بايثون العربي | Python Arabe 🇵🇸
قناة عربية لتعلّم Python من الصفر بأسلوب مبسّط وعملي مع أمثلة وتمارين ومشاريع تساعدك تبني مهاراتك البرمجية خطوة بخطوة.
Show more📈 Analytical overview of Telegram channel بايثون العربي | Python Arabe 🇵🇸
Channel بايثون العربي | Python Arabe 🇵🇸 (@pythonarabe) in the Arabic language segment is an active participant. Currently, the community unites 12 270 subscribers, ranking 9 913 in the Technologies & Applications category and 6 138 in the Saudi Arabia region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 12 270 subscribers.
According to the latest data from 29 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -168 over the last 30 days and by -2 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 3.66%. Within the first 24 hours after publication, content typically collects 1.20% reactions from the total number of subscribers.
- Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 147 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
- Thematic interests: Content is focused on key topics such as ذَات, قَنَاة, إِنتِرنِت, بُرمُجَة, تَجمِيعَة.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“قناة عربية لتعلّم Python من الصفر بأسلوب مبسّط وعملي مع أمثلة وتمارين ومشاريع تساعدك تبني مهاراتك البرمجية خطوة بخطوة.”
Thanks to the high frequency of updates (latest data received on 30 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
plus = 3
old1 = 15
old2 = round(old1 / 2) - plus + 1
old1 += plus
old2 += plus
if round(old1/2) == old2:
print('old =', old1)
صاحب الحل : @V1_2S
A, B= 3, 15;C = round(A/2)+B+1;print(f"AGE => {C}")