code

def max_clique(g): n = 0 for x in g: n = max(n, len(x)) l = [set() for _ in range(n + 1)] s = [0] * len(g) for i, x in enumerate(g): ll = len(x) l[ll].add(i) s[i] = ll m = 0 for _ in range(len(g)): for i in range(n + 1): if len(l[i]) > 0: x = l[i].pop() m = max(m, i) s[x] = 0 for k in g[x]: if s[k] > 0: l[s[k]].remove(k) s[k] -= 1 l[s[k]].add(k) break return m + 1 def dfs(s, b, u): s.add(u) b[u] = True for v in g[u]: if b[v]: continue dfs(s, b, v) for _ in range(int(input())): n, m = map(int, input().split()) g = [list() for _ in range(n)] for _ in range(m): u, v = map(int, input().split()) g[u-1].append(v-1) g[v-1].append(u-1) print(max_clique(g)) Telegram:- @placementupdatess 👉the hugging distance code

Lynda has three children. She wantsgo distribute N candies among all three in such a way that exactly one childe gets the maximum number of candies among all three and each child gets at least one candy The task is to find the total number of ways distribute N candies among the three children. Code:- def countWays(N): if(N<4): return 0 ans = ((N-1) * (N-2)) // 2 s = 0 for i in range (2, N - 2,1): for j in range(1, i, 1): if(N==2*i+j): s+=1 if(N%3==0): s=3*s+1 else: s=3*s return ans-s N = int(input()) print (countWays(N)) Example 1:- Input:- 6 Output:- 9 @placementupdatess

#include <bits/stdc++.h> using namespace std; class Solution { public: int Ngarden(int n, vector<int>& ranges) { int ret = 1; vector<int> v(n + 1, -1); for (int i = 0; i <= n; i++) { int u = max(i - ranges[i], 0); int e = min(n, i + ranges[i]); v[u] = max(v[u], e); } if (v[0] == -1) return -1; int curr = v[0]; int i = 0; int next = 0; while (curr < n) { while (i <= curr) { next = max(next, v[i]); i++; } if (next == curr) return -1; curr = next; ret++; } return ret; } }; main(){ int arr; Solution ob; vector<int> v ; cout << (ob.Ngarden(arr, v)); } Gardlen question Telegram:- @placementupdatess

Today Tcs code For hiring car code

#include <bits/stdc++.h> using namespace std; int main() { long r1,n,r2,x,h,res=0; cin>>r1; cin>>n; cin>>r2; cin>>x; h=n; n=x; x=n/60; if(n%60)x++; if(h>=x) { res=x*r1; } else { res=r1*h+r2*(x-h); } cout<<res; return 0; } Telegram:- @placementupdatess

Opening for Freshers !! Company name- Manuh Solutions India Pvt Ltd Job Role: Trainee Engineer. Degree Needed: B.E/B.Tech/M.E/M.Tech -2019, 2020, 2021 pass out. 10th/12th/Degree percentage: 70% and above. Work Location(s): Bangalore. Kindly share Cv to careers@manuhsolutions.com

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