UPSC CSAT Notes 2024
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Sir, It can also be Solved through Permutations when repetitions not allowed ( ^7P3 ) = 210
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For a no. To be smallest two smallest no. Should be multipled so bc multiplication will give smallest result
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What is the smallest number greater than 1000 that when divided by any one of the numbers 6, 9, 12, 15, 18 leaves a remainder of 3?
