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Three persons A, B and C are standing in a queue. There are four persons between A and B and 7 persons between B and C. If there be 11 persons ahead of C and 13 persons behind A, what could be the minimum number of persons in the queue?
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X and Y run a 3 km race along a circular course of length 300 m. Their speeds. are in the ratio 3:2. If they start together in the same direction, how many times, would the first one pass the other (the start-off is not counted as passing)?
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Hi Anand,
Don't be disheartened..
Add your number in above message..il forward in our spoorthy group, some of them cleared prelims.
Solution:
a / b minimum possible remainder is zero. (When b divides a exactly)
Maximum possible remainder is, = b – 1
Difference is = (b – 1) – 0 = b – 1
