PythonBoost - сообщество питонистов
Лучший Python телеграм канал для новичков. Цель: подготовка студентов, начинающих питонистов к нахождению первой работы. @anothertechrock РКН: https://kurl.ru/Jhcwp
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Network:📈 Analytical overview of Telegram channel PythonBoost - сообщество питонистов
Channel PythonBoost - сообщество питонистов (@pythonboost) in the Russian language segment is an active participant. Currently, the community unites 10 848 subscribers, ranking 11 009 in the Technologies & Applications category and 58 800 in the Russia region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 10 848 subscribers.
According to the latest data from 29 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -70 over the last 30 days and by -2 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 8.14%. Within the first 24 hours after publication, content typically collects 3.34% reactions from the total number of subscribers.
- Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 362 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
- Thematic interests: Content is focused on key topics such as true, docker, собеседование, кортеж, параметр.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“Лучший Python телеграм канал для новичков.
Цель: подготовка студентов, начинающих питонистов к нахождению первой работы.
@anothertechrock
РКН: https://kurl.ru/Jhcwp”
Thanks to the high frequency of updates (latest data received on 30 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
def find_odd(lst):
for num in lst:
if lst.count(num) % 2:
return num
Еще 3 других решения есть у нас на сайте по ссылке: https://pythonturbo.ru/zadacha-najti-nechetnoe-czeloe-chislo/find_odd([1, 1, 2, -2, 5, 2, 4, 4, -1, -2, 5]) ➞ -1
find_odd([20, 1, 1, 2, 2, 3, 3, 5, 5, 4, 20, 4, 5]) ➞ 5
find_odd([10]) ➞ 10
Пишите ваши варианты в комментариях под постом.
Решение скоро.
