Algebra Quint
Open in Telegram
If you have any Query (Maths and Reasoning) then you can directly contact to @JituRider1554 #algebra , #trigonometry, #numbersystem Our team will provide your solution as soon as possible .👍 Join 🔜 https://t.me/Mathquizonly
Show more1 549
Subscribers
No data24 hours
-17 days
-1130 days
Posts Archive
1 549
n²x² + 1/x² = n
n(nx² + 1/nx²) = n
(nx² + 1/nx²) = 1
So
(nx²)³ = - 1
n³x⁶ = - 1
n³x³ = - 1/x³
(nx)³ = - 1/x³
1/(nx)³ = - x³
Now
x³ + 1/(nx)³
x³ - x³
0
1 549
2ˣ - 2ʸ = 31/6
2²ˣ - 2²ʸ = 341/12
(2ˣ)² - (2ʸ)² = 341/12
(2ˣ + 2ʸ)×(2ˣ - 2ʸ) = 341/12
(2ˣ + 2ʸ)×31/6 = 341/12
(2ˣ + 2ʸ) = 11/2..............(1)
(2ˣ - 2ʸ) = 31/6..............(2)
Eqn (1)÷(2)
°°°°°°°°°°°°°
(2ˣ + 2ʸ)/(2ˣ - 2ʸ) = 33/31
2ˣ/2ʸ==64/2
2^(x-y)=32=2⁵
(x-y)==5✅
1 549
A+B+C = π
So
tan(A+B+C) = tan π = 0
So
tan A + tan B + tan C = tan A tan B tan C
Now
(tan A + tan B + tan C)/3 ≥ (tan A tan B tan C)^1/3
(tan A + tan B + tan C)³/27 ≥ (tan A tan B tan C)
(tan A + tan B + tan C)³/27 ≥ (tan A + tan B + tan C)
(tan A + tan B + tan C)²/27 ≥ 1
(tan A + tan B + tan C)² ≥ 27
(tan A + tan B + tan C) ≥ √27
(tan A + tan B + tan C) ≥ 3√3
