Alok Kumar - JEE/OLY
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sub x = sec@
solving u get sec@ - cosec@ = 91/60. put m,n -> sec, cosec. you have two equations , m-n = 91/60 and 1/m^2 + 1/n^2 =1 => m^2+n^2 = m^2n^2. square the first and substitute m^2+n^2 in terms of mn into second to get (mn)^2 -2mn - (91/60)^2 = 0 to get mn = 169/60 , -49/60 , where second value is rejected as its abs <1. so you have m * (-n) = -169/60 and m + (-n) = 91/60. solve this quadratic as sigma1 and sigma2 is given to get m = 13/5 or - 13/12
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The Indian team for 15th IOAA being held at Kutaisi, Georgia departed today (ioaa2022.ge). The team consists of 5 students and 4 mentors. We wish the team the best wishes.
L to R: Prof. Sarita Vig, Mr. Tejas Shah, Mr. Raghav Goyal, Mr. Malay Kedia, Mr. Md Sahil Akhtar, Mr. Mehul Borad, Mr. Atharva Mahajan, Dr. Shriharsh Tendulkar, Prof. Ajit Mohan Srivastava.
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12/7/22 #POTD 26
Here is a simple and straightforward problem if you have the right mindset!
Definitely one the easier side of JEE ADV!
Solve and Share your Solutions!
Share among max students 🔥🔥🔥
